Chemistry High School

what mass of oxygen would form from 5 moles of water?

Answers

Answer 1

Answer:

Explanation: The equation of water is H2+1/2O2=H2O

->5 moles H2O*1 mol O2/2 mole

-> H2O=2.5 moles O2

->Now, molar mass of O2= 2*16=32gms

To find mass of O2,

-> No. of moles*Molar mass of O2

->2.5*32=0 gms

So, the mass of oxygen will be 80 gms.

Related Questions

which of the following is a characteristic of fractional distillation? select all that apply: components with higher boiling points tend to rise to the top of the distillation apparatus. repeated vaporization and condensation are part of the fractional distillation process. fractional distillation is useful for the separation of liquids with boiling points that are close together. the apparatus used for fractional distillation is often a multi-level insulated column.

Answers

The components with higher boiling point will be at the bottom during fractional distillation. So, all of the following statement follows except option (A).

Fractional distillation process is defined as the process of separation of a mixture into its component parts or into the fractions. Chemical compounds are separated by heating them to a temperature after which one or more fractions of the mixture will vaporize from their component. This process uses distillation to fractionate. It is a process by which components in a chemical mixture are separated into different parts according to their different boiling points. This distillation process is used to purify chemicals and to separate mixtures to obtain their components. This involves repeated vaporization and condensation are part of the fractional distillation process.

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The complete question is,

which of the following is a characteristic of fractional distillation? select all that apply:

A. components with higher boiling points tend to rise to the top of the distillation apparatus.

B. repeated vaporization and condensation are part of the fractional distillation process.

C. fractional distillation is useful for the separation of liquids with boiling points that are close together.

D. the apparatus used for fractional distillation is often a multi-level insulated column.

at what ph must the solution in the lead-acid battery be to produce its standard cell potential of 2.05 v?

Answers

At ph = 0 must the solution in the lead-acid battery be to produce its standard cell potential of 2.05 v.

Pb + PbO₂ + 2H₂SO₄ ⇄ 2PbSO₄ + 2H₂O

At anode: Pb + SO²⁻₄ → PbSO₄ + 2e⁻

E = 0.356 V

At Cathode: PbO₂ + H₂SO₄ +2H⁺ + 2e⁻→ PbSO₄ +2H₂O

E = 1.690 V

Overall:

Pb + PbO₂ + 2H₂SO₄ ⇄ 2PbSO₄ + 2H₂O

E =2.05 at standard concentration = 1 M

ph = log[1]

ph= 0

The cell potential is the voltage of a single electrochemical cell, to put it simply. To boost the voltage of the battery, many cells may be packaged in series. A completely charged lead-acid battery will always have a cell potential of about 2.1 V, regardless of the battery's size since cell potential is a property of a specific chemical reaction. Similar to this, depending on the cathode material, lithium-ion batteries have nominal cell potentials between 3.2 and 3.85 V.

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what is the probability of finding a hydrogen 1s electron within the so called van der waals radius of hydrogen

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The probability of finding a hydrogen 1s electron within the so-called van der Waals radius of hydrogen is 90%.

Van der Waals radius (vdW) is an estimate of the size of an atom. It is the radius of a sphere encompassing the outermost orbital of an atom (such as van der Waals radii).The probability of locating an electron in a particular area is referred to as probability density. The probability density of an electron in the hydrogen atom in its ground state is greatest at the center of the atom and decreases exponentially as the distance from the nucleus increases.The probability of finding a hydrogen 1s electron within the so-called van der Waals radius of hydrogen is approximately 90%.

The radius of the hydrogen atom is 53 pm, and the van der Waals radius of the hydrogen atom is 120 pm, respectively. As a result, there is a higher likelihood of locating a hydrogen 1s electron within the van der Waals radius of hydrogen than outside of it, which is roughly 90%.

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