When there is a temperature inversion, you would expect to experience Group of answer choices clouds with extensive vertical development above an inversion aloft. good visibility in the lower levels of the atmosphere and poor visibility above an inversion aloft. an increase in temperature as altitude increases.
Temperature inversion leads to an increase in temperature as altitude increases.
The term temperature inversion refers to a situation in which a layer of warm air lies over a layer of cool air. This is also referred to as thermal inversion. This occurs when the air below to loose heat rapidly.
One of the effects of temperature inversion is reduction in visibility. So, thermal inversion leads to an increase in temperature as altitude increases.
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in an electromagnetic wave, the electric and magnetic fields are oriented such that they are
Answer:
The electric and magnetic fields are oriented such that they are perpendicular to one another and parallel to the direction of wave propagation.
In an electromagnetic wave, the electric field and magnetic field are oriented such that they are perpendicular to each other and perpendicular to the direction of propagation.
What are electromagnetic waves?Electromagnetic radiations are made of electromagnetic waves that are produced when an electric field and magnetic field come in contact with each other. Electromagnetic waves are oscillating electric and magnetic fields.
An electric field is generated by a charged particle and a force is exerted by it on other charged particles. Positive charges are accelerated in the direction of the field and negative charges are accelerated in the opposite direction of the field.
The Magnetic field is generated by a moving charged particle and force is exerted by it on other moving particles. The force is always perpendicular to the direction of their velocity.
The electric field and magnetic fields of EM waves are perpendicular to each other and are also perpendicular to the direction of propagation of waves.
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Anna used a rock to drive a peg into the ground to put up her tent. If the rock applied a 9. 5 N force in 0. 50 s, what is the impulse on the peg? 4. 8 N • s 9. 5 N • s 10 N • s 19 N • s.
Answer:
4.8 N*s
Explanation:
P = F*t
P = Impulse/ momentum
F = force (Newtons)
t = time (seconds)
P = 9.5N*0.5s
P = 4.75 N*s
Hi there!
[tex]\large\boxed{I = 4.8 N}[/tex]
Impulse = Force (N) × Time (s)
We can also express this as:
I = Δp = Ft
Plug in the given values:
I = 9.5(.50) = 4.75 ≈ 4.8 Ns
The energy transferred per unit electric charge in a circuit is .
A current
B charge
C power
D potential difference
- A block of mass 4m can move without friction on a horizontal table. This block is attached to another block of
mass m by a string that passes over a frictionless pulley. If the masses of the string and the pulley are negligible,
what is the magnitude of the acceleration of the descending block?
The magnitude of the acceleration of the descending block is equal to 1.96 m/s².
What is the tension in the string?Tension can be described as a force acting along the length of a rope or a cable, especially a force that comprises by a flexible medium. Tension can be described as an action-reaction pair of forces acting at each end of the length of the medium. Each endpoint carried tension and force from the weight attached.
Given that the block with mass, M₁ = 4m is placed on the horizontal table.
The block with mass, M₂ = m is attached by a string.
The block (M₂) suspended by the string experiences tension (T) in the upward direction and weight in the downward direction.
M₂g - T = M₂a ..............(1)
The block (M₁) placed on the table experienced only one force which is tension (T)
T = M₁ a .....................(2)
From equation (1) and (2):
M₂g - M₁a = M₂a
M₁a + M₂a = M₂g
(M₁ + M₂) a = M₂g
a = M₂g/(M₁ + M₂)
Substitute the value of masses of the blocks:
a = m g /( 4m + m)
a = g/5
a = 1.96 m/s²
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suppose A=3i-2j and B=-i-4j three vectors in xy plane A+B-C =0 what is the answer Ci
Answer:
Ax + Bx = 3 - 1 = 2
Cx = -2
Ay + By = -2 -4 = -6
Cx + Cy = -2 - 6
Then
Ax + Bx - Cx = 2 - (-2) = 0
Ay + By - Cy = -6 - (-6) = 0
C must have the form:
C = -2i - 6j
what is the magnitude of the torque that the axle must apply to prevent the disk from rotating?
The required torque at the axle, is given by the difference between the
moments of the applied forces.
The torque required is 19.62 N·m counterclockwise
Reasons:
The given parameters are;
Mass of the disk, m = 5.0 kg
Location of the axle = Half the radius of the disk
Diameter of the disk, D = 40 cm = 0.4 m
Applied mass, 0.1 m from the axle = 15 kg
Applied mass, 0.3 m from the axle = 10 kg
Required:
Magnitude of torque at the axle that prevent the disk from rotating
Solution:
Torque needed = Clockwise moment - Counterclockwise moment
Clockwise moment = (10 kg × 0.3 m + 5 kg × 0.1 m) × 9.81 m/s² = 34.335 N·m
Counterclockwise moment = 15 kg × 0.1 m × 9.81 m/s² = 14.715 N·m
τ + Counterclockwise moment = Clockwise moment
τ + 14.715 N·m = 34.335 N·m
Torque required, τ = 34.335 N·m - 14.715 N·m = 19.62 N·m
Torque required, τ = 19.62 N·m counterclockwise
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The probable question drawing obtained from a similar question online is attached
1kg red-hot iron is put into 1 L of cool water. Explain in detail what will happen to the temperatures of both objects.
The equilibrium temperature of the iron-water mixture will be greater than the initial temperature of the cold water but less than the initial temperature of the hot iron.
According to the principle of conservation of energy, the heat lost by the red-hot iron is equal to heat absorbed by the cold water.
[tex]Q_{I} = Q_{w}\\\\m_IC_I(t_I - T) = m_wC_w (T-t_w)[/tex]
where;
T is the equilibrium temperatureFrom the equation given above, we can conclude that the equilibrium temperature of the iron-water mixture will be greater than the initial temperature of the cold water but less than the initial temperature of the hot iron.
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When riding your bike, you come up to a small child who jumps in front of you. You slam on the brakes, and your bike comes to a sliding stop. Which force greatly increases when you lock the brakes and slide
Answer: friction :)
Explanation:
I took the test and got 100%
Un automóvil aumenta su rapidez cuando está en una pista circular. ¿Tieneaceleración centrípeta? ¿Tiene aceleración angular? Explique.
Explanation:
espero que re ayude esta información para tu pregunta
What might be an example of newtons second law of motion
Answer:
Pushing a car and a truck
Explanation:
The velocity (in m/s) of a free-falling object as a function of the height from which it is dropped is
v = 25 h. So, ignoring the air resistance, at what height should you drop a watermelon if you want
it to hit the ground at 50 m/s?
Answer:
Falling objects form an interesting class of motion problems. For example, we can estimate the depth of a vertical mine shaft by dropping a rock into it and listening for the rock to hit the bottom. By applying the kinematics developed so far to falling objects, we can examine some interesting situations and learn much about gravity in the process.
The most remarkable and unexpected fact about falling objects is that, if air resistance and friction are negligible, then in a given location all objects fall toward the center of Earth with the same constant acceleration, independent of their mass. This experimentally determined fact is unexpected because we are so accustomed to the effects of air resistance and friction that we expect light objects to fall slower than heavy ones.
A hammer and a feather will fall with the same constant acceleration if air resistance is considered negligible. This is a general characteristic of gravity not unique to Earth, as astronaut David R. Scott demonstrated on the Moon in 1971, where the acceleration due to gravity is only 1.67 m/s^2.
In the real world, air resistance can cause a lighter object to fall slower than a heavier object of the same size. A tennis ball will reach the ground after a hard baseball is dropped at the same time. (It might be difficult to observe the difference if the height is not large.) Air resistance opposes the motion of an object through the air, while friction between objects, such as between clothes and a laundry chute or between a stone and a pool into which it is dropped, also opposes motion between them. For the ideal situations of these first few chapters, an object falling without air resistance or friction is defined to be in free-fall.
Hope this helps, have a nice day/night! :D
can someone pls help me in this q
Answer: B
Explanation:
for what angle of projetion is the range is maximum
Answer:
46 degrees
Explanation:
A change of state, such as boiling, is an example of a chemical change. True or False?
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
The given statement is false, change in state is considered as a physical chance because the state can be regained by using physical methods ~
for example boiling causes water to evaporate (converted into gaseous state) , but it can gain the liquid form again by Condensation ~
Answer:
False
Explanation:
This is False because boiling is not included in the chemical category.
Boiling is a PHYSICAL change, a chemical change is one or more substances combine or break apart to form new substances.
To learn more, read from the passage above the questions!
Hope this helped!!
Please help !!!
Will give the brainliest..
Please answer correctly..
Explanation:
hope this is right!!!!!!!!!!!!!
1. a. Electron 1 -1
b. Proton 2000 +1
c. Neutron 2000 0
2. a. An uncharged nucleon is neutron. It is a chargeless subatomic particle.
b. The particle with the least mass is electron. The mass of an electron is so small that it is considered to be negligible while calculating the atomic mass of an element.
c. The particle with the same mass as a neutron is proton. However if we see the absolute mass of neutron and proton then it is seen that neutron has a greater mass than proton.
d. The particle with the same amount of charge as an electron is proton. Note that the amount of charge is only same. Electron is negatively charged while proton is positively charged.
e. A particle that is negatively charge is electron. The relative charge of electron is -1.
Hope you could understand.
If you have any query, feel free to ask.
I would like to know if it would be m/s² or just m/s and explain why. thanks
It will be
[tex] {m/s}^{2} [/tex]
I am just explaining with the units only, because you want to know the accurate unit.
[tex] \frac{m/s}{s} \\ = \frac{m}{s} \times \frac{1}{s} \\ = \frac{m}{s \times s} \\ = \frac{m}{ {s}^{2} } \\ = {m/s}^{2} [/tex]
Hope you understood.
Do comment if you have any query.
Find the mass of the second object if the force of gravity between the two objects is 0.128N. The mass of the first object is 1300 kg and the 2 objects are 0.23 m apart.
Considering the Law of Universal Gravitation, the mass of the second object is 78090.19 kg.
The Law of Universal Gravitation is a law that states that bodies, by the simple fact of having mass, experience a force of attraction towards other bodies with mass, called gravitational force.
This law establishes that every particle attracts any other particle with a force directly proportional to the product of the masses of both and inversely proportional to the square of the distance that separates them:
[tex]F=G\frac{m1m2}{r^{2} }[/tex]
where m1 and m2 are their masses; r the distance between them and G a universal constant that is called the constant of gravitation.
In this case, you know:
F= 0.128 NG=6.67× 10⁻¹¹ Nm²/kg²m1= 1300 kgm2= ?r= 0.23 mReplacing:
[tex]0.128 N=6.67x10^{-11}\frac{Nm^{2} }{kg^{2} } \frac{1300 kg m2}{(0.23 m)^{2} }[/tex]
Solving:
[tex]0.128 N=1.639x10^{-6}\frac{N}{kg }x m2[/tex]
m2=0.128 N ÷ 1.639×10⁻⁶ [tex]\frac{N}{kg}[/tex]
m2=78090.19 kg
In summary, the mass of the second object is 78090.19 kg.
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https://brainly.com/question/858421?referrer=searchResultshttps://brainly.com/question/2347945?referrer=searchResultsCan you achieve Light Speed with a Perpertual Motion Machine containing High Energy?
Answer:
Yes
Explanation:
Perpetual Motion Machine (PMM) which can be applied to produce electricity, may be an alternative solution for the problem the world is facing today. The machine is designed to generate power from repulsive forces of permanent magnet without utilizing external sources.
A 4.6 kg bucket of water is raised from a well by a rope. The acceleration of gravity is 9.8 m/s 2 . If the upward acceleration of the bucket is 3 m/s 2 , find the force exerted by the rope on the bucket. Use g
Hi there!
If we sum the forces acting on the bucket:
∑F = T (upward) - Mg (downward)
Thus:
ma = T - mg
We can rearrange for T:
ma + mg = T
Plug in the given values:
4.6(3 + 9.8) = T = 58.88 N
What is its time interval between the release of the ball and the time it reaches its maximum height? Its initial vertical speed is 9 m/s and the acceleration of gravity is 9.8 m/s 2 . Neglect air resistance.
Answer:
The time to reach max height is h = 1/2 g t^2
The time to fall is the same as that for an equivalent rise
m g h = 1/2 m v^2 KE vs PE
Here: (Vf - VI) / g = t = -9 / -9.8 = .92 s
How long does it take a plane, traveling at a constant speed of 200 m/s, to fly once around a circle whose radius is 2750 m
Answer:
2000 and 156300
jade it jawaban nya
Any vector can be expressed as the sum of two components, usually
referred to as what?
Two vectors can be added together to determine the result (or resultant). ... computing the vector sum of all the individual forces acting upon that object.
i hope u understand
A car traveling due north at 60 km/hr increased its velocity to 80 m/s due south in 20 seconds. Draw i) speed against time graph, ii) acceleration against time graph.
The slope of the graph is acceleration of the car with a value of 3.2 m/s².
The given parameters;
initial velocity of the car, u = 60 km/hrfinal velocity of the car, v = 80 m/stime of motion of the car, t = 20 sThe initial velocity of the car in m/s is calculated as follows;
[tex]60 \ \frac{km}{hr} \times \frac{1 \ hr}{3600 \ s} \times \frac{1000 \ m}{1 \ km} = 16.67 \ m/s[/tex]
The acceleration of the car is calculated as follows;
[tex]a = \frac{v- u}{t} \\\\a = \frac{80 - 16.67 }{20} \\\\a = 3.2 \ m/s^2[/tex]
The graph of the velocity against time and acceleration against time is in the image uploaded.
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Please help me calculate this question along with the equation
Hi there!
We can use the following:
U (Gravitational Potential Energy) = mgh
m = mass of object (kg)
g = acceleration due to gravity OR gravitational field strength
h = height, or displacement (m)
ΔU = Uf - Ui, so:
Uf = 3 × 1.5 × 10 = 45 J
Ui = 3 × 0 × 10 = 0
ΔU = Uf - Ui = 45 - 0 = 45 J
Find the acceleration if the force is 10 N and the mass is 5000 g.
Answer:
If the force is 10N and mass is 5000G, then a=2m/s2
Explanation:
F=10N
m=5000
g=5kg
a=10N/ 5kg
and finally; a= 2m/s2
The Maximum and Minimum resultant of two forces are 35N and 51N. What is the possible Value of the two forces ?
hplhevsdvakxjb1zonsvaka shdv
If a 5.00 kg box slides down a ramp inclined at 60.0° above the horizontal, what is the
acceleration of the box
Answer:
A 70 kg box is slid along the floor by a 400 n force. The coefficient of friction between the box and the floor is 0. 50 when the box is sliding
the temperature of a room is 77°F what would be the temperature in Celsius scale
Formulas change from F to degree C : C = ( F - 32 )/1.8
so we have (77-32)/1.8 = 25 oC
ok done. Thank to me :>
Answer: The answer is C. 298 K
Explanation:
stacie, who has a mass of 45 kg, starts down a slide that is inclined at an angle of 45 degree with the horizontal. If the coefficient of kinetic friction between stacie's shorts and the slide is 0.25, what is her acceleration
The acceleration of the mass sliding along the horizontal surface is 5.2 m/s².
The given parameters;
mass of the crate, m = 45 kgangle, = 45 degreescoefficient of kinetic friction, = 0.25The acceleration of the mass is calculated by determining the net force on the mass as shown below;
[tex]\Sigma F_{net} = ma\\\\Wsin\theta - F_k = ma\\\\mg sin\theta - \mu_k F_n = ma\\\\mg sin\theta - \mu_k mg\ cos\theta = ma\\\\g sin\theta - \mu_k g\ cos\theta = a\\\\g(sin\theta - \mu_k \ cos\theta ) = a\\\\9.8(sin\ 45 \ - \ 0.25\times cos \ 45) = a\\\\9.8(0.53) = a\\\\5.2 \ m/s^2 = a[/tex]
Thus, the acceleration of the mass sliding along the horizontal surface is 5.2 m/s².
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