Answer:
5000 JExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass in kg
v is the velocity of the object in m/s
From the question
m = 100 kg
v = 10 m/s
We have
[tex]k = \frac{1}{2} \times 100 \times {10}^{2} \\ = 50 \times 100 \\ = 5000 \: \: \: \: \: \: \: \: [/tex]
We have the final answer as
5000 JHope this helps you
2H20 1) How many hydrogen atoms are represented by this much water? A) 1 B) 2 )4 D) 6
What is the potential energy of a 2 kg bowling ball resting at the top of a 5 m high hill? Show all of your work and include the correct units to receive full credit.
Answer:
[tex]\boxed {\boxed {\sf 98 \ J}}[/tex]
Explanation:
We are asked to find the potential energy of a bowling ball.
Potential energy is the energy an object possesses due to its position. It is calculated using the following formula.
[tex]E_p= mgh[/tex]
In this formula, m is the mass, g is the acceleration due to gravity, and h is the height.
The bowling ball has a mass of 2 kilograms. The hill is 5 meters high. Assuming this situation is occurring on Earth, the acceleration due to gravity is 9.8 meters per second squared.
m= 2 kg g= 9.8 m/s²h= 5 mSubstitute the values into the formula.
[tex]E_p= (2 \ kg )(9.8 \ m/s^2)(5 \ m)[/tex]
Multiply the numbers together.
[tex]E_p=19.6 \ kg*m/s^2(5 \ m)[/tex]
[tex]E_p=98 \ kg*m^2/s^2[/tex]
Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule. Our answer of 98 kg*m²/s² is equal to 98 Joules.
[tex]E_p= 98 \ J[/tex]
The bowling ball has 98 Joules of potential energy.
A tennis ball thrown with a velocity of 25m/s[Fwd] in the horizontal direction from the top of an 80m high building.
1. How long does it take the tennis ball to reach the ground?
2. How far is the range (how far from the base of the building will the ball land) ?
3. What is the final velocity?
Even answering one will help me out and i will give brainlest!
Answer:
Explanation:
Ignoring air resistance
1) from vertical rest
s = ½at²
t = √(2s/a)
t = √(2(80)/9.8)
t = 4.040610...
t = 4.0 s
2) d = vt
d = 25(4.0)
d = 100 m
3) v² = u² + 2as
v² = 25² + 2(9.8)(80)
v² = 2193
v = 46.8294...
v = 47 m/s
θ = - 90 + arcsin(25/46.8294)
θ = -57.7339...
θ = 58° below the horizontal
People wear special snowshoes when there is a snowfall in the cold countries. Why?
Answer:
The fundamental function of snowshoes is to offer float, allowing you to avoid sinking into snow. Hikers who do not have snowshoes may find themselves knee- or waist-deep in unconsolidated snow if they attempt to traverse it without snowshoes, a practice known as post-holing.
Explanation:
Answer:
Explanation:
I live in a cold country and I own snow shoes. I have to confess I've never thought about this question before.
If the snow is fresh, it is also very loosely packed. If you wear ordinary shoes, the first thing that will happen is that you will sink. How far depends on how deep the snow is. I can see you up to your waist in snow, if the snowfall is heavy enough.
So to prevent that, my snowshoes are 3 feet long and about 1 foot wide, Except for a small hole near the middle, the entire area is covered. I weigh about 140 pounds.
A very small calculation should tell you that if I wear house shoes (mine are 8" long by about 3 inches wide). The pressure is going to be 140 pounds / (2/3 * 1/4) = 140 // 2/12 = 140 / 1/6 = 140 * 6 = 840 pounds / square foot. Trust me, that is a lot of pressure.
What do the snowshoes accomplish?
140 / (3*1) = 46.7 pounds per square foot. You might sink a little, but you are not going down as far as you would with street clothes shoes.
The units are not the normal units you would use, but the ratio is going to be roughly the same. 840 / 46.
All of this is very approximate. That's what physics is all about. Approximations lead you to understanding.
what is the full meaning of hip
Answer:
History in Perspective (education) HIP. Health Information Professional. HIP.
Explanation:
hope this helps
URGENT NEED GIVING POINTS question is how do i find R and the angle THANK YOU
Answer:
Theta = 26.93°
R = 0.38m
Explanation:
Theta = cos^-1(0.74m/0.83m)
Theta = 26.93°
R = sqrt(0.83²-0.74²)
R = 0.38m
the small lightweight particles outside the nucleus of an atom are called___.
The neutron has no charge, and a mass of slightly over 1 amu. Some scientists propose the neutron is made up of a proton and electron-like particle. The electron is a very small particle located outside the nucleus.
Electron: -1
Neutron: 0
Proton: +1
In which of the cases below is friction most helpful?
A.
between a moving box and a ramp
B.
between car tires and a road
C.
between a person and a playground slide
D.
between ice skates and an ice rink
Answer:
between car tires and a road
Explanation:
A wave moving with a speed of 0.5 m/s has a frequency of 50 Hz. What is the
wavelength of the wave?
A. 0.10 m
B. 0.01 m
C. 100 m
D, 25 m
Answer:
0.01 mExplanation:
The wavelength of the wave given it's velocity and frequency can be found by using the formula
[tex] \lambda = \frac{c}{f} \\[/tex]
where
c is the speed of the wave
f is the frequency
From the question we have
[tex] \lambda = \frac{0.5}{50} = 0.01 \\ [/tex]
We have the final answer as
0.01 mHope this helps you
A small ball is attached to one end of a spring that has an unstrained length of 0.201 m. The spring is held by the other end, and the ball is whirled around in a horizontal circle at a speed of 3.41 m/s. The spring remains nearly parallel to the ground during the motion and is observed to stretch by 0.0176 m.
Required:
By how much would the spring stretch if it were attached to the ceiling and the ball allowed to hang straight down, motionless?
The extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.
The given parameters;
unstrained length, l₁ = 0.201 mextension of the string, x = 0.0176 mspeed of the ball, v = 3.41 m/sThe radius of the circular path when spring is stretched is calculated as;
R = l₁ + x
R = 0.201 + 0.0176
R = 0.2186 m
The spring constant is calculated as follows;
[tex]F = ma\\\\Kx = \frac{mv^2}{R} \\\\K = \frac{mv^2}{Rx} \\\\K = \frac{(3.41)^2 m}{0.2186 \times 0.0176} \\\\K = 3,022.4 m \ N/m[/tex]
The extension of the spring when the ball is allowed to hang straight down, motionless;
[tex]F = mg\\\\Kx=mg\\\\x = \frac{mg}{K} \\\\x = \frac{9.8 m}{3022.4 m} \\\\x = 0.0032 \ m[/tex]
Thus, the extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.
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how can the motion of an object that is already moving change?
Answer: A force can change the direction in which an object is moving
Explanation: A bigger force of an object will produce a bigger change in motion
A piece of wood has a mass of 8g and a volume of 10cm³. Work out the density of the wood in /3 .
no links please just explain how you got the answer.
Answer:
8×10^-3÷10×10^-6=8×10^2=800 kg/m^3
Answer:
2.4/3
Explanation:
first we make 8g/10cm then 0.8 so the only number that can fit for /3 is 2.4
hope helped!
Two cars a and b are moving along a straight road in the same direction with velocities of 25km/h and 40km/h . Find the velocity of car b relative to car a
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
A block of wood mass 0.60 kg is balanced on top of a vertical port 2.0 m high. A 10 gm
bullet is fired horizontally into the block and the embedded bullet land at a 4.0 m from
the base of the port. Find the initial velocity of the bullet.
A. 10 3 m/s B. 8.32 m/s C. 3.82 m/s D. 1.0 m/s
Answer:
m V1 = (m + M) V2 conservation of momentum
T = time to fall 2 m
2 = 9.8 / 2 T^2 initial vertical velocity zero
T^2 = 4/9.8 T = .639 sec
Sx = V2 * .639 sec distance traveled horizontally
V2 = 4 /.639 = 6.26 m/sec
V1 = (m + M) / m * 6.26 m/sec from first equation
V1 = (600 + 10) / 10 * 6.26 m/s = 382 m/s
There seems to be some confusion on units
Note that 382 m/s is a reasonable answer for speed of bullet
1100 ft/sec is reasonable for a .22 cal bullet
1100 ft/sec / 3.28 ft/m = 335 m/sec
If F = 4.0 N and m = 2.0 kg, what is the magnitude a of the acceleration for the block shown below? The surface is frictionless. *
The magnitude of the acceleration of the block is 3.5 [tex]\bold{m/s^2.}[/tex]
The correct option is (C) 3.5 [tex]\bold{m/s^2.}[/tex]
What do you mean by acceleration?Acceleration is the rate of change of velocity with time.
By Newton’s Second law
This law establishes the relationship between the net applied force on an object with the resultant acceleration. For a constant magnitude of force, the more is the mass of the object, the lesser will be its acceleration.
Given,
The mass of the block is 2.0 kg.
The force in the horizontal direction on the block is [tex]\bold{4.0 N + 4.0 N \cos 40{}^\circ.}[/tex]
a is the acceleration in the horizontal direction.
The acceleration for the block can be determined using Newton’s Second law,
[tex]\begin{aligned} \Sigma F&=ma \\ F+F\cos 40{}^\circ &=ma \\ a&=\frac{F\left( 1+\cos 40{}^\circ \right)}{m} \\ &=\frac{4.0\text{ N}\left( 1.766 \right)}{2.0\text{ kg}} \\ &=3.5\text{ m/}{{\text{s}}^{2}} \end{aligned}[/tex]
Thus, the acceleration is 3.5 [tex]\bold{m/s^2.}[/tex]
Learn more about acceleration, here:
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a person walks 9 meters to the right and 8 meters to the left what's the distance and displacement
Answer:
walked: 17 meters
displacement: 1
Explanation:
so you add 9+8 and the displacement is 1 b/c when you moved back those 8 meters you were still 1 meter away from where you where originally standing
PLEASE ANSWER ASAP
A 5 kg bowling ball traveling at 2 m/s hits a motionless 10 kg bowling ball. If the smaller ball bounces back at a speed of -1 m/s, what will be the speed of the larger ball after the collision?
Hi there!
Recall the conservation of momentum:
m1v1 + m2v2 = m1v1' + m2v2'
Let m1 = 5 kg ball and m2 = 10 kg ball
Since m2 is at rest, we can rewrite:
m1v1 = m1v1' + m2v2'
Plug in the given values:
5(2) = 5(-1) + 10v2'
Solve for v2':
10 = -5 + 10v2'
15 = 10v2'
15/10 = 1.5 m/s
We know that,
m1v1 + m2v2 = m1v1' + m2v2'
5 x 2 + 0 = 5 x -1 + 10 x v2'
10= -5 +10 x v2'
15 = 10 x v2'
v2' = 15/10
v2' = 1.5 m/s
hence , the speed of the larger ball after the collision will 1.5m/s
is climbing stairs work done
Answer:
The work you did in climbing the stairs is the force you applied (your weight) times the distance you moved upward (the height of the stairs.) So yes, climbing stairs is work done.
Explanation:
Hope this helped, nya~ :3
true and false? When an object remains stationary, any forces acting on it must be balanced.
Answer:
Balanced forces acting on a stationary object cause the object to remain at rest. True: Forces can give energy to an object it acts on causing the object to change it state of motion. If forces acting on an object are balanced, they do not cause a change in motion.
Answer:
False
Explanation:
It is NOT possible for just three forces to be acting upon an object and they still balance each other. A free-falling object experiences a balance of forces.
In the very distant future, given our best model of the accelerating universe, what will the universe look like?
The models of the universe allow finding the result for how serious the universe in the distant future is:
In the distant future the galaxies are far apart and the interaction between them would be negligible.
The Big Bang model shows that the universe was created at a certain point and time where from which all matter is separating at a speed from these objects.
Based on these models and the measurements that the galaxies are moving away, in the distant future the galaxies must be very far from each other so that the universe would be composed of isolated entities without the possibility of interaction between them.
Within each galaxy the bodies are not separated because in each one there is a black body whose gravity holds the stars within its galaxy together.
In conclusion of the models of the universe we can find the result for how serious the universe in the distant future is:
In the distant future the galaxies are far apart and the interaction between them would be negligible.
Learn more about the motion of the galaxies here: brainly.com/question/18212080
what Characteristic of an object is related to both kinetic energy and its potential energy a objects velocity b height c speed d mass
Answer:
I think it's a. Object velocity
Explanation:
.
Answer:
Object mass
Explanation:
I had answered and thats what it is
Which is a characteristic of tolerance? A.enjoying your hobbies B.accepting diversity C.having pride in your cultureD. knowing many types of people
Answer:
B
Explanation:
Because Tolerance Is The Level Of Ability That Someone Has To Recognise And Help Others Values And Differences.
A bus speeds up from 5 m/s to 15 m/s in 20 seconds. How far did it go during the 20 seconds? (use KE1 to find a, then use that to find xf)
The distance the bus travelled in 20 seconds is 12.75 m
The first step is to write out parameters given in the question
Final velocity= 15
Initial velocity= 5
Time= 20
Distance= ?
V² + U²= 2as
15² + 5²= 2(9.8)s
225+25= 19.6s
250= 19.6s
s= 250/19.6
= 12.75
Hence the distance the bus travelled in 20 seconds is 12.75 m
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What is the total of two or more numbers added together called?
weight
mass
sum
product
The sum of numbers is the total of two or more numbers added together.
Numbers is the arrangement of digits used to count, measure, and label. There are different types of numbers such as whole numbers, integers, natural numbers and many more.
The four basic mathematical operations are addition, subtraction, multiplication and division.
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Explain how work and power are different. Give an example of doing the same amount of work, but producing different amounts of power.
Answer:Work is a measurement of energy.
Power is a measurement of energy per time.
So, power measures how fast work is done.
If we raise 1kg up to a height of 1 meter it takes a certain amount of work. It doesn't matter if it takes us 1 second or 1 hour to raise it. It takes more power, energy per second, to raise it in 1 second than to raise it in one hour.
An engines power rating is in horsepower. A higher horsepower car engine will get a certain car up a hill more quickly than if it had a lower horsepower engine. Even though both engines did the same amount of work in getting the car up the hill
Answer:
work is a measurement of energy, but power is how much energy it takes. Two people could do the same amount of work. Sally and James. James may finish his work in 2 days due to the amount of power he puts in, but it may take Sally a week.
What is meant by collisions?
Answer:
come into conflict or opposition.
"in his work, politics and metaphysics collide
7. A taxi is travelling at 15 m/s. Its driver accelerates with acceleration 3 m/s2 for 4 s. What is its new velocity
Hi there!
To solve, we can use the following equation:
vf = vi + at
vi = initial velocity (m/s)
a = acceleration (m/s²)
t = time (s)
vf = final velocity (m/s)
Plug in the given values:
vf = 15 + 3(4)
vf = 15 + 12 = 27 m/s
Answer:
[tex]\boxed {\boxed {\sf 27 \ m/s}}[/tex]
Explanation:
We are asked to find the new or final velocity of a taxi.
We will use the following kinematic equation:
[tex]v_f=v_i+at[/tex]
The car was initially traveling at 15 meters per second. It accelerated at 3 meters per second squared for 4 seconds.
[tex]v_i=[/tex]15 m/s[tex]a=[/tex]3 m/s ²t= 4 sSubstitute the values into the formula.
[tex]v_f= 15 \ m/s + (3 \ m/s^2* 4 \ s)[/tex]
Multiply the numbers in parentheses.
3 m/s/s * 4 s = 3 m/s *4 = 12 m/s[tex]v_f= 15 \ m/s +12 \ m/s[/tex]
Add.
[tex]v_f=27 \ m/s[/tex]
The new velocity of the taxi is 27 meters per second.
Match these items. Match the items in the left column to the items in the right column. 1 . gravitational force the physical law nicknamed "action-reaction" 2 . Newton's First Law the physical law that states that planetary orbits are ellipses 3 . Copernican system described as a field 4 . Kepler's First Law the model of a planetary system that has the earth at the center 5 . Kepler's Second Law an example of a heliocentric system 6 . centripetal force the physical law that states that R3\T2 = K for a system 7 . Kepler's Third Law a spacecraft cruising at v = constant with its rockets shut down 8 . geocentric system the physical law that relates acceleration to net force 9 . Newton's Third Law gravitational force that keeps planets in orbit 10 . Newton's Second Law the physical law that states that equal areas are swept out in equal times
Answer:
i can't tell which is left and right
Explanation:
Answer:
1. gravitational force = described as a field
2. Newton's First Law = a spacecraft cruising at v = constant with its rockets shut down
3. Copernican system = an example of a heliocentric system
4. Kepler's First Law = the physical law that states that planetary orbits are ellipses
5. Kepler's Second Law = the physical law that states that equal areas are swept out in equal times
6. centripetal force = gravitational force that keeps planets in orbit
7. Kepler's Third Law = the physical law that states that R3\T2 = K for a system
8. geocentric system = the model of a planetary system that has the earth at the center
9. Newton's Third Law = the physical law nicknamed "action-reaction"
10. Newton's Second Law = the physical law that relates acceleration to net force
How many revolutions does the motor shaft turn through between the time when the current is reversed and the instant when the angular velocity is zero
Answer:it equals 0
Explanation:hope this is a good answer
Angular velocity is the ratio of angular displacement to time. Then the number of turns by the shaft is zero.
What is angular velocity?The rate of change of angular displacement is called angular velocity. It is a vector quantity.
We know that the angular velocity formula
[tex]\rm Angular \ velocity = \dfrac{Angular \ displacement}{time}[/tex]
The motor shaft turns through between the time when the current is reversed and the instant when the angular velocity is zero.
Then the number of turns will be
[tex]\rm Number \ of\ turns = Angular \ velocty \times time \\\\Number \ of\ turns = 0 *time \\\\Number \ of\ turns = 0[/tex]
The number of turns by the shaft is zero.
More about the Angular velocity link is given below.
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• What net force is needed to accelerate a 1200 kg car along a
horizontal surface from rest to 130 km/h in 80 seconds?
Hi there!
We can begin by converting 130 km/h to m/s:
[tex]\frac{130km}{1hr} * \frac{1hr}{3600s} * \frac{1000m}{1km} = 36.11 m/s[/tex]
Find the acceleration associated with this velocity change in the given time frame:
vf = vi + at (vi = 0 m/s)
vf = at
vf/t = a
36.11/80 = 0.45 m/s²
Now, we can calculate Net Force using Newton's Second Law:
∑F = ma
∑F = (1200)(0.45) ≈ 540 N