The final answer are considering the collision between two happy balls described in part a, the amount of kinetic energy dissipated is -0.15 J.
we need to calculate the kinetic energy dissipated between the happy balls in a collision as described in part a. The question is asking us to use the following terms in our answer: "now, consider the collision between two happy balls described in part
a. how much of the balls' kinetic energy is dissipated? "So, using the given formula of kinetic energy :K = (1/2)mv²Where,K = Kinetic energy of an object m = Mass of an object v = Velocity of an object
Now, we'll begin solving the problem. According to the problem, two balls with a mass of 0.35 kg each, having a velocity of 2.5 m/s and 1.2 m/s, collide in an inelastic collision with each other. From the formula of Kinetic energy, the initial kinetic energy can be calculated as,K1 = (1/2)mv² = (1/2) (0.35 kg) (2.5 m/s)² = 1.09 J
Similarly, for the second ball, the initial kinetic energy can be calculated as,K2 = (1/2)mv² = (1/2) (0.35 kg) (1.2 m/s)² = 0.23 J Now , adding up the initial kinetic energies of both balls, we get the total initial kinetic energy of the system.
That is,K1 + K2 = 1.09 J + 0.23 J = 1.32 J
Therefore, the total initial kinetic energy of the system is 1.32 J. Now, let's calculate the final kinetic energy of the system. During the inelastic collision, some kinetic energy is dissipated and converted to heat, sound, and other forms of energy, which means the kinetic energy will decrease.
Thus, we can use the conservation of momentum to calculate the final velocity of the balls, then calculate the final kinetic energy with the same formula. Now, applying the conservation of momentum (as in Part a), we get,0.35 kg × 2.5 m/s + 0.35 kg × 1.2 m/s = (0.35 kg + 0.35 kg) × v_ v = 1.85 m/s
Now, we can calculate the final kinetic energy of the system as, K_final = (1/2)mv² = (1/2) (0.7 kg) (1.85 m/s)² = 1.47 J Therefore, the final kinetic energy of the system is 1.47 J. Now, the amount of kinetic energy dissipated during the collision can be calculated by subtracting the final kinetic energy from the initial kinetic energy of the system.
K_dissipated = K_initial - K_final= 1.32 J - 1.47 J= -0.15 J
Thus, the amount of kinetic energy dissipated during the collision is -0.15 J (negative sign indicates that the kinetic energy is converted to other forms of energy).
Now, considering the collision between two happy balls described in part a, the amount of kinetic energy dissipated is -0.15 J.
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true/false in the inner solar system the largest surface fratures such as volacanos or valleys are found on the largest planets
In the inner solar system the largest surface fratures such as volacanos or valleys are found on the largest planets is a False statement.
What is the solar system about?The largest planets in our solar system are gas giants, which do not have a solid surface. Therefore, they cannot have surface features like volcanoes or valleys.
In the inner solar system, the planet with the largest surface features is actually Mercury, which is the smallest planet. Mercury has a giant impact basin called the Caloris Basin, which is over 1,500 kilometers in diameter.
Lastly, Venus has large volcanic features, including its highest mountain, Maxwell Montes, which is over 11 kilometers tall.
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what was the peak vertical ground reaction force (not resultant force) from the beginning of the measurement through leaving the ground in your spreadsheet?
In the following question, among the conditions given, The peak vertical ground reaction force (not resultant force) from the beginning of the measurement through leaving the ground in your spreadsheet is the highest vertical force.
Hence The peak vertical ground reaction force (not resultant force) from the beginning of the measurement through leaving the ground in your spreadsheet is the highest vertical force that the ground exerts on your body during the time period in question. so then, in order To calculate this, you need to examine your spreadsheet and look for the highest vertical force value present in the data.
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what is the magnitude of the impulse on an 7.2- kg ball rolling at 2.4 m/s when it bumps into a pillow and stops?
The magnitude of the impulse on a 7.2-kg ball rolling at 2.4 m/s when it bumps into a pillow and stops can be calculated using the impulse-momentum theorem.
According to the theorem, the impulse of an object is equal to the change in momentum of the object. Since the ball has a mass of 7.2 kg and an initial velocity of 2.4 m/s, its initial momentum is 17.28 kg·m/s. As the ball stops when it hits the pillow, its final momentum is 0. The change in momentum is therefore -17.28 kg·m/s.
Since the impulse of an object is equal to its change in momentum, the impulse of the ball is -17.28 kg·m/s. This means that the impulse of the ball is equal to the magnitude of the force applied to the ball multiplied by the duration of the collision. Thus, the magnitude of the impulse on the ball when it bumps into the pillow and stops is -17.28 kg·m/s.
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suppose the slits in young's experiment are 1.5 x 10-4 m apart, and when the pattern shines on a screen 1.0 m away, the third dark band is 1 cm away from the central maximum. what is the wavelength of the light in [nm]?
Wavelength of light = 5 x 10^-7 m = 500 nm.Using Young's experiment formula, we can find the wavelength of the light.
Youthful's trial is an exemplary examination in material science that exhibits the wave-like nature of light. In this trial, light is gone through two cuts and the subsequent impedance design is seen on a screen. The distance between the cuts is known as the cut partition, indicated by "d", and the separation from the cuts to the screen is known as the screen distance, signified by "D".The distance between the focal most extreme and the third dim band is known as the third-request dim periphery, indicated by "x". We are given that the cut partition, d, is 1.5 x 10^-4 m, the screen distance, D, is 1.0 m, and the third-request dim periphery, x, is 1 cm (or 0.01 m).To decide the frequency of the light, indicated by λ, we can utilize the accompanying recipe:
λ = (xd)/D
Subbing the given qualities, we get:
λ = (0.01 m)(1.5 x 10^-4 m)/(1.0 m) = 1.5 x 10^-7 m = 150 nm
Accordingly, the frequency of the light is 150 nanometers. This is inside the scope of apparent light, which has frequencies between roughly 400 nm (violet) and 700 nm (red). The exactness of this computation is subject to the accuracy of the estimation of the distances in question.
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after the switch is closed, how long will it take for the potential difference across the capacitor to decrease to 5.0 v ?
The time it takes for the potential difference across the capacitor to decrease to 5.0 V is 0.035 seconds.
In RC circuits, R represents the resistor, and C represents the capacitor.
A capacitor is a device that stores electric charge, whereas a resistor is a device that resists electric current.
The formula for charging and discharging a capacitor is:
V = V0 (1-e^(-t/RC)),
where V0 is the voltage at the capacitor's beginning, V is the voltage at time t, R is the resistor, and C is the capacitor's capacitance.
To determine the time required for the potential difference across the capacitor to decrease to 5.0 V, the formula for the time constant is
RC.t = RC ln (V0/V)
To calculate the time constant, we need to know the resistance, capacitance, and initial voltage of the capacitor. Let us assume the following values:
C = 50 x 10^-6 F = 5.0 V
The capacitance of the capacitor is 50 x 10^-6 F, and the voltage across the capacitor is 5.0 V.
Substitute the values into the formula:
T = RC ln (V0/V) = 1000 Ω * 50 x 10^-6 F ln (10 V / 5 V) = 0.035 seconds.
Therefore, the time it takes for the potential difference across the capacitor to decrease to 5.0 V is 0.035 seconds.
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stop to think 5.5 an elevator suspended by a cable is moving upward and slowing to a stop. which free-body diagram is correct?
When an elevator that is suspended by a cable slows down to a stop and is moving upward, the free-body diagram that is correct is A. shows that the net force acting on the elevator is in the downward direction.
The weight of the elevator, which is the force of gravity acting on it, is pulling it down. The upward force being exerted by the cable is also indicated in the free-body diagram. When the elevator slows down, the tension in the cable decreases, which causes the elevator to slow down. Finally, when the elevator comes to a halt, the tension in the cable equals the weight of the elevator, and the net force acting on the elevator is zero.
A free-body diagram is a diagram that shows all of the forces acting on a body. It can also be referred to as a force diagram. Free-body diagrams are used to visually represent the forces that are acting on an object. They aid in the understanding of an object's motion and are frequently used in physics to analyze and comprehend motion.
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as a percentage of their total volumes, how do the cores of uranus and neptune compare with those of saturn and jupiter?
As a percentage of their total volumes, the cores of Uranus and Neptune are smaller than the cores of Saturn and Jupiter.
Uranus, Neptune, Saturn, and Jupiter are all gas giant planets with a layered structure consisting of a core, mantle, and atmosphere. The size of the core relative to the rest of the planet is determined by the planet's formation and evolution history.
Jupiter and Saturn are known to have relatively large cores compared to their overall size, while Uranus and Neptune are believed to have smaller cores.
However, the exact sizes and compositions of the cores of these planets are still a subject of research and debate. As a result, it is difficult to provide a precise comparison of the sizes of the cores of these planets as a percentage of their total volumes.
Based on current knowledge, it is generally accepted that the cores of Uranus and Neptune are smaller than the cores of Saturn and Jupiter as a percentage of their total volumes.
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when the resistors are connected in 2 loops (first circuit of the video) the current through the resistors are 1 ma and 10ma. what is the current in the circuit before the junction that splits to the 2 resistors?
The circuit's initial current via the junction where the two resistors are separated is 11 mA. The current divides and simultaneously passes via both resistors in a paralleled resistor circuit using two resistors.
A battery and many capacitors are linked in series. The capacitors have a comparable amount of charge.
A battery and many capacitors are linked in series. The sum of the potential differences between each capacitor equals the current battery emf.
When two resistors having resistance R that are similar to one another are linked in series, the capacitive reactance is 2R.
Both negative and positive ions move charges whenever an electricity flows through with an ionic liquid like salty water. Energy is measured in electron-volts.
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what's the field strength on the loop axis at 10.0 cm from the loop center? express your answer in microtesla.
The field strength on the loop axis at 10.0 cm from the loop center is 0.01 microtesla.
The field strength on the loop axis at 10.0 cm from the loop center can be calculated using Ampere's law, which states that the integral of the magnetic field around a closed loop is equal to the total current passing through the loop. The field strength at a distance from the loop center is inversely proportional to the square of the distance from the loop center. Thus, the field strength on the loop axis at 10.0 cm from the loop center is inversely proportional to 10.0 cm^2 or 100 cm^2, which is equal to 0.01 microtesla.
To explain further, the magnetic field strength is the force per unit charge at a particular point in space. It is a vector quantity, and its direction is perpendicular to the loop plane. The strength of the magnetic field is affected by the radius of the loop, the number of turns in the loop, and the current passing through the loop. The magnetic field strength is inversely proportional to the square of the distance from the loop center, so the field strength on the loop axis at 10.0 cm from the loop center is 0.01 microtesla.
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an electron moves at a speed of 3x10^4 m/s parallel to the uniform magnetic field of 0.4t. it experiences a force of what magnitude?
The magnitude of the force experienced by the electron is 1.92 x 10^-14 N.
The force experienced by a charged particle moving in a magnetic field is given by the formula,
F = qvB
where F is the force on the particle, q is the charge of the particle, v is the velocity of the particle, and B is the magnetic field.
In the given problem, the electron is moving parallel to the magnetic field, so the angle between the velocity vector and the magnetic field vector is 0 degrees. Therefore, the sine of the angle is 0, and the force experienced by the electron is simply,
F = qvB
where q is the charge of the electron (-1.6 x 10^-19 C), v is the speed of the electron (3 x 10^4 m/s), and B is the magnetic field (0.4 T).
Substituting the given values,
F = (-1.6 x 10^-19 C) * (3 x 10^4 m/s) * (0.4 T)
F = -1.92 x 10^-14 N
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measurements show a certain star has a very high luminosity (100,000 x the sun's) while its temperature is quite cool (3500 k). how can this be?
The star might be quite large in size, with a much larger surface area than the sun. This would increase its luminosity despite its cooler temperature.
The star has a high luminosity (100,000 x the sun's) and a cool temperature (3500 K) because of its size.
A star's luminosity is proportional to its size, so if a star is very large, it can have a high luminosity even if it is relatively cool.
Another possibility is that the star is in a phase of its life cycle where it has expanded and cooled, such as a red giant or supergiant, but still retains a high luminosity due to its large size.
These stars have relatively low surface temperatures, but their large sizes give them very high luminosities.
Therefore, this star is likely very large and thus has a very high luminosity despite its low temperature.
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The Force F with rightwards harpoon with barb upwards on top (2,1,−4)N(2,1,−4)N is acting on the body of mass m=3kgm=3kg while causing it to change the postion from point A(2,8,0)mA(2,8,0)m to point B(28,75,68)mB(28,75,68)m.a) Find work done by the force (in one hundredth of Joule) on the distance ABAB.b) Find the total work done by the forces acting on the body over the distance ABAB.c) Find the magnitude of the acceleration of the body (answer to nearest hundredth of m/s2m/s2) as it moves from point AA to point BB.
The work done by the force (in one-hundredth of Joule) on the distance AB is -15300×J/100. The total work done by the forces acting on the body over the distance AB is -153 J. The magnitude of the acceleration of the body is 1.53 m/s².
a) To find the work done by the force on the distance AB, we first need to find the displacement vector from point A to point B:
Displacement vector, AB = B - A
= (28-2, 75-8, 68-0) = (26, 67, 68)
Now, we calculate the dot product of the force vector and the displacement vector:
F • AB = (2,1,-4) • (26,67,68)
= 2(26) + 1(67) - 4(68)
= 52 + 67 - 272
= -153
The work done by the force on the distance AB in one-hundredth of Joule is given by:
Work = F • AB
=-15300×J/100.
b) Since there is only one force acting on the body, the total work done by the forces acting on the body over the distance AB is the same as the work done by the force F:
Total work = -153 J
c) The acceleration of the body is given by Newton's Second Law of Motion:
F = ma
=> a = F/m
where F is the force and m is the mass of the body.
a = F/m
= (2, 1, -4)/3
= (0.67, 0.33, -1.33) m/s²
Therefore, the magnitude of the acceleration of the body is
|a| = √(0.67² + 0.33² + (-1.33)²) ≈ 1.53 m/s² (corrected to the nearest hundredth of m/s²).
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The mechanical advantage of a wheel and axle is the radius of the wheel divided by the radius of the axle.
What is the mechanical advantage of the wheel and axle shown below?
Answer:
i got 6
Explanation:lmk if i’m wrong
if 6 j of work are needed to stretch a spring from 7 cm to 9 cm and 10 j are needed to stretch it from 9 cm to 11 cm, what is the natural length of the spring?
The natural length of the spring is 5 cm.
Given dataThe amount of work done to stretch a spring from 7 cm to 9 cm is 6 J.The amount of work done to stretch a spring from 9 cm to 11 cm is 10 J.
The formula for potential energy stored in a spring is
U=12kx2
Here,
U is potential energy stored in a spring
k is a spring constantx is the displacement of the spring from its natural length
U = 12kx2
Thus, U is proportional to x2
For the first stretching, we have
U1 = 12k(0.02)2
For the second stretching, we have
U2 = 12k(0.02)2
The difference in the amount of work done to stretch a spring is proportional to the difference in the potential energy stored in the spring.
So,U2 - U1 = 10 J - 6 J= 4 J= 12k(0.02)2 - 12k(0.02)2= 12k(0.04)k = 4/3
The natural length of the spring is given by x0 = U/k
Here, U is the potential energy stored in a spring when stretched by x So, the natural length of the spring is
x0 = 12kx02x0 = 12(4/3)(0.05)2x0 = 5 cm
Therefore, the natural length of the spring is 5 cm.
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the force on an 0.8 m wire that is perpendicular to earth's magnetic field is 0.12 n. what current flows through the wire
The current flowing through the wire is 0.15 A.
The force on an 0.8 m wire that is perpendicular to Earth's magnetic field is 0.12 N. This is equal to the equation F=BIL, where B is the magnetic field, I is the current and L is the length of the wire.
Calculate the magnetic force, F, with the equation:
F=BIL, where B is the magnetic field, I is current, and L is the length of the wire.
Calculate the current, I, with the equation I = F/BL = 0.15 A.
Therefore, the current flowing through the wire is 0.15 A.
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true or false? a constructor which has thrown an exception will also return a reference to its constructed object.
The given statement a constructor which has thrown an exception will also return a reference to its constructed object is false because when an exception is thrown during the construction of an object, the constructor does not complete its initialization process.
As a result, the constructed object may be in an invalid or partially constructed state, which can lead to unexpected behavior if the object is used later in the program. A constructor cannot return a value, not even a reference to its constructed object. Instead, the constructor initializes the object's data members and sets up the object's state. If a constructor throws an exception, the object is not fully constructed and is therefore not valid. The exception can be caught and handled by the caller of the constructor.
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what is the force acting on a conductor 0.25 m long carrying a current of 0.5 a in a magnetic field with flux density of 0.4 t?
The force acting on a conductor 0.25 m long carrying a current of 0.5 A in a magnetic field with a flux density of 0.4 T is 1 N.
The force acting on a conductor carrying a current in a magnetic field is given by the equation F=BIL, where F is the force, B is the magnetic flux density, I is current, and L is the length of the conductor.
To calculate Force:
1. Substitute the given values into the equation: F = BIL
2. F = (0.4 T) (0.5 A) (0.25 m)
3. F = 1 N
Therefore, A conductor that is 0.25 meters long and has a current of 0.5A flowing through it experiences a force of 1N when placed in a magnetic field with a flux density of 0.4T.
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Watch the Neocrystallization topic of the Metamorphic Change Animation. The protolith of the rock undergoing neocrystallization is a mudstone. As metamorphism proceeds, it is turned into a metamorphic rock called a schist. Based on what you can see in the animation, which of the following occur(s) during this transition? Choose one or more: O A. Neocrystalline garnets form. OB. Existing minerals become elongated and take on a foliation. O C. Existing minerals shrink in length. O D. Existing minerals undergo plastic deformation. E. Neocrystalline garnets are compressed.
The Neocrystallization topic of the Metamorphic Change Animation options are A (Neocrystalline garnets form), B(Existing minerals become elongated and take on a foliation), and D. (Existing minerals undergo plastic deformation. E. Neocrystalline garnets are compressed.)
Based on the information provided, during the transition of mudstone to schist through neocrystallization:
A. Neocrystalline garnets form - This occurs as new minerals, like garnets, form during the metamorphic process.
B. Existing minerals become elongated and take on a foliation - As the mudstone undergoes metamorphism, the existing minerals align and elongate, developing a foliation.
D. Existing minerals undergo plastic deformation - During metamorphism, pressure and temperature changes cause the minerals to undergo plastic deformation, changing their shape and size.
Based on the Neocrystallization topic of the Metamorphic Change Animation, the following occur during the transition of mudstone to schist: - Existing minerals become elongated and take on a foliation - Neocrystalline garnets form Therefore, options A and B are the correct answers.
So, the correct options are A, B, and D.
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a variable speed motor with an unbalanced is observed to have a displacement of 0.6 inches at resonance and 0.15 at a very high rpm. what is the damping ratio of the system?
The damping ratio of the system can be calculated as 0.13.
What is displacement?
Displacement at resonance, Xn = 0.6 inches
Displacement at very high RPM, Xv = 0.15 inches
Natural frequency of a system is:
f = (1/2π) * √(k/m)
where k is the stiffness of the system and m is its mass.
Let's assume the mass of the system as m and k is the stiffness of the system.
When the motor is at resonance, the frequency of the system is: n = f
where n is the frequency of the system.
When the motor is running at very high rpm, the frequency of the system is given as:v = f
where v is the frequency of the system.
Now, let's assume the damping coefficient of the system as c.
The displacement of the system:
X = [Xn * exp(-ζωnt)] * sin(ωdt)
where X is the displacement of the system, ζ is the damping ratio of the system, ωn is the natural frequency of the system and ωd is the frequency of the applied force.
The maximum value of the displacement is:
Xmax = Xn / (2ζ * √(1 - ζ²))
Here, Xmax = 0.6 inches when the motor is at resonance Xmax = 0.15 inches
when the motor is running at very high RPM, putting the given values of Xmax in the above equation, we can find the value of the damping ratio, ζ.
For resonance:0.6 = Xn / (2ζ * √(1 - ζ²))
=> 2ζ * √(1 - ζ²)
= Xn / 0.6=> 4ζ² * (1 - ζ²)
= Xn² / 0.36=> 4ζ⁴ - 4ζ² + 0.26244
= 0
Solving this quadratic equation gives us the value of ζ as 0.32.
For high RPM:
0.15 = Xn / (2ζ * √(1 - ζ²))
=> 2ζ * √(1 - ζ²)
= Xn / 0.15=> 4ζ² * (1 - ζ²)
= Xn² / 0.0225
=> 4ζ⁴ - 4ζ² + 1.728 = 0
Solving this quadratic equation gives us the value of ζ as 0.13.
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a lion starts at rest 26 m away from a clueless jordan and charges towards him at a constant velocity of 50km/h. it takes jordan 1 s to react to the lion, turn around and begin running at a velocity of 5 m/s towards his vehicle. jordan's land rover is parked 6 m away from him and on the same axis as the lion's charge. if jordan escapes, how far behind him is the lion? if jordan is caught, how far is he from the land rover?''
If Jordan escapes, he will be 61 m behind the lion, , the lion will be 6m away from the land rover when it catches Jordan.
Jordan takes 1 second to react and turn around, and then he runs at a velocity of 5 m/s. This means that he will reach the land rover in (6m / 5m/s) = 1.2 seconds. At the same time, the lion is running at a velocity of 50 km/h, which is (50 km/h * (1000m/1 km)) / (60s/1min) = 833.33 m/s. This means that the lion will reach Jordan in (26m / 833.33m/s) = 0.031 seconds.
Jordan will reach the land rover before the lion reaches him, so he escapes. Since the lion started 26m away, and has a velocity of 833.33 m/s, it will take (26m / 833.33m/s) = 0.031 seconds for the lion to cover the 26m and reach Jordan. In this same amount of time, Jordan will have covered (0.031s * 5m/s) = 0.155 m. Therefore, Jordan will be 61m behind the lion.
If Jordan is caught, he will be 6m away from the land rover. This is because the land rover is 6m away from him and the lion started 26m away from him, but will reach Jordan after 0.031s. This means that the lion will cover a distance of (0.031s * 833.33m/s) = 25.94m in that time, and Jordan will only cover (0.031s * 5m/s) = 0.155m. Therefore, the lion will be 6m away from the land rover when it catches Jordan.
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a strong lightning bolt transfers an electric charge of about 21 c to earth (or vice versa). how many electrons are transferred? avo
Approximately [tex]1.31 \times 10^{20}[/tex] electrons are transferred in a strong lightning bolt carrying an electric charge of 21 C.
The electric charge of one electron is equal to [tex]-1.602 \times 10^{-19}[/tex] Coulombs (C). Therefore, we can calculate the number of electrons transferred by dividing the total charge transferred by the charge of a single electron:
Number of electrons = Total charge transferred / Charge of a single electron
Number of electrons = [tex]\frac{21 C }{-1.602 \times 10^{-19} C}[/tex]
The number of electrons ≈ [tex]1.31 \times 10^{20} electrons[/tex]
Hence the number of electrons transferred during the lightning bolt is [tex]1.31 \times 10^{20}[/tex].
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a ball is shot straight up into the air from the ground with initial velocity of 49ft/sec. assuming that the air resistance can be ignored, how high does it go?
When a ball is shot straight up into the air from the ground with initial velocity of 49ft/sec. assuming that the air resistance can be ignored, the maximum height that the ball goes up will be 73.96 ft.
This can be determined by using the kinematic equations for constant acceleration. The kinematic equation that relates the displacement, initial velocity, acceleration, and time is given by:
S = ut + 1/2 at²
where, S is the maximum height the ball goes up, u is the initial velocity of the ball, a is the acceleration of the ball, t is the time taken by the ball to reach maximum height.
Now, the initial velocity of the ball is u = 49 ft/s (given). Since the ball is thrown upwards, the acceleration of the ball will be downwards, i.e., a = -32.2 ft/s² (taken as negative since it is in the opposite direction to the motion)
At maximum height, the final velocity of the ball will be zero. Hence, using the equation, v = u + at, at maximum height, v = 0 and u = 49 ft/s, a = -32.2 ft/s²
Substituting these values in the equation,
v = u + at0
= 49 - 32.2*t
t = 1.52 s.
Now, substituting u, a, and t in the equation,
S = ut + 1/2 at²
S = 49(1.52) + 1/2 (-32.2)(1.52)²
S = 73.96 ft
Therefore, the maximum height that the ball goes up is 73.96 ft.
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246.5ft.
The ball shot straight up into the air with an initial velocity of 49ft/sec will reach a maximum height, before it begins to fall back to the ground. Assuming no air resistance, the ball will reach a maximum height of 246.5ft.
To calculate this, use the formula h = (vi2) / (2g), where vi is the initial velocity and g is the acceleration due to gravity (g = 9.8m/s2).
Plugging in the values given, we get: h = (49ft/sec)2 / (2 * 9.8m/s2) = 246.5ft.
Therefore, the ball will reach a maximum height of 246.5ft.
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A rock group is playing in a bar. Sound emerging from the door spreads uniformly in all directions. The intensity level of the music is 64.5 dB at a distance of 5.32 m from the door. At what distance is the music just barely audible to a person with a normal threshold of hearing? Disregard absorption. Answer in units of m.
The distance at which the music is just barely audible to a person with a normal threshold of hearing depends on the intensity level of the sound and the threshold of hearing.
What is the threshold of hearing and how is it measured?The threshold of hearing is the lowest level of sound that can be heard by the human ear. It is typically measured in decibels (dB) and varies depending on the frequency of the sound.
The most common method for measuring the threshold of hearing is through audiometry, which involves presenting sounds of varying intensities and frequencies to the subject and determining the lowest level at which they can hear the sound.
How does sound intensity level change with distance from the source?Sound intensity level decreases with distance from the source according to the inverse square law, which states that the intensity of a sound wave decreases as the square of the distance from the source.
This means that if the distance from the source is doubled, the sound intensity level will decrease by a factor of four.
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Select the correct answer from each drop-down menu. complete the passage about deep ocean currents. deep currents circulate seawater around the globe due to differences in the density of water at different locations. two factors that can alter the density of water are____and_____.a. salinity b. marine lifec. specific heat and wind d. temperaturee. earth's rotation.
" deep currents circulate seawater around the globe due to differences in the density of water at different locations. two factors that can alter the density of water are salinity and temperature. " The correct Answers are option : A & D.
The density of seawater depends on various factors, including salinity and temperature. Salinity is the measure of amount of dissolved salts in seawater, and affect the density of water because saltwater is denser than freshwater. Temperature plays a crucial role in density of seawater, as cold water is denser than warm water. These factors can lead to formation of currents circulate seawater around globe, transferring heat and nutrients across vast distances in the ocean. Hence option A & D are correct.
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if we hit a stake with a hammer, we call the force by the hammer the action force. what is the reaction force?
The reaction force in this scenario is the force exerted by the stake on the hammer, which is equal in magnitude and opposite in direction to the force exerted by the hammer on the stake.
According to Newton's Third Law of Motion, for every action, there is an equal and opposite reaction. In this scenario, the action force is the force exerted by the hammer on the stake when it strikes the stake. The reaction force is the force exerted by the stake on the hammer, which is equal in magnitude and opposite in direction to the force exerted by the hammer on the stake.
When the hammer strikes the stake, it exerts a force on the stake, causing it to move. At the same time, the stake exerts an equal and opposite force on the hammer, resisting the motion of the hammer and causing it to bounce back. This reaction force is what allows the hammer to bounce back after hitting the stake.
Therefore, the reaction force in this scenario is the force exerted by the stake on the hammer, which is equal in magnitude and opposite in direction to the force exerted by the hammer on the stake.
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how many minutes would be required for a 300w immersion heater to het 250g of water from 20c to 100c
The immersion heater would take approximately 0.0465 minutes to heat 250g of water from 20°C to 100°C.
The number of minutes required for a 300W immersion heater to heat 250g of water from 20°C to 100°C can be calculated by applying the specific heat capacity formula.
According to the formula,
The amount of heat needed to increase the temperature of a substance is equal to the product of the mass of the substance, the specific heat capacity of the substance, and the change in temperature.
Specific heat capacity formula:
q = mcΔT
Where:
q = heat energy (Joules)
m = mass of substance (kg)
c = specific heat capacity of substance (Joules/kg°C)
ΔT = change in temperature (°C)
In this case, we have:
m = 0.25 kg (since 250g is equal to 0.25kg
c = 4.184 J/g°C (specific heat capacity of water)
ΔT = (100°C - 20°C) = 80°C
We need to convert the power of the immersion heater from Watts to Joules per second since the specific heat capacity formula requires the units of power to be in Joules per second (J/s).
1 Watt = 1 Joule/second (J/s)
So, the power of the immersion heater can be converted as follows:
300 Watts = 300 Joules/second (J/s)
q = mcΔT
to find the heat energy required to heat the water:
q = (0.25 kg) x (4.184 J/g°C) x (80°C)
q = 836.8 Joules
The time taken to heat the water can be calculated using the formula:
Power = Energy / Time
where Power is in Watts (J/s), Energy is in Joules, and Time is in seconds.
Time = Energy / Power
Time = 836.8 J / 300 J/s
Time = 2.79 seconds
So, the number of minutes required for the immersion heater to heat 250g of water from 20°C to 100°C is:
2.79 seconds ÷ 60 = 0.0465 minutes
Therefore, the immersion heater would take approximately 0.0465 minutes to heat 250g of water from 20°C to 100°C.
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what is the average linear velocity of water in the aquifer if the specific discharge is 0.35 m/day?
The linear velocity of water in the aquifer is 0.35 m/day if the specific discharge is 0.35 m/day.
Linear velocity, often known as tangential velocity or tangential speed, refers to the rate at which an object travels in a straight line around a circular path.
Average linear velocity is defined as the ratio of discharge to cross-sectional area. The formula for average linear velocity is as follows: V = Q/A Where: V = Average linear velocity Q = DischargeA = Cross-sectional area. Substitute the given values of discharge in the above equation to find the average linear velocity of water in the aquifer.
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calculate the angular momentum, in kilogram meters squared per second, of the earth spining on its axis.
The angular momentum of the Earth spinning on its axis is 7.1 × 10³⁰ kilogram meters squared per second.
What is angular momentum?Angular momentum is the quantity of rotation of a body that takes into account its mass and its rotational speed. Angular momentum = Moment of inertia × Angular velocity
where the moment of inertia is a measure of how an object's mass is distributed around its centre of rotation.
The moment of inertia of the Earth:
moment of inertia = 2/5 × mass × radius²
where the mass of the Earth is 5.97 × 10²⁴ kg and its radius is 6.38 × 10⁶ m.
Therefore, moment of inertia = 2/5 × 5.97 × 10²⁴ kg × (6.38 × 10⁶ m)²
= 9.83 × 10³⁷ kg m²
Using the fact that the Earth completes one rotation every 24 hours, or 86400 seconds,
the angular velocity of the Earth:
angular velocity = 2π / time taken for one rotation
= 2π / 86400 seconds
= 7.27 × 10⁻⁵ radians per second
Finally, the angular momentum of the Earth spinning on its axis:
angular momentum = Moment of inertia × Angular velocity
=9.83 × 10³⁷ kg m² × 7.27 × 10⁻⁵ radians per second
= 7.1 × 10³⁰ kg m²/s
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A ramp is 4 meters tall and has a mechanical advantage of 2.5 what is its length? HELP
We must use the mechanical advantage formula to determine the length of the ramp:
Output force minus Input force equals Mechanical Advantage (MA). In this instance, the input force is the force required to hoist the object in the absence of the ramp, and the output force is the weight of the object being raised up the ramp
How do you determine a ramp's mechanical advantage?By dividing the length of the slope by its height, you may calculate the optimal mechanical advantage of an inclined plane. The ideal mechanical advantage of a ramp, for instance, is 3 metres 1 metre, or 3 metres, if you are loading a truck that is 1 metre high utilising it.
How is the mechanical advantage determined?Basic Machines' Mechanical Advantage and Efficiency Calculated. The IMA is typically calculated as the resistance force (Fr) divided by the effort force (Fe). IMA is also equal to the product of the load's travel distance (d) and the distance over which the effort is applied (de).
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if a bag has a mass of 25 kg, how much force must you apply vertically to lift it off of a baggage cart?
A force of 245 N must be applied vertically to lift the bag off the baggage cart.
The force that must be applied vertically to lift a bag off a baggage cart, given that the bag has a mass of 25 kg, can be determined using the formula F = m*g
where F is force, m is mass, and g is acceleration due to gravity. The value of g is 9.8 m/s².So, F = 25 kg x 9.8 m/s² = 245 N. Therefore, a force of 245 N must be applied vertically to lift the bag off the baggage cart.
The mass of the bag = 25 kg.The formula used is, F = m*gwhereF = Force required to lift the bagm = Mass of the bagg = Acceleration due to gravityF = 25 kg x 9.8 m/s² = 245 N.
Therefore, a force of 245 N must be applied vertically to lift the bag off the baggage cart.
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