the distance (d) between two telephone poles is 49.5 m. a taut telephone wire is connected between the poles. when a 1.02 kg bird lands on the telephone wire midway between the poles, the wire sags 0.212 m (h). how much tension does the bird produce in the wire?
The tension in the wire created by the bird landing on it is calculated by using the equation T= (mgh)/d, where m is the mass of the bird, g is the acceleration due to gravity, h is the amount the wire sags and d is the distance between the two telephone poles.
In this case, with m = 1.02 kg, g = 9.81 m/s2, h = 0.212 m and d = 49.5 m, the tension in the wire is calculated as T = (1.02 kg x 9.81 m/s2 x 0.212 m)/49.5 m = 4.299 N.
This means that the bird produces a tension of 4.299 N in the telephone wire when it lands on it midway between the two poles. This amount of tension is relatively small, but enough to cause the wire to sag slightly. The tension in the wire will increase if the bird moves further along it, as the distance d between the poles will decrease.
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a cleaner pushes a 3.1-kg laundry cart in such a way that the net external force on it is 63 n. calculate the magnitude of its acceleration in m/s2.
Answer: The magnitude of the acceleration of the laundry cart is 20.32 m/s2.
The magnitude of the acceleration of the laundry cart can be calculated using the equation F = ma, where F is the force applied, m is the mass of the object and a is the acceleration.
We can rearrange the equation to solve for acceleration: a = F/m.
Plugging in the values we know, the acceleration of the laundry cart is:
a = 63N / 3.1kg = 20.32 m/s2
Therefore, the magnitude of the acceleration of the laundry cart is 20.32 m/s2.
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Compare and contrast how heat flows between a person and the environment for someone submerged in water and for someone in the air
Heat transfer between a person and the environment occurs through the processes of convection, conduction, and radiation. The rate of heat transfer depends on factors such as the temperature difference between the person.
What is a conduction ?Conduction is a process of heat transfer that occurs through a material or between two materials that are in direct contact with each other. In this process, heat flows from a region of higher temperature to a region of lower temperature through molecular collisions. The heat energy is transferred through the material or the contact surface by means of the vibration and movement of the molecules.
Conduction is responsible for heat transfer in solids, such as metals, ceramics, and polymers, and it can also occur between different solids in contact with each other. The rate of conduction depends on several factors, including the thermal conductivity of the material, the temperature difference between the two regions, the thickness of the material, and the surface area of contact.
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what magnitude force is required to give a helicopter of mass m an acceleration of 0.10g upward? express your answer in terms of the variable m and appropriate constants.
Magnitude of the force required to give the helicopter an acceleration of 0.10g upward is 0.981m N, where m is the mass of the helicopter in kilograms.
What is force?Physical quantity which causes or tends to cause a motion in any object at rest or changes or tends to change the direction of motion of a moving object or shape or size of object is called force.
Force required to give a helicopter of mass m an acceleration of 0.10g upward can be calculated using Newton's second law. Here, the acceleration is 0.10g, which can be expressed as:
a = 0.10g = 0.10 * 9.81 m/s² = 0.981 m/s²
F = ma
F = m * 0.981
Therefore, magnitude of the force required to give the helicopter an acceleration of 0.10g upward is 0.981m N, where m is the mass of the helicopter in kilograms.
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6. object x of mass m travels toward object y of mass 2m in such a way that they collide. the table contains data about the velocities of object x and object y immediately before the collision and immediately after the collision. what are the change in momentum of the two-object system from immediately before the collision to immediately after the collision?
The change in momentum of the two-object system from immediately before the collision to immediately after the collision is m(v-V) + 2m(V-v).
The change in momentum of the two-object system from immediately before the collision to immediately after the collision can be determined using the following equation:
Change in Momentum = Final Momentum - Initial Momentum.
The initial momentum of object x is given by the formula: Mass x Velocity = mv, where m is the mass of object x and v is the velocity of object x immediately before the collision. The initial momentum of object y is given by 2mv, where 2m is the mass of object y and v is the velocity of object y immediately before the collision. The final momentum of object x is given by m(v-V) where m is the mass of object x, v is the velocity of object x immediately before the collision and V is the velocity of object x immediately after the collision. The final momentum of object y is given by 2m(V-v) where 2m is the mass of object y, V is the velocity of object y immediately after the collision and v is the velocity of object y immediately before the collision. The change in momentum = m(v-V) + 2m(V-v).Therefore, the change in momentum of the two-object system from immediately before the collision to immediately after the collision is given by m(v-V) + 2m(V-v).
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you have learned that in the earth-moon system, the gravitational pull of earth's tidal bulges causes the moon to spiral away from earth. since triton has a retrograde orbit, how does this affects the neptune-triton system?
You have learned that in the earth-moon system, the gravitational pull of earth's tidal bulges causes the moon to spiral away from earth. since triton has a retrograde orbit, this affects the neptune-triton system to be unstable, making it difficult for the other moons to maintain stable orbits.
Triton is a large moon of Neptune, about 1,680 miles (2,700 kilometers) in diameter. Its orbit is tilted and is also in the opposite direction of the other moons in the solar system's plane. Triton's orbit is retrograde, which means it is moving in the opposite direction to Neptune's rotation. When an object orbits in the opposite direction to the rotation of the planet it orbits, it is said to have a retrograde orbit. This is because the gravitational attraction between the two objects is weaker when they are moving in opposite directions. Because of this, Triton's retrograde orbit has a destabilizing effect on Neptune's other satellites.
The retrograde orbit of Triton causes the Neptune-Triton system to be unstable, making it difficult for the other moons to maintain stable orbits. The gravitational force of Triton is pulling away at the other moons, causing them to move erratically, some being pushed further away from Neptune and others being pulled closer. In addition to the destabilizing effect, Triton's retrograde orbit has caused it to move closer to Neptune over time, where it is thought that it will eventually break apart, forming a ring around the planet.
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which of the following is an advantage of digital imaging? increased patient radiation exposure, increased chemical usage, increased speed for viewing images
One of the advantages of digital imaging is increased speed for viewing images.
Digital imaging is a technology that enables doctors to take X-rays, MRIs, CT scans, and other medical images, and store them digitally.
Digital imaging provides many advantages over traditional film-based imaging, such as increased speed for viewing images.
Digital imaging is a medical technology that allows physicians to take, store, and view medical images in digital form. Digital imaging includes modalities such as X-rays, computed tomography (CT), magnetic resonance imaging (MRI), and ultrasound.
Digital imaging provides several benefits, such as increased speed, improved diagnostic accuracy, lower radiation exposure, and reduced chemical usage. It also enables doctors to view images in real-time, making it easier to detect and diagnose medical conditions.
Additionally, digital images can be easily shared between medical professionals, allowing for better communication and collaboration.
The advantages of digital imaging include increased speed for viewing images. Instead of waiting for film-based images to be developed, doctors can view digital images instantly. This can be particularly important in emergency situations, where time is critical.
Digital imaging also allows doctors to manipulate images, zooming in or out as needed, to get a clearer view of the affected area or to identify specific features or abnormalities.
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if all motion is relative what happens when two objects traveling at a combined speed over the speed of light collide
If all motion is relative what happens when two objects traveling at a combined speed over the speed of light collide, According to Einstein's theory of relativity, it is impossible for an object with mass to travel at the speed of light or beyond it. The reason for this is that the faster an object travels, the more massive it becomes.
Therefore, if two objects with mass are traveling at a combined speed greater than the speed of light, it would violate the laws of physics and be impossible for them to collide. What is relative motion? Relative motion is the motion of an object relative to a point of observation. In other words, it is the motion of an object relative to a reference frame or observer.
An object's motion may appear different to different observers, depending on their relative motion with respect to the object. For example, a train may appear to be moving slowly to someone standing beside the tracks, but it may appear to be moving quickly to someone sitting inside the train. Therefore, all motion is relative, depending on the observer's frame of reference.
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what quantity describes the ability of a force to rotate an object? how does it differ from a force? on what quantities does it depend?
The quantity that describes the ability of a force to rotate an object is torque. It differs from a force in that it is a rotational force, not a linear force. Torque depends on the force applied and the distance from the point of application to the pivot point.
Torque is the measure of the ability of a force to cause rotational motion. It is defined as the product of the force and the distance between the point of application of the force and the pivot point or axis of rotation. Unlike a linear force, which produces linear motion, a torque produces rotational motion. The unit of torque is the newton-meter (N·m) in the SI system.
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A 2 kg mass moving to the right makes an elastic head-on collision with a 4 kg mass moving to the left at 4 m/s. The 2 kg mass reverses direction after the collision and moves at 3 m/s. The 4 kg mass moves to the left at 1 m/s. What was the initial velocity of the 2 kg mass?
Answer: That's a good question
Explanation:
a mass of 500g ball is kicked at angle of 45 degree to the horizontal the ball reaches 12m height what is the initial velocity
The initial velocity of a 500g ball kicked at a 45-degree angle to the horizontal and reaching a height of 12m can be calculated using the kinematic equation.
What is the kinematic equation?The equation of kinematics is a set of equations that are used to describe the motion of objects. They relate to displacement, velocity, acceleration, and time. Kinematic equations are divided into two categories, depending on the object's acceleration: zero acceleration and non-zero acceleration.
The kinematic equation for the object in motion with uniform acceleration is as follows:v^2 = u^2 + 2asWhere: v = final velocity u = initial velocity a = acceleration s = displacement. To calculate the initial velocity of the ball, we can rearrange the equation above to obtain:u^2 = v^2 - 2as From the given, a = -9.8 m/s² (negative acceleration indicates that the ball is decelerating or moving upward) s = 12m v = 0 (the final velocity is zero because the ball has stopped rising and is about to start falling). We'll use these values to calculate the initial velocity of the ball.u² = (0)² - 2(-9.8)(12)u² = 235.2u = sqrt(235.2)u = 15.33 m/s.
Therefore, the initial velocity of the ball is approximately 15.33 m/s.
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a van exerts a force on trailers of different masses m. compared with the force exerted on each trailer, rank the magnitude of force each trailer exerts on the van. (or are all pairs of forces equal in magnitude?)
The trailer pulls on the vehicle with an average force of A=B=C.
Newton's second law of acceleration is expressed as follows: F = ma
In this case, the mass is m, and the acceleration is a.
Assume that g=9.8 m/s2 represents the acceleration caused by gravity.
The acceleration of the object will be zero if it is travelling at a constant speed.
Because of the constant velocity, the van's net force on the trailer is therefore zero.
As a result, the van applies the same amount of force to each trailer. Thus, FA FB = FC.
As a result, each trailer pulls on the van with the same amount of force in the opposite direction. FA' = FB' = Fc', therefore.
As a result, A=B=C represents the rank of the force the trailer exerts on the van.
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trying to solve this please i need help asap
The force from student is positive, the force due to gravity is zero and the frictional force due to air is negative.
Given the distance of the bag from the room = 3m
From the diagram we can see that there are three different forces acting on the bag such as:
Fs : force from the student
FG: Force due to gravity
f: force of friction from air
Here we can say that according to the free-body diagram:
The force from from student(Fs) is acting upwards and is positive since the student is pushing the bag across the room, the force from the student (Fs) is doing positive work on the bag.
The force due to gravity(FG) is acting downwards and is zero since the bag is moving in a level room, the force of gravity (FG) is parallel to the motion of the bag and therefore isn't doing any work on the bag.
The work done by the frictional force of air (f) on the bag is negative since it is opposing the displacement of the bag.
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a copper wire of length 25 cm is in a magnetic field of 0.20 t. if it has a mass of 10 g, what is the minimum current through the wire that would cause a magnetic force equal to its weight?
The minimum current through the wire that would cause a magnetic force equal to its weight is 1.96 A.
The force experienced by a wire carrying a current (i) in a magnetic field (B) is given by the formula:
F = Bli
where l is the length of the wire.
The weight of the wire is given by the formula:
w = mg
where m is the mass of the wire and g is the acceleration due to gravity.
The minimum current that will cause the magnetic force on the wire to be equal to its weight is the current that makes F = w.
Find the weight of the wire using the formula:
w = mg = 0.01 kg × 9.8 m/s² = 0.098 N
Now, we can equate the weight of the wire to the force experienced by the wire in the magnetic field:
F = Bli
0.098 = 0.20 × 0.25 × i
i = 1.96
So, for the magnetic force on the wire to be equal to its weight, the current must be 1.96 A.
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a 75 kg skydiver is falling through air with a drag coefficient of 0.6. what is his terminal speed as he falls feet first?
The terminal speed of the skydiver as he falls feet first would be 54.9 m/s.
Terminal speed calculationTo find the terminal velocity of the skydiver, we need to balance the forces acting on him. At terminal velocity, the force of air resistance (also known as drag) is equal and opposite to the force of gravity. This means that the net force on the skydiver is zero and his velocity remains constant.
The force of air resistance is given by:
F_drag = (1/2) * rho * v^2 * C_d * A
where:
rho is the density of air (about 1.2 kg/m^3 at sea level)
v is the velocity of the skydiver
C_d is the drag coefficient (0.6 in this case)
A is the cross-sectional area of the skydiver
The force of gravity on the skydiver is given by:
F_gravity = m * g
where:
m is the mass of the skydiver (75 kg in this case)
g is the acceleration due to gravity (9.81 m/s^2)
At terminal velocity, F_drag = F_gravity, so we can set the two equations equal to each other:
(1/2) * rho * v^2 * C_d * A = m * g
Solving for v, we get:
v = sqrt((2 * m * g) / (rho * C_d * A))
Substituting in the values given, we get:
v = sqrt((2 * 75 kg * 9.81 m/s^2) / (1.2 kg/m^3 * 0.6 * 1.5 m^2))
v = 54.9 m/s
Therefore, the terminal speed of the skydiver is about 54.9 m/s when falling feet first with a drag coefficient of 0.6.
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describe the principle of hydrostatic equilibrium as it relates to the internal structure of a star. (select all that apply.)
The principle of hydrostatic equilibrium as it relates to the internal structure of a star: Hydrostatic equilibrium is a state in which a fluid is at rest and in which the pressure in the fluid is balanced by the weight of the surrounding material.
The pressure inside a star is balanced by the force of gravity, resulting in hydrostatic equilibrium inside the star. Hydrostatic equilibrium is the fundamental principle that governs the internal structure of a star. As a result, the star is prevented from collapsing under the gravitational forces acting upon it.
As a result, the star remains in a state of stability, maintaining its size and shape over long periods of time. A star's life is a delicate balance between gravitational forces that try to compress it and nuclear fusion that try to expand it.
The nuclear reactions in a star produce heat and radiation, which produces the outward force required to balance the inward force of gravity, maintaining the star's stability.
Therefore, the principle of hydrostatic equilibrium is crucial to the internal structure and stability of a star.
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do you think that sometimes even if all the trackers are green, they might produce the wrong camera solve/calibration?
Yes, sometimes even if all the trackers are green, they might produce the wrong camera solve/calibration.
The green tracker status indicates that the tracker is properly tracked, but it does not guarantee the accuracy of the camera solve. Various factors could lead to an incorrect camera solve.
One of the primary factors is improper tracking. In some cases, a tracker may seem to be in the right position, but the camera solver could generate an inaccurate camera solve if the tracker is not in the appropriate location on the image. To get accurate camera solves/calibration, you should place trackers in areas of high contrast, where the tracker can be tracked consistently throughout the sequence. If the trackers are placed in low-contrast regions, the tracker might not be tracked accurately, resulting in a poor camera solve. Therefore, it's critical to double-check the tracker placement for each frame to ensure that the tracking is accurate.
Other factors that could lead to an incorrect camera solve include incorrect lens distortion measurements, incorrect focal length measurements, improper image sequence alignment, incorrect image resolution, and other variables.
Hence, it is essential to monitor and inspect the solver settings to ensure accurate camera solve/calibration.
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a 25 kg iron block that is initially at 350 c is dropped into an insulated tank that contains 100 kg of water at 18 c. no water changes phase or leaves the tank in the process. determine the total entropy change during this process. the cp,water
The total entropy change during this process is, -16.4 J/°C.
To determine the total entropy change during this process, we need to consider both the entropy change of the iron block and the entropy change of the water in the tank. We can assume that the entire process is adiabatic (i.e., no heat transfer occurs between the system and the surroundings), so the total entropy change of the system is zero.
The entropy change of the iron block can be calculated as,
ΔS_iron = m × Cp_iron × ln(T_f / T_i)
where m is the mass of the iron block, Cp_iron is the specific heat capacity of iron, T_f is the final temperature of the iron block, and T_i is the initial temperature of the iron block.
Assuming that the final temperature of the iron block is the same as the temperature of the water in the tank (i.e., 18°C), we can calculate the entropy change of the iron block as,
ΔS_iron = 25 kg × 0.45 J/g°C × ln(18°C / 350°C)
≈ -16.4 J/°C
The entropy change of the water in the tank can be calculated as,
ΔS_water = m × Cp_water × ln(T_f / T_i)
where m is the mass of the water in the tank, Cp_water is the specific heat capacity of water, T_f is the final temperature of the water, and T_i is the initial temperature of the water.
Assuming that the iron block and the water reach a final temperature of 18°C, we can calculate the entropy change of the water as,
ΔS_water = 100 kg × 4.18 J/g°C × ln(18°C / 18°C)
= 0 J/°C
Therefore, the total entropy change during this process is,
ΔS_total = ΔS_iron + ΔS_water
≈ -16.4 J/°C + 0 J/°C
≈ -16.4 J/°C
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the speed of sound in air is approximately the same for all wavelengths. what evidence is there that this is true?
The speed of sound in air is approximately the same for all wavelengths.
Step by step Explanation :
The evidence that this is true is the following:
The speed of sound in air is approximately the same for all wavelengths. This is proved by the fact that a sound wave is an atmospheric disturbance that propagates as a longitudinal wave through the air, travelling as a pressure wave that causes areas of compression and rarefaction.
The speed of sound in air is constant and is determined by the average kinetic energy of the air molecules. This is why the speed of sound is the same for all wavelengths.
When the temperature of air is held constant, the speed of sound in air is constant. This is the primary reason why the speed of sound in air is practically constant at a given temperature.
The wavelengths of sound range from about 17 meters for the lowest audible frequency (about 20 Hz) to about 17 millimeters for the highest audible frequency (about 20,000 Hz).
The speed of sound in dry air at room temperature is around 343 meters per second, but it may vary depending on a variety of factors, including humidity, temperature, and pressure.
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blue objects absorb most wavelengths but reflect light at about 450 nm. this phenomenon relates to .
The blue objects absorb most wavelengths but reflect light at about 450 nm. This phenomenon relates to the colors of objects.
When the sunlight falls on an object, some of the light is absorbed, and the rest of the light is reflected. Objects appear to be a certain color because they absorb some colors of light and reflect others. Some objects appear blue because they absorb all colors of light except blue.
Blue light has a shorter wavelength than other colors of light, so it is scattered more in the Earth's atmosphere. The sky appears blue because the shorter blue wavelengths are scattered in all directions and are more likely to reach the observer's eye.
The light that is reflected off blue objects is at a wavelength of around 450 nm. When white light passes through a prism, it splits into the colors of the spectrum.
Violet light has the shortest wavelength, and red light has the longest wavelength. Between violet and green, the colors blend to form blue. So, if blue objects reflect light at around 450 nm, that means they reflect blue light.
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the graph starting from the instant it is released. how could a student use the graph to determine the total energy of the block-earth system?
A student can use the graph to determine the total energy of the block-earth system by finding the total area under the curve of the graph. This is because the area under the curve represents the work done on the block-earth system and work is a measure of energy.
What is a Graph?The graph can be a position-time curve, velocity-time curve or acceleration-time curve. The student can calculate the total energy of the block-earth system using the work-energy principle which states that the net work done on an object is equal to the change in its kinetic energy. This is given by the equation
W = ΔK
Where W is the net work done, and ΔK is the change in kinetic energy.
If the potential energy of the block is considered, then the equation will be
W = ΔK + ΔPU
where ΔPU is the change in potential energy.
The total energy of the block-earth system will be the sum of its kinetic energy and potential energy at any point in time.
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numerade a constant 10-n horizontal force is applied to a 20-kg cart at rest on a level floor. if friction is negligible, what is the speed of the cart when it has been pushed 8.0 m?
The speed of the cart is 4.0 m/s.
step by step explanation:
Force F is 10-N,
Distance d is 8.0-m, and
Mass m is 20-kg,
A constant 10-N horizontal force is applied to a 20-kg cart at rest on a level floor.
If friction is negligible, then the speed of the cart when it has been pushed 8.0 m can be calculated using the equation v = Fd/m,
where v is the speed of the cart,
F is the applied force,
d is the distance, and
m is the mass of the cart.
so the speed of the cart is v = (10 N × 8.0 m) / 20 kg = 4.0 m/s.
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T or F: Surface currents flow vertically in the uppermost 400 meters of the water column. False (horizontally).
The given statement, "surface currents flow vertically in the uppermost 400 meters of the water column," is false because surface currents flow horizontally in the uppermost 400 meters of the water column. They move water parallel to the surface, driven by factors such as wind and temperature differences.
Surface currents are driven by the wind, and they are characterized by movement across the surface of the water. The direction and intensity of surface currents are influenced by a variety of factors, including wind speed and direction, the shape of the coastline, and the rotation of the Earth. These currents are an essential component of the ocean circulation system and can have a significant impact on the climate and the distribution of marine life. They flow parallel to the water columns in the uppermost parts.
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how much energy is stored by the electric field between two square plates, 9.3 cm on a side, separated by a 2.5- mm air gap? the charges on the plates are equal and opposite and of magnitude 13 nc .
The electric field stored between two square plates of 9.3 cm on a side and separated by a 2.5 mm air gap is 1110 N/C. This can be calculated using Coulomb's law and the given information.
Coulomb's law states that the electric field is equal to the charge (Q) divided by the permittivity of free space (ε₀) multiplied by the distance (d) squared:
E=Q/(ε₀*d²).
Plugging in the given information,
E=(13 nC)/(8.85 x 10⁻¹² * 0.0025²) = 1110 N/C.
This answer uses Coulomb's law to calculate the electric field stored between two square plates, given the plates' side lengths, air gap width, and charge magnitude.
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a bullet of mass 0.010 kg and speed of 100 m/s is brought to rest in a wooden block after penetrating a distance of 0.10 m. this process takes 0.02 second. the magnitude of the impulse delivered to the bullet by the block during this time is
The magnitude of the impulse delivered to the bullet by the block during this time is 0.90 Ns.
The mass of the bullet is given as 0.010 kg and its initial speed as 100 m/s. After travelling 0.10 m, the bullet comes to rest in a wooden block. The time taken for the bullet to stop is 0.02 seconds. We need to calculate the magnitude of the impulse delivered to the bullet by the block during this time. We can use the formula for impulse, which is Impulse = Force × Time. Impulse is defined as the change in momentum. Thus, we can use the equation m₁v₁ - m₁v₂ = F×t , where m₁ is the mass of the bullet, v₁ is the initial speed of the bullet, v₂ is the final velocity of the bullet, t is the time for which the force acts, and F is the force applied on the bullet. In this case, we know the mass and initial speed of the bullet. We need to find the final velocity of the bullet to calculate the force. We can use the formula for final velocity, which is v₂ = u + at , where u is the initial velocity of the bullet, a is the acceleration due to the force acting on the bullet, and t is the time for which the force acts. Here, the force acting on the bullet is the force of the wooden block, and the acceleration is given by a = F/m₁ . Thus, we have v₂ = u + F/m₁ × t . The distance travelled by the bullet is given as 0.10 m. We can use the formula for distance travelled, which is s = ut + ½at² . Here, s is the distance travelled by the bullet, u is the initial velocity of the bullet, a is the acceleration due to the force acting on the bullet, and t is the time for which the force acts. We have u = 100 m/s, s = 0.10 m, and t = 0.02 s. We can use this equation to calculate the acceleration of the bullet. Solving for a, we get a = (2s - ut) / t² = (2 × 0.10 - 100 × 0.02) / (0.02)² = -450 m/s². Here, the negative sign indicates that the acceleration is in the opposite direction to the velocity of the bullet. Substituting this value of a in the equation for v₂, we get v₂ = 100 - 450 × 0.02 / 0.010 = 10 m/s. Thus, the change in velocity of the bullet is Δv = v₂ - v₁ = 10 - 100 = -90 m/s. The magnitude of the impulse delivered to the bullet by the block during this time is |Impulse| = m₁ × |Δv| = 0.010 × 90 = 0.90 Ns. Therefore, the magnitude of the impulse delivered to the bullet by the block during this time is 0.90 Ns.
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(6) As the aeroplane travels away from the airport; it sends signal to the airport uslng radio waves wlth wavelength of 1,2m: When the signal Is received at the alrport; the wavelength Is 1.1 x 10"m longer than when It Is emitted by the aeroplane: Calculate the speed of the aeroplane using the formula change of wavelength speed of aeroplane wavelength speed of radlo wave [speed of radio waves = 3.0x 10" m/s] speed of aeroplane m/s (Total for Questlon 5 6 marks)
The problem involved calculating the speed of an airplane using the change in wavelength of radio waves it emits. By using the formula and substituting the given values, we found that the speed of the airplane is 2.5 x 10^5 m/s.
The given information can be summarized as:
The wavelength of the radio wave emitted by the airplane = λ_emitted = 1.2 m
The wavelength of the radio wave received at the airport = λ_received = λ_emitted + 1.1 x 10^-6 m
The speed of the radio wave = v_wave = 3.0 x 10^8 m/s
We can use the formula given in the problem to find the speed of the airplane:
change of wavelength = speed of airplane x wavelength / speed of radio wave
Substituting the given values, we get:
λ_received - λ_emitted = speed of airplane x λ_emitted / v_wave
Simplifying and solving for the speed of the airplane, we get:
speed of airplane = (λ_received - λ_emitted) x v_wave / λ_emitted
Plugging in the values, we get:
speed of airplane = (1.2 + 1.1 x 10^-6 - 1.2) x 3.0 x 10^8 / 1.2
speed of airplane = 2.5 x 10^5 m/s
Therefore, the speed of the airplane is 2.5 x 10^5 m/s.
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A 7.00-g bullet is fired horizontally into a 1.20-kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.20. The bullet remains embedded in the block, which is observed to slide 0.390 m along the surface before stopping.What was the initial speed of the bullet?Express your answer with the appropriate units
A 7.00-g bullet is fired horizontally into a 1.20-kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between the block and the surface is 0.20. The bullet remains embedded in the block, which is observed to slide 0.390 m along the surface before stopping the initial velocity of the bullet was 958 m/s.
First, let's calculate the momentum of the bullet before the collision. Momentum is defined as mass times velocity, so we need to find the velocity of the bullet. We can use the fact that the bullet remains embedded in the block to determine the final velocity of the bullet-block system. The momentum of the system is equal to the mass of the system times its velocity.
Let's call the initial velocity of the bullet "v". The mass of the system is the mass of the bullet plus the mass of the block, which is 7.00 g + 1.20 kg = 1.207 kg. After the collision, the block and bullet move together at a final velocity of "vf". We can use the fact that the block slides 0.390 m along the surface before stopping to determine vf. The work done by friction is equal to the force of friction times the distance over which it acts. This work is equal to the change in kinetic energy of the system, which we know is equal to the initial kinetic energy of the bullet. We can write:
frictional force x distance = 1/2 x m x v^2
The frictional force is equal to the coefficient of kinetic friction times the normal force, which is equal to the weight of the block. We can write:
0.20 x 1.20 x 9.81 x 0.390 = 1/2 x 1.207 x vf^2
Solving for vf, we get:
vf = 2.62 m/s
Now we can use the conservation of momentum to find the initial velocity of the bullet:
m_bullet x v = (m_bullet + m_block) x vf
7.00 g x v = 1.207 kg x 2.62 m/s
v = 958 m/s
So the initial velocity of the bullet was 958 m/s.
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water travels through a 9.6 cm diameter fire hose with a speed of 1.3 m/s. at the end of the hose, the water flows out through a nozzle whose diameter is 2.5 cm. what is the speed of the water coming out of the nozzle?
The speed of the water coming out of the nozzle is 19.2 m/s. The result is obtained by using the formula for volumetric flow rate.
How to count the water flow rate in pipes of different diameters?The speed of the water coming out of the nozzle can be calculated using the flow rate equation. This equation states that the flow rate of a fluid passing through a constant cross-sectional area is constant, meaning that the water coming out of the nozzle must have the same flow rate as it did when it entered the hose.
Q₁ = Q₂
A₁v₁ = A₂v₂
We have
Determine v₂!
While A is the cross-sectional area of the hose and nozzle, it can be find by πr², where r = ½d.
Using the formula above, we get:
πr₁² × v₁ = πr₂² × v₂
(½(9.6))² × 1.3 = (½(2.5))² × v₂
23.04 × 1.3 = 1.562 × v₂
v₂ = 19.2 m/s
Hence, the speed of the water coming out of the nozzle is 19.2 m/s.
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Please help me, been trying to figure it out but I cant.
An m= 68.0 kg person running at an initial speed of
v = 4.10 m/s jumps onto an M=136 kg cart initially at rest. The person slides on the cart's top surface and finally comes to rest relative to the cart. The coefficient of kinetic friction between the person and the cart is 0.420 . Friction between the cart and can be ignored. (Let the positive direction be to the right)
(a) Find the final velocity of the person and cart relative to the ground. (Indicate the direction with the sign of your answer.) ______ m/s
(b) Find the friction force acting on the person while he is sliding across the top surface of the cart. (Indicate the direction with the sign of your answer.)
______ N
(c) How long does the friction force act on the person? ______ s (d) Find the change in momentum of the person. (Indicate the direction with the sign of your answer.)
______ N⋅s
Find the change in momentum of the cart. (Indicate the direction with the sign of your answer.)
______ N⋅s
(e) Determine the displacement of the person relative to the ground while he is sliding on the cart. (Indicate the direction with the sign of your answer.) ______ m (f) Determine the displacement of the cart relative to the ground while the person is sliding. (Indicate the direction with the sign of your answer.) ______ m (g) Find the change in kinetic energy of the person. ______ J (h) Find the change in kinetic energy of the cart.
Explain why the answers to (g) and (h) differ. (What kind of collision is this one, and what accounts for the loss of mechanical energy?)
(a) The final velocity of the person and cart relative to the ground is 0 m/s.
(b) The friction force acting on the person while he is sliding across the top surface of the cart is -28.96 N, acting in the negative direction.
(c) The friction force acts on the person for a time of 1.50 s.
(d) The change in momentum of the person is -103.2 N⋅s, acting in the negative direction.
(e) The displacement of the person relative to the ground while he is sliding on the cart is 6.07 m, acting in the positive direction.
(f) The displacement of the cart relative to the ground while the person is sliding is 3.03 m, acting in the positive direction.
(g) The change in kinetic energy of the person is -128.8 J.
(h) The change in kinetic energy of the cart is -64.4 J.
This is an inelastic collision, meaning that the kinetic energy of the system is not conserved. This is because some of the kinetic energy is lost to friction as the person slides across the cart's surface. As the person has a greater mass than the cart, the change in kinetic energy of the person is greater than that of the cart. The total kinetic energy of the system is thus decreased, as the person and cart come to rest relative to each other.
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