suppose a student conducted a titration of an unknown solution of the weak acid ch3cooh with 0.880 m naoh. first, the student diluted 15.0 ml of the ch3cooh solution with 85.0 ml of water in an erlenmeyer flask and added 2 drops of the indicator, phenolphthalein. then, 0.880 m naoh was titrated into the diluted ch3cooh solution until the color of the solution changed to pink and the end point of the titration was reached. at the end point, 6.80 ml of 0.880 naoh was added to the ch3cooh solution. calculate the concentration of the ch3cooh solution.

The phenomenon is called reversion. It is caused when the medium used has a lower amount of carbohydrates and occasionally produces false (pink/alkaline) results after 48 hours. Two steps that can be taken to prevent reversion are increase the amount of carbohydrates in the medium used and reducing the incubation period of the medium used,

The phenomenon known as reversion occurs when the test results turn out to be pink/alkaline despite the presence of lactose and glucose, indicating the absence of a positive reaction. This occurs as a result of glucose exhaustion after 24 hours, and lactose is then broken down into galactose and glucose, both of which may be utilised by the microorganisms.

As the microorganisms consume these sugars, the medium's pH rises, causing a shift from acid to alkaline. The pH increase results in the formation of an alkaline pH that turns the pH indicator pink, this phenomenon is referred to as reversion. The factors contributing to the phenomenon are a minimal amount of carbohydrates in the medium and reduced incubation time. Two steps that can be taken to prevent reversion are increase the amount of carbohydrates in the medium used and reducing the incubation period of the medium used.

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The meta oxides when dissolved in water they gives us there ions as the major products of the dissolving substance.

When M₂O is mixed with water, it dissociates into ions because it is water soluble.

M2O → 2M⁺ + O⁻

The process of dissolving a gaseous, liquid, or solid solute in a solvent to form a solution is called dissolution. The maximum concentration of a solute that can be dissolved in a solvent at a given temperature is called solubility. A solution is said to be saturated when it contains the maximum amount of solute.

Ionic compounds dissolve in water if the energy released when the ions interact with water molecules offsets the energy needed to break ionic bonds in the solid and separate the water molecules, so that the ions can be dissolved.

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The pH of the resulting solution after the addition of 13.0 mL of 0.100 M HCl is 4.7. This indicates that the solution is acidic and that there is still some of the weak acid HA remaining in the solution.

The addition of the strong acid HCl will react with the weak base A- produced during the titration, forming the weak acid HA and neutralizing some of the OH- ions present. This will result in a lower pH than the pH at the equivalence point, and the difference between the two pH values can be used to calculate the dissociation constant (pKa) of the weak acid.

At the equivalence point, the pH is determined by the dissociation constant (Ka) of the weak acid. In this case, the pale-pink phenolphthalein endpoint indicates that the pH at the equivalence point is approximately 8.5-9.5.

Since the pH at the equivalence point is higher than the pH of 4.7 after the addition of HCl, the weak acid must be less dissociated at the latter pH.

This means that the pKa of the weak acid is higher than the pH of 4.7, because a higher pKa corresponds to a weaker acid and a lower degree of dissociation.

Therefore, we can conclude that the pKa of the unknown weak acid HA is greater than 4.7, based on the pH of the resulting solution after the addition of HCl.

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The correct order is: Fr 1, Ba 2, In 3, Sn 4, Se 5

To arrange the following elements in order of increasing metallic character (1 = most, 6 = least): Fr, Sn, In, Ba, Se, you should consider their positions in the periodic table. As you move down a group, metallic character increases; as you move left across a period, metallic character also increases.

Step 1: Locate the elements in the periodic table:
Fr (Francium): Group 1, Period 7
Sn (Tin): Group 14, Period 5
In (Indium): Group 13, Period 5
Ba (Barium): Group 2, Period 6
Se (Selenium): Group 16, Period 4

Step 2: Order the elements according to the trends in metallic character:
1. Fr (most metallic character)
2. Ba
3. In
4. Sn
5. Se (least metallic character)

So the correct order is: Fr 1, Ba 2, In 3, Sn 4, Se 5.

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All of the examples listed could be considered to exhibit well-designed structures supporting well-designed functions, but the level at which they are designed may differ.

A squirrel's teeth and jaws are well-designed structures that allow them to strip open sunflower seeds, which is a well-designed function for obtaining food. Similarly, an otter's use of a pebble as a tool to break into a mussel shell is also an example of well-designed structures supporting well-designed functions.

A molecule of the correct dimensions storing information is an example of a well-designed structure at the molecular level that supports the well-designed function of storing genetic information. Likewise, enzymes are also well-designed structures that catalyze specific chemical reactions, and the breaking of a specific covalent bond to generate a specific molecular product is an example of a well-designed function.

Therefore, the correct answer is: all of the above.

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In a face-centered cubic (FCC) lattice, each unit cell contains atoms at each of its eight corners and one atom at the center of each of its six faces.

To calculate the diameter of the metal atom, we need to know the relationship between the edge length of the unit cell and the diameter of the atom. In an FCC lattice, the atoms are arranged in a close-packed arrangement, where the atoms touch along the face diagonal of the unit cell.

The face diagonal of an FCC unit cell can be calculated using the Pythagorean theorem:

face diagonal = sqrt(2) x edge length

Substituting the given value for the edge length of the unit cell:

face diagonal = sqrt(2) x 434 pm = 614 pm

The diameter of the metal atom is equal to the distance between the centers of two adjacent atoms along the face diagonal of the unit cell. In an FCC lattice, the atoms touch along the face diagonal, so the distance between the centers of two adjacent atoms is equal to the length of the face diagonal minus the diameter of the atom:

diameter of atom = face diagonal - atomic radius

where atomic radius is half of the diameter of the atom.

Rearranging this equation to solve for the diameter of the atom, we get:

diameter of atom = face diagonal - 2 x atomic radius

Substituting the given value for the face diagonal and solving for the atomic radius:

atomic radius = (face diagonal - diameter of atom)/2

diameter of atom = face diagonal - 2 x atomic radius

diameter of atom = 614 pm - 2 x atomic radius

We are given the edge length of the unit cell, but we need to find the diameter of the atom. Therefore, we need to rearrange the above equations to solve for the diameter of the atom:

atomic radius = edge length/2

diameter of atom = face diagonal - 2 x atomic radius

diameter of atom = 614 pm - 2 x (edge length/2)

diameter of atom = 614 pm - 2 x 434 pm

diameter of atom = 614 pm - 868 pm

diameter of atom = -254 pm (This answer is negative, which is not physically meaningful.)

Therefore, we cannot calculate the diameter of the metal atom with the given information. There might be some mistake in the calculation or the given value for the edge length of the unit cell.

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When carrying out the synthesis of meso-hydrobenzoin, the initially expected observation that would not be observed had all the NaBH₄ added to the reaction mixture decomposed before reacting with benzil is a reduction in the solution volume.

What is the Synthesis of Meso-Hydrobenzoin, The synthesis of meso-hydrobenzoin involves the reduction of benzil using NaBH₄, which produces hydrobenzoin. In order to obtain meso-hydrobenzoin, hydrobenzoin must be dissolved in hot ethanol, followed by adding a seed crystal.

This mixture is allowed to cool, causing the formation of meso-hydrobenzoin crystals. Initially, if all of the NaBH₄ added to the reaction mixture decomposed before reacting with benzil, there would be no observable reduction in the volume of the solution. This is because the reduction of benzil using NaBH₄ is an exothermic reaction that produces hydrogen gas. As a result, the volume of the solution would decrease over time.

Therefore, if there was no reduction in the solution volume, it would be an indication that the NaBH₄ did not react with the benzil.

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The carbon concentration of an iron–carbon alloy for which the fraction of total ferrite is 0.94 at the temperature of about 700℃ (at which the field extends to 0.022 wt% c) is 0.06 wt% c.

An iron-carbon alloy is an alloy of iron and carbon that is commonly used in the manufacture of industrial goods. Steel, wrought iron, and cast iron are all examples of iron-carbon alloys. Iron-carbon alloys' properties are determined by their carbon content. Carbon content in the alloys may range from 0.008 to 2.14 percent by weight.

The amount of carbon in an iron-carbon alloy is referred to as its carbon concentration. When the iron-carbon alloy is melted or worked, carbon is added to it, and the carbon concentration is calculated by dividing the amount of carbon by the alloy's weight.

Therefore, the carbon concentration of an iron–carbon alloy for which the fraction of total ferrite is 0.94 at the temperature of about 700℃ (at which the field extends to 0.022 wt% c) is 0.06 wt% c.

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Since Q < Ksp (4.0x10-5), PbF2 will not precipitate out of solution. The solution will contain Pb2+, F-, NH4+, and NO3- ions in equilibrium.

When lead nitrate (Pb(NO3)2) and ammonium fluoride (NH4F) are mixed, they will react to form lead fluoride (PbF2) and ammonium nitrate (NH4NO3) according to the following balanced chemical equation:

Pb(NO3)2 + 2 NH4F → PbF2 + 2 NH4NO3

To determine whether or not PbF2 will precipitate out of solution, we need to calculate the ion product (Q) and compare it to the solubility product constant (Ksp) for PbF2. The ion product is calculated by multiplying the concentrations of the lead ion (Pb2+) and the fluoride ion (F-) in solution.

First, we need to calculate the concentration of Pb2+ and F- in solution after the reaction has occurred. Since the initial concentrations of Pb(NO3)2 and NH4F are both 2.0x10-4 M, the total volume of the solution is 100.00 mL. Therefore, the concentration of Pb2+ and F- after the reaction will be:

[Pb2+] = (50.00 mL / 100.00 mL) × 2.0x10-4 M = 1.0x10-4 M

[F-] = (50.00 mL / 100.00 mL) × 2.0x10-4 M = 1.0x10-4 M

Now we can calculate the ion product:

Q = [Pb2+][F-] = (1.0x10-4 M)(1.0x10-4 M) = 1.0x10-8

Since Q < Ksp (4.0x10-5), PbF2 will not precipitate out of solution. The solution will contain Pb2+, F-, NH4+, and NO3- ions in equilibrium.

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The balanced chemical equation for the reaction between carbon (C) and oxygen (O2) to form carbon monoxide (CO) and carbon dioxide (CO2) is below and the moles of CO2 produced is 0.117.

C + O2 → CO + CO2

According to the equation, for every 1 mole of C, we need 1 mole of O2 to produce 1 mole of CO and 1 mole of CO2.

Given that we have 0.155 moles of C and 0.117 moles of O2, we can use the mole ratio from the balanced equation to determine how many moles of CO2 could be produced:

Moles of CO2 = Moles of C = 0.155 moles

Therefore, based on the moles of each reagent, we could produce a maximum of 0.155 moles of CO2.

To determine the limiting reagent, we need to calculate the amount of CO2 that would be produced if all of the limiting reagent were consumed. We can do this by comparing the amount of CO2 that would be produced by each reagent and identifying the one that produces the smaller amount:

Using C as the limiting reagent:

Moles of CO2 produced = Moles of C = 0.155 moles

Using O2 as the limiting reagent:

Moles of CO2 produced = Moles of O2 × (1 mole CO2 / 1 mole O2) = 0.117 moles × (1 mole CO2 / 1 mole O2) = 0.117 moles

Since the amount of CO2 produced by the reaction with C is greater than the amount produced by the reaction with O2, we can conclude that O2 is the limiting reagent for this problem. Therefore, only 0.117 moles of CO2 could be produced based on the available amount of O2, and any excess C would be left over after the reaction.

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The correct option is (A) - This Bohr Model of atom describes that there are a total of 6 electrons in the given figure.

The electrons are positioned in circular orbitals at particular distances from the central nucleus in the Bohr model of the atom. These orbits create electron shells or energy levels, which allow us to see how many electrons are present in each shell. The number and the letter "n" are used to identify these energy levels. The first energy level nearest to the nucleus, for instance, is represented by the 1n shell. Normally, an electron resides in the shell with the lowest energy, which is the one closest to the nucleus. A photon of light's energy can raise it to a higher energy shell, but this is an unstable position, and the electron quickly returns to the ground state.

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Option B, singing in a tiled shower, is most likely to produce a loud echo. This is because sound waves reflect more easily off hard and smooth surfaces, which are found in a tiled shower. This means that sound waves will bounce back and forth between the walls, floor, and ceiling of the shower, creating a series of reflections that can produce a perceptible echo. In comparison, a furnished, carpeted room (option A) would have more sound-absorbing materials, such as furniture and carpet, which would dampen the sound waves and reduce the likelihood of an echo. Option C, yelling across an open field, would also not produce a loud echo, as it requires a reflective surface to bounce off of. In an open field, there are no nearby surfaces for the sound waves to reflect off of, so they will simply dissipate into the air.

The observation that only 28.3 grams or 56.6 grams of mercury are consumed in the reactions is consistent with the Law of Multiple Proportions, which predicts that the masses of the elements that combine are in small whole number ratios.

According to the Law of Multiple Proportions, when two elements form more than one compound, the masses of one element that combine with a fixed mass of the other element are in the ratio of small whole numbers.

In this case, chlorine is reacting with mercury to form different compounds, and the masses of mercury consumed in the two reactions are in the ratio of 1:2, which is a small whole number ratio.

If we assume that the fixed amount of chlorine used in both reactions is 10 grams, then we can calculate the expected mass of mercury consumed based on the law of multiple proportions.

If the first reaction consumes 28.3 grams of mercury, then the ratio of mercury to chlorine is 2.83:1. If the second reaction consumes 56.6 grams of mercury, then the ratio of mercury to chlorine is 5.66:1.

We can see that the ratios of mercury to chlorine in the two reactions are in the ratio of 2:1, which is a small whole number ratio, consistent with the Law of Multiple Proportions.

This suggests that chlorine is reacting with mercury to form two different compounds with a fixed ratio of chlorine to mercury, and that the mass ratios of the compounds are related by small whole numbers.

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The age of the muscovite crystal is 0.86 billion years.

We can use the half-life formula to determine the age of the muscovite crystal. The half-life formula is given as:

N = N₀ (1/2)^t/T

Where N is the remaining quantity of a substance, N₀ is the original quantity, t is the time that has passed, and T is the half-life of the substance.

Substituting the given values, we get:

N/N₀ = (1/2)^(2.2)T (N₀/2^2.2) = N

The age of the muscovite crystal is given by t, which we can calculate using the following formula:

t = T * log (N₀/N)

Substituting the values of N₀ and N, we get:

t = 1.3 * 10^9 * log (1/2^2.2)t = 1.3 * 10^9 * log (1/4.59479342)

t = 1.3 * 10^9 * 0.662t = 860.6 million years

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C. "Sifting ore at the site before transporting" is the way that optimizes environmental impact.

This method can help to reduce the amount of waste material that needs to be transported and processed, which in turn reduces the environmental impact associated with mining operations, such as land degradation, soil erosion, and water pollution. By removing unwanted materials from the ore at the site, the amount of waste material generated can be reduced, which can also save energy and lower greenhouse gas emissions associated with transportation and processing.

What is an ore?

An ore is a naturally occurring mineral or rock that contains a valuable substance that can be extracted at a profit. Ores typically contain metals, such as copper, iron, gold, silver, and aluminum, or non-metallic minerals, such as phosphate, limestone, and sulfur.

The valuable substance in an ore is usually present in relatively high concentrations compared to other minerals in the rock or mineral deposit, and can be extracted through mining and processing using various methods, such as smelting, leaching, and refining. The identification and extraction of ores have been a vital part of human civilization for thousands of years, and the discovery of new ores and improved extraction methods have played an important role in shaping the development of technology, industry, and society.

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Complete question is: C. "Sifting ore at the site before transporting" is the way that optimizes environmental impact.

Pressure is accepted as constant when using the Gibbs free energy equation, ΔH − TΔS.

The Gibbs free energy equation is a thermodynamic equation used to determine whether a chemical reaction is spontaneous or non-spontaneous under certain conditions. The equation is:

ΔG = ΔH - TΔS

where:

   ΔG is the variation in Gibbs free energy

   ΔH is the change in enthalpy

   T is the temperature in Kelvin

   ΔS is the change in entropy

If ΔG is negative, the reaction is spontaneous (i.e., it will occur without an external input of energy). If ΔG is positive, the given reaction is not spontaneous, and thus it will not occur without an external input of energy. If ΔG is zero, then it means that the reaction is at equilibrium.

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If the theoretical yield is 20 grams and the actual yield is 17 grams, the percent yield would be 85%.

To get the mass per mole, divide the reactant's mass by its molecular weight. As an alternative, we can multiply the millilitres of the reactant solution by the grams per millilitre of the liquid solution.

Once you have the theoretical yield, you can use the following formula to calculate the percent yield:

percent yield = (actual yield / theoretical yield) x 100%

For example, if the theoretical yield is 20 grams and the actual yield is 17 grams, the percent yield would be:

percent yield = (17 grams / 20 grams) x 100% = 85%

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Increasing the surface area of one or more reactants generally increases the reaction rate of a system. This is because the rate of a chemical reaction is dependent on the frequency of successful collisions between reactant particles, which is in turn dependent on the surface area available for those collisions to occur.

When the surface area of a reactant is increased, the number of reactive sites available for collisions with other particles also increases. This results in a greater number of successful collisions and a higher reaction rate.

For example, consider the reaction of a solid metal with a gaseous reactant. If the metal is initially in the form of a solid block, the surface area available for reaction is limited to the exposed surface area of the block.

However, if the metal is ground into a powder, the surface area available for reaction increases significantly, allowing for a much greater number of successful collisions and a higher reaction rate.

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--The given question is incorrect, the correct question is

"How will increasing the surface area of one or more reactants affect the reaction rate of a system?"--

C. All the water would reach an equilibrium temperature and heat would stop flowing.

When hot and cold water are mixed together, heat flows from hotter to colder until both reach a common temperature. This is because the molecules in the hotter water have more kinetic energy than those in the colder water, and so they transfer some of their energy to the colder water until both have the same amount of energy. Eventually, all the water in the mixture will reach the same temperature, and heat transfer will stop. Therefore, the end result of mixing hot and cold water would be that all the water would reach an equilibrium temperature and heat would stop flowing.

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We can use the ideal gas law to solve this problem:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in kelvins.

First, we need to calculate the number of moles of CO2 using its molar mass:

molar mass of CO2 = 12.01 + 2(15.99) = 44.01 g/mol

moles of CO2 = 20.0 g / 44.01 g/mol = 0.454 mol

Next, we can rearrange the ideal gas law to solve for V:

V = (nRT) / P

V = (0.454 mol)(8.31 J/(mol·K))(298 K) / (105 kPa) = 10.5 L

Therefore, 20.0 g of CO2 would occupy a volume of 10.5 L at a temperature of 25°C and a pressure of 105 kPa.

100.0ml solution of 0.30m cu(no3)2 is mixed with 100.0ml of 6.0 m ammonia solution, the concentration cu in the resulting mixture is: 0.15 M.

To find the concentration of Cu in the resulting mixture, follow these steps:

1. Calculate the moles of Cu(NO3)2 in the initial solution: moles = Molarity × Volume
  moles of Cu(NO3)2 = 0.30 M × 0.100 L = 0.030 mol

2. Determine the moles of Cu in the Cu(NO3)2 solution (1:1 ratio between Cu and Cu(NO3)2)
  moles of Cu = 0.030 mol

3. Calculate the total volume of the resulting mixture:
  Total volume = Volume of Cu(NO3)2 solution + Volume of ammonia solution
  Total volume = 0.100 L + 0.100 L = 0.200 L

4. Calculate the new concentration of Cu in the resulting mixture: Molarity = moles / Volume
  Molarity of Cu = 0.030 mol / 0.200 L = 0.15 M

So, the concentration of Cu in the resulting mixture is 0.15 M.

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Answer:

Explanatidescribe everyday events such as shaving, ear peircing, and brushing teeth so that they do not sound like "primitive" customs.

on:

The pH of the buffer solution will be 8.1. containing an acid of pka8.1, with an acid concentration equivalent to that of its conjugate base

The pH of a buffer solution can be determined using the Henderson-Hasselbalch equation, which is:

pH = pKa + log([A-]/[HA])

In this case, the buffer solution contains an acid with a pKa of 8.1 and has an acid concentration ([HA]) equal to the concentration of its conjugate base ([A-]). Therefore, the ratio [A-]/[HA] is equal to 1.

Now, let's plug in the values into the equation:

pH = 8.1 + log(1)

Since the log of 1 is 0, the equation simplifies to

pH = 8.1

So the pH of the buffer solution will be 8.1. This is because the acid and its conjugate base are present in equal concentrations, maintaining a balanced pH close to the pKa value of the acid. The buffer's ability to resist changes in pH comes from the presence of both the weak acid and its conjugate base, which can neutralize any added acids or bases and keep the pH stable.

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The combination of elements that will be most likely to form an ionic compound is one where there is a large difference in electronegativity between the two atoms. This is because ionic bonds are formed when there is a transfer of electrons from one atom to another, resulting in the formation of cations and anions.

In general, metal atoms tend to have low electronegativities, while nonmetal atoms tend to have high electronegativities. Therefore, a combination of a metal and a nonmetal is most likely to form an ionic compound.

For example, sodium (Na) is a metal with low electronegativity, while chlorine (Cl) is a non-metal with high electronegativity. When sodium and chlorine react, sodium donates its outer electron to chlorine, forming the ionic compound sodium chloride (NaCl).

Other examples of metal-nonmetal combinations that are likely to form ionic compounds include magnesium (Mg) and oxygen (O) (forming MgO), and aluminium (Al) and fluorine (F) (forming AlF3).

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The element that conducts electricity to some extent and tends to form molecular compounds is most likely a nonmetal

Nonmetals have high electronegativity and tend to gain or share electrons to form molecular compounds. Some examples of nonmetals include hydrogen, carbon, nitrogen, oxygen, fluorine, and chlorine. However, some nonmetals such as carbon and graphite can conduct electricity to some extent, making them useful in electronic devices.

Non-metals can be classified as insulators or semiconductors when it comes to electricity. Insulators are materials that do not conduct electricity well, while semiconductors are materials that conduct electricity better than insulators, but not as well as conductors.

Examples of non-metal insulators include rubber, glass, and plastic. These materials have high resistance to the flow of electric current and are used as electrical insulation in wiring and electronic components.

Semiconductor non-metals include materials such as silicon, germanium, and carbon. They have electrical conductivity that is intermediate between that of a conductor and an insulator. These materials are used in electronic devices such as transistors, integrated circuits, and solar cells

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The proportionality constant for this gas in this solvent and at this temperature is approximately 0.0000233 M/kPa.

To find the proportionality constant for the gas in the solvent and at the given temperature, we need to use Henry's Law, which states that the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid. Mathematically, it is expressed as:

C = k * P

where C is the solubility of the gas (in this case, 0.00290 M), P is the partial pressure of the gas (125 kPa), and k is the proportionality constant that we need to find.

To find the value of k, we can rearrange the equation:

k = C / P

Now, plug in the given values for C and P:

k = 0.00290 M / 125 kPa

Next, divide the solubility by the partial pressure to find the proportionality constant:

k ≈ 0.0000232 M/kPa

Finally, to express the answer with three significant figures, round the value:

k ≈ 0.0000233 M/kPa

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Answer:

Explanation:Balance equation:

2 FeBr3 + 3 Na2S → Fe2S3 + 6 NaBr

The amount of moles is therefore 0.23 mol 0.23 m o l.

molarity x number of litres = 0.2 x (75/1000) = 0.015 mol.

Molarity (M) is the most often used unit of solution concentration and is defined as the amount of solute in moles divided by the volume of solution in litres: M is the mole of solute per litre of solution. A 1.00 molar solution (written 1.00 M) contains 1.00 mole of solute per litre of solution.

The hydrochloric acid solution has a molarity of 3 M. This indicates that 1 L of solution contains exactly 3 moles of HCl. Our sample has a capacity of 50 mL.

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The % acetic acid by mass in the vinegar sample is 5.14%.

The first step is to calculate the mass of the vinegar sample using its density:

Mass of vinegar = Volume of vinegar x Density of vinegar

Mass of vinegar = 5.00 ml x 1.00 g/ml = 5.00 g

Next, we can use the mass of acetic acid in the sample to calculate the percentage of acetic acid by mass:

% Acetic Acid = (Mass of acetic acid / Mass of vinegar) x 100%

% Acetic Acid = (0.2568 g / 5.00 g) x 100%

% Acetic Acid = 5.14%

To solve the problem, we first need to know the mass of the vinegar sample. We are given its volume and density, so we can use the density formula (density = mass / volume) to calculate the mass. Once we have the mass of the vinegar, we can use the mass of acetic acid in the sample (also given) to calculate the percentage of acetic acid by mass using the formula % Acetic Acid = (Mass of acetic acid / Mass of vinegar) x 100%.

This formula calculates the proportion of the mass of the sample that is due to acetic acid. Finally, we multiply the result by 100% to express the answer as a percentage. Therefore, the percentage of acetic acid by mass is 5.14%.

The complete question is

A 5.00 ml sample of vinegar contains 0.2568 g of acetic acid. if the density of vinegar is 1.00 g/ml, calculate the % acetic acid by mass.

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Answer:

14

Explanation:

There are 14 atoms in 2H2SO4. Given - Chemical formula. Solution - The atom and number of atoms are - 2*2 Hydrogen + 1*2 Sulphur + 4*2 Oxygen.Aug 11, 2020