Answer:
2 m/s2
Explanation:
|acceleration| = (change in speed) divided by (time for the change)
Change in speed = (end speed) minus (start speed)
Initial speed of walking = 1 m/s
Final speed of walking = 3 m/s
Change of speed in walking = (3 - 1) m/s
= 2 m/s
Time in which the change of speed occurred = 1 sec
Then
Acceleration = Change of Speed/ Time taken
= 2/1 m/s^2
= 2 m/s^2
Therefore the answer is 2 m/s2.
The acceleration is 2 m/s².
What is acceleration?Acceleration can be defined as the rate of change of velocity.
The acceleration can be calculated using the formula below.
Formula:
a = (v-u)/t................... Equation 1Where:
a = accelerationv = Final velocityu = Initial velocityt = time.From the question,
Given:
v = 3 m/su = 1 m/st = 1 secondsSubstitute these values into equation 1
a = (3-1)/1a = 2 m/s².Hence, The acceleration is 2 m/s².
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The maximum allowable potential difference across a 250 mH inductor is 360 V . You need to raise the current through the inductor from 1.5 A to 2.5 A . What is the minimum time you should allow for changing the current?
This question involves the concepts of potential difference, inductance, and current.
The minimum time that should be allowed for the current to change is "0.694 ms".
The inductance of an inductor is given by the following formula:
[tex]E=L\frac{\Delta I}{\Delta t}\\[/tex]
where,
E = potential difference across the inductor = 360 volts
L = inductance of the inductor = 250 mH = 0.25 H
ΔI = change in current = 2.5 A - 1.5 A = 1 A
Δt = time required = ?
Therefore,
[tex]\Delta t = \frac{(0.25\ H)(1\ A)}{360\ volts}[/tex]
Δt = 6.94 x 10⁻⁴ s = 0.694 ms
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help with this question
Answer:
D and B.
Explanation:
The wavelength must be taken from the same corresponding point. D and B are both at the crests of a wave, with no other crests in between, which means the distance between them is equal to one wavelength.
When making a left turn, drive into the intersection, make the turn smoothly and without strain on the engine, braking to about ... to .........mph and stay on the brake until approximately half way into the intersection.
Answer:
whats the question
Explanation:
Noah runs 200 m to the east and then 400 m north. What is Noah's distance and displacement?
Answer:
Noah has run 600 metres north east
What is the approximate value of log⁵³ 217895.4
Answer:
3.09594
Explanation:
hope this helps
To minimize signal distortion, at each end of the J-1939 CAN-bus there is a(n)_____________resistor.
A bowling ball and a ping-pong ball are each tied to a string and hung from the ceiling. The distance from the ceiling to the CM of each object is the same. Which object would have a longer period of motion if they were set swinging
what is the average power supplied by a 60.0 kg person running up a flight of stairs a vertical distance of 4.0 in 4.2s
Hi there!
We know that:
[tex]P = \frac{W}{t}\\\\[/tex]
Where:
W = Work done (J)
t = time (s)
We can calculate the work using the equation:
[tex]W = \Delta U = mg\Delta h[/tex]
Plug in the given values:
[tex]W = 60(9.8)(4) = 2352J[/tex]
Now, divide by time:
[tex]P = \frac{W}{t} = \frac{2352}{4.2} = \boxed{560W \text{ (Watts)}}[/tex]
60W light bulb is left on for 5mins. How much energy does it use in KWH
Answer:
Energy = Power × Time
time must be hoursPower must be in kilowatts[tex]{ \tt{E = ( \frac{60}{1000} ) \times ( \frac{5}{60}) }} \\ \\ { \tt{E = 0.005 \: kwh {}^{ } }}[/tex]
difference between 1 hectoliter and one kiloliter
Answer: 100 and 1000
Explanation:
A ball is dropped from a 20.0 m high tower.
a. How long will it take the ball to reach the ground?
b. What is the velocity of the ball just before it hits the ground?
Hi there!
We can begin by using the derived kinematic equation:
[tex]t = \sqrt{\frac{2h}{g}[/tex]
Plug in the given values and let g = 9.8 m/s²:
[tex]t = \sqrt{\frac{2(20)}{g}} = \boxed{2.02 s}[/tex]
Now, we can solve for its final velocity using the equation:
[tex]v_f = v_i + at[/tex]
It is dropped from rest, so vi = 0 m/s.
[tex]v_f = at[/tex]
[tex]v_f = 9.8(2.02) = \boxed{19.796 m/s}[/tex]
Answer:
a. The ball would reach the ground in approximately [tex]2.02\; \rm s[/tex].
b. The velocity of the ball right before landing would be approximately [tex]19.8\; \rm m\cdot s^{-1}[/tex].
(Assumptions: the ball was dropped with no initial velocity; air resistance on the ball is negligible; [tex]g = 9.81\; \rm m\cdot s^{-2}[/tex].)
Explanation:
Under these assumptions, the acceleration of this ball would be constantly [tex]a = g = 9.81\; \rm m\cdot s^{-2}[/tex] (same as the gravitational field strength) during the descent.
Displacement of the ball: [tex]x = 20.0\; \rm m[/tex].
Initial velocity of the ball: [tex]v_{0} = 0\; \rm m\cdot s^{-1}[/tex].
Let [tex]t[/tex] denote the duration of this descent.
The SUVAT equation [tex]x = (1/2)\, a\, t^{2} + v_{0}\, t[/tex] relates the known quantities [tex]a[/tex], [tex]x[/tex], and [tex]v_{0}[/tex] to the unknown [tex]t[/tex].
Substitute the known quantities into this equation and solve to find the value of [tex]t\![/tex]:
[tex]\displaystyle 20.0\; {\rm m} = \frac{1}{2}\times 9.81\; {\rm m\cdot s^{-2}} \times t^{2} + 0\; {\rm m \cdot s^{-1}} \times t[/tex].
[tex]\displaystyle 20.0\; {\rm m} = \frac{1}{2}\times 9.81\; {\rm m\cdot s^{-2}} \times t^{2}[/tex].
[tex]\displaystyle t^{2} = \frac{20.0\; \rm m}{(1/2) \times 9.81\; \rm m\cdot s^{-2}}[/tex].
Since [tex]t > 0[/tex]:
[tex]\begin{aligned}t &= \sqrt{\frac{20.0\; \rm m}{(1/2) \times 9.81\; \rm m\cdot s^{-2}}} \\ &\approx 2.01928\; \rm s\\ &\approx 2.02\; \rm s \\ & (\text{Rounded to 2 sig. fig.})\end{aligned}[/tex].
Since the acceleration of this ball is constant, the velocity of the ball right before landing would be:
[tex]\begin{aligned}v_{1} &= a\, t \\ &\approx 9.81\; \rm m\cdot s^{-2} \times 2.01928\; \rm s \\ &\approx 19.8\; \rm m \cdot s^{-1} \end{aligned}[/tex].
What is the correct definition of rarefaction
Answer:
Explanation:
A decrease in the density of something is rarefaction. ... Most of the time, rarefaction refers to air or other gases becoming less dense. When rarefaction occurs, the particles in a gas become more spread out. You may come across this word in the context of sound waves.
2. A bowling ball is dropped off a 300 meter high bridge. A water bottle is dropped from
the same position 3 seconds later. How high above the ground is the water bottle, when the
bowling ball has a speed of 64 m/s? *
(2 Points)
A bowling ball is dropped off a 300 meter high bridge. A water bottle is dropped from the same position 3 seconds later. the ground is the water bottle, when the bowling ball has a speed of 64 m/s is zero.
what is speed ?Speed is measured as the ratio of distance to the time in which the distance was covered. Speed is a scalar quantity as it has only direction and no magnitude.
The formula of speed is represented as s=d/t, Where, s is the speed in m.s-1, d is the distance traveled in m, t is the time taken in s
There are four types of speed such as Uniform speed, Variable speed, Average speed, Instantaneous speed
Uniform speed is an uniform speed when the object covers equal distance at equal time intervals, variable speed is defined as when the object covers a different distance at equal intervals of times.
Average speed is defined as the uniform speed the ratio of total distance travelled by an object to the total time taken by the object.
Instantaneous speed is defined as an object is moving with variable speed, then the speed at any instant of time is known as instantaneous speed.
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Two cars A and B are moving along a straight road in the OPPOSITE direction with velocities of 25 km/h and 40 km/h, respectively. Find the velocity of car B relative to car
Answer:
65km/h
Explanation:
Here,
Relative velocity of car moving in different directions with different velocities =Va + Vb
=25+40
=65 km/h
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
How do you solve problems involving acceleration
Answer:
Velocity/time =acceleration
Acceleration x time = velocity
Velocity/acceleration=time
What torque will increase angular velocity of a solid cylinder of mass 16 kg and diameter 1 m from zero to 120 rpm in 8 s?
a)π/4Nm
b)π/2Nm
c)π/3Nm
d)πNm
Which will be different on the moon than it is on Earth?
weight
mass
Answer:
Below
Explanation:
On the moon, an objects weight will be different than it is on earth. This is because we cannot change the mass of an object, the mass of an object is the measure of matter an object has. However the weight is depended on the gravitational pull of whatever planet you are on. In this case, weight will be lighter on the moon than it is on earth because the moon's gravitational pull is 1.62 m/s^2 while earths is around 9.8 m/s^2.
Hope that helps!
What average force magnitude is required to stop a 15,000 kg train in 12.1 s if the train is traveling at 86 km/hr
Answer:
Explanation:
Givens
m = 15000 kg
t = 12.1 seconds
vi = 86 km / hr
vf =0
Formula
F = m*a
a = (vf - vi)/ t
vi has to be converted to m/s
86 km/hr [1000 m / 1 km] * [1 hour / 3600 seconds]
86 * 1000 / 3600 = 23.89 m/s
Solution
a = (vf - vi) / t
a = (0 - 23.89)/12.1
a = - 1.97 m/s^2 The minus means that the trains is slowing down.
F = 15000 kg * - 1.97 m/s^2
F = -29615.7 Newtons.
which acts as a transverse wave with particle motion perpendicular to wave motion?
Answer:
transverse wave, motion in which all points on a wave oscillate along paths at right angles to the direction of the wave's advance. Surface ripples on water, seismic S (secondary) waves, and electromagnetic (e.g., radio and light) waves are examples of transverse waves.
The weight of a 1,000 kg car is ______________ (pick best answer)
Group of answer choices
9800 N
102.4 N
1000 N
10000 N
What is the weight of a car with the mass of 1000 kg?
Answer: it is 9800 N.
A car goes from 60 m/s to 75 m/s in 10 seconds.calculate the car’s acceleration?
Explanation:
Uhhhh here is an example
a=vt. =27 m/s10 s. =2.7 m/s2.
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
Acceleration of the car is ~
[tex] \boxed{1.5 \: \: m/s}[/tex]
[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]
We know that,
Acceleration = rate of change in velocity ~
that is ~
[tex]a = \dfrac{v - u}{t} [/tex]where,
v = final velocityu = initial velocity t = time taken ~now, let's solve ~
[tex]a = \dfrac{75 - 60}{10} [/tex][tex]a = \dfrac{15}{10} [/tex][tex]a = 1.5 \: \: m/s[/tex]LED lightbulbs are the most energy efficient way to light your home, as they use _____ of the energy of a comparable compact fluorescent bulb.
Light - emitting diode lightbulbs known as LED lightbulbs are energy saving lightbulbs. They consume very small amount of energy compare to other lightbulbs. Therefore, LED lightbulbs are the most energy efficient way to light your home, as they use about ten percent (10%) of the energy of a comparable compact fluorescent bulb.
There are varieties of different light bulbs. some of them are incandescent, compact fluorescent (CFL), halogen, and light-emitting diode (LED) to mention a few.
Before the advent of light - emitting diode (LED) bulbs, some of the bulbs consume a lot of energy. For instance, we have incandescent bulbs of 20 watts, 50 watts, 100 watts and even 200 watts.
But with the advent of light - emitting diode (LED) bulbs, consumers can save energy because light - emitting diode (LED) bulbs save a lot of energy and they are very bright.
We can therefore conclude that light - emitting diode lightbulbs known as LED lightbulbs are the most energy efficient way to light your home, as they use about ten percent (10%) of the energy of a comparable compact fluorescent bulb.
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where does most star formation occur in the milky way galaxy?
Answer:
Star formation occurs most rapidly in the spiral arms, where the density of interstellar matter is highest.
test questions!!!!!!!!
Answer:
B. surface wave
a person with a mass of 15 kg is walking downhill at a velocity of 10 ms what is the Walkers momentum
Answer:
[tex]150 kg\cdot m/s[/tex]
Explanation:
Same as if he was walking uphill, or horizontally. Momentum is defined as the product of mass times velocity. [tex]p = mv = 15\cdot 10 = 150 kg\cdot m/s[/tex]
Is a football tackle an elastic or inelastic collision and why?
A: elastic, because momentum is conserved
B: inelastic, because kinetic energy is conserved
C: inelastic, because momentum is not conserved
D: inelastic, because kinetic energy is not conserved
If the kinetic energy of an object changes, then the collision is considered inelastic. This is regardless of whether the objects sticks together or not.
My best answer for this question would be D) inelastic, because kinetic energy is not conserved.
We can tell from the collision that it is not elastic.
Momentum is is conserved, it transfers to the other player.
Kinetic energy is not conserved, at it turns into internal friction.
I hope this helps! :)
A football tackle is an inelastic collision , because kinetic energy is not conserved.
What is collision?When two bodies or particles move towards enough to interact with each other it is called the particles or the bodies are colliding.
What are the types of collision?Elastic collisioninelastic collisionWhat is an elastic collision?In this type of collision , there is no loss of kinetic energy.The momentum and kinetic energy both are conserved.What is an inelastic collision?in this type of collision , there is a loss of kinetic energy.The momentum of the system is conserved but the kinetic energy is not conserved .So, when the football tackles it's kinetic energy changes.
Thus, A football tackle is an inelastic collision , because kinetic energy is not conserved.
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What is the acceleration of a 20 kg backpack lifted with a force of 15 N?
a. 0.75 m/s2
b. 1.33 m/s2
c. 300 m/s2
d. 5 m/s2
The answer is option A. 0.75 m/s^2
the formula needed to solve this is acceleration = force/mass
we know the following:
mass of the backpack = 20KG
the force is 15N
therefor- acceleration = 15/20
which can also be written as 3/4, leaving us with the final answer of .75 m/s^2
Answer:
0.75 m/s2
Explanation:
0.75 m/s2
Suppose measure the mass of an orange. Then you peel the orange and separate out the slices. If you measure the orange peel and all the slices, will that mass equal the mass of the whole orange?
yes
no
The mass of the orange after it has been cut into pieces will still remain the same as the mass of the whole orange.
Let us recall that the law of conservation of mass states that, mass can neither be created nor destroyed but is converted from one form to another. In accordance with this law of conservation of mass. The mass of the orange must remain the same after it has been cut in pieces.
Hence, If the mass of an orange is measured after it has been cut into pieces, the mass of the orange after it has been cut into pieces will still remain the same as the mass of the whole orange.
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Two illustrations labeled A and B. In Illustration A a hand is pushing on a mass labeled m that is connected to a spring and the spring is connected to a wall. In illustration B the spring is back to its normal length and the mass is moving away from the end of the spring at a velocity v. The position where the block started from is labeled x = 0. A spring attached to a mass is at rest in the initial position (not shown). The spring is compressed in position A and is then released, as shown in position B. Which equation describes conservation of energy in position A?
Answer:
The answer is (C) E= 1/2 kx^2
Explanation:
Answer:
ITS C JUST FINISH
Explanation:
if 20 boys can sweep the school compound in 8 minutes, how many boys can sweep it in 10minutes
Answer:
So this is just a ratio/proportion problem
so lets say its in boys:minutes
so in the first scenario
20:8
and we want to find
x:10
So proportion really
20/8=x/10
cross multiply
25
25 boys can sweep it in 10 minutes