According to the information, the values that coincide are: 2.2 meters with 2200 millimeters, 14 decimeters with 0.014 hectometers, 0.14 meters with 0.014 decameters, 0.022 decameters with 22 centimeters.
How to find the numbers that match?To find the numbers that match we must take into account the relationship between the values:
Decameter: Unit of length equal to 10 meters.Centimeter: Unit of length equal to one hundredth of a meter.Decimeter: Unit of length equal to one tenth of a meter.Millimeter: Unit of length equal to one thousandth of a meter.Hectometer: Unit of length equal to 100 meters.According to the above, we can infer that the values that match are:
2.2 meters with 2200 millimeters.14 decimeters with 0.014 hectometers.0.14 meters with 0.014 decameters,0.022 decameters with 22 centimeters.Learn more about measurements at: https://brainly.com/question/4725561
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100 POINTS NEED HELP ASAP QUESTIONS ARE BELOW
Area of triangle= 24 cm²
Area of sector= 72.243 cm²
Total area= 96.243 cm².
What is triangle?A polygon with three sides and three vertices is called a triangle. It is one of the fundamental geometric forms. Triangle ABC is the designation for a triangle with points A, B, and C. In Euclidean mathematics, any three points that are not collinear produce a distinct triangle and a distinct plane.
What is sector?The portion of a disc enclosed by two radii and an arc is called a circular sector, also known as a circle sector or disc sector. The smaller area is referred to as the minor sector, and the bigger area as the major sector. A sector is referred to as a component of a circle made up of the circular's arc and its two radii.
In this question,
Area of triangle= 1/2 × base × height
= 1/2 × 6 ×8
= 24 cm²
Area of sector = (θ/360°) × πr²
= (82/360) × πr²
Here r=√6²+8²
= 10 cm
Area of sector = (82/360) × π10²
= 0.23 × 314.1
= 72.243 cm²
Total= 24 cm²+72.243 cm²= 96.243 cm².
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I please need help matching the angles. I cannot seem to get it right.
The angles and lines that match the angles and lines in the diagram consisting of two lines and their common transversal to the correct description are;
Alternate Interior Angles; 2. ∠4 and ∠8
Consecutive Exterior Angles; 5. ∠1 and ∠6
Alternate Exterior Angles; 3. ∠1 and ∠5
Transversal; line l
Consecutive Interior Angles; 4. ∠3 and ∠4
Corresponding Angles; 1. ∠1 and ∠7
What is a transversal line?A transversal is a line that intersects two or more other lines.
The description of the relationship between the angles in the question are;
Alternate Interior Angles
Alternate interior angles are a pair of angles formed when a transversal intersects two lines. They are located between the two lines on opposite side of the transversal.
Consecutive Exterior Angles
Consecutive Exterior Angles are a pair of angles formed when a transversal intersects two lines. They are located outside the two lines on the same side of the transversal
Alternate Exterior Angles
Alternate exterior angles are a pair of angles formed when a transversal intersects two lines. They are located outside the two lines on the opposite sides of the transversal.
Consecutive Interior Angles
Consecutive Interior Angles, also known as Same-Side Interior Angles are a pair of angles formed when a transversal intersects two parallel lines. They are located between the two parallel lines on the same side of the transversal.
Corresponding Angles
Corresponding angles are a pair of angles formed when a transversal intersects two lines. They are located on the same relative positions with respect to the transversal and the two lines.
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Para prepara un pastel Anita tenía un paquete de harina de 1 1/3 si solo uso 3/6 kg del paquete que cantidad de harina le sobró
Para preparar un pastel, Anita tenía un paquete de harina de 1 1/3 kg: 0.83 kg
Primero, debemos convertir 1 1/3 kg a una fracción común. 1 1/3 kg es igual a 4/3 kg o 1.33 kg. Luego, podemos simplificar 3/6 a 1/2.
Ahora podemos restar 1/2 de 1.33 kg para encontrar la cantidad de harina que sobró.
1.33 kg - 1/2 kg = 1.33 kg - 0.5 kg = 0.83 kg
Entonces, Anita le sobró aproximadamente 0.83 kg de harina después de preparar su pastel.
Es importante recordar que la medición y las cantidades de los ingredientes son cruciales al preparar cualquier receta de cocina. Es importante seguir las instrucciones cuidadosamente para obtener resultados exitosos en la cocina.
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Question 7 of 10
AFGH is a right triangle.
9
6
G
√45
H
A. True
OB. False
Yes, it is true that Triangle FGH is a right triangle.
How can this be determined?We check whether the Pythagorean theorem holds true for these sides to determine if this triangle is a right triangle. According to the Pythagorean theorem, the square of the hypotenuse is equal to the sum of the squares of the right triangle's legs.
a² + b² = c²
If this is a right triangle, the hypotenuse will be the longest side, and the other two sides will be the legs. We have these when we incorporate the Pythagorean theorem.
6²+(√45)² = 9²
36+45 = 81
which implies that right triangle because the assertion is true.
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I need help ASAP.I m really confused with it
16 Triangle ABC is translated to triangle A'B'C' by
the following motion rule.
(x, y)(x+2y-5)
-8 -6
G
A. (4,-4)
B. (2,-5)
C. (0.6)
D. (-2.5)
N
8
6
B
-2
S
-6
-8
2
What will be the coordinates of A'?
6 8
Answer:
To find the coordinates of A' after the translation, we need to apply the motion rule to the coordinates of A:
(x, y) → (x + 2y - 5, y - 6)
Substituting the coordinates of point A, which is (4, -4), into this motion rule, we get:
A' = (4 + 2(-4) - 5, -4 - 6) = (-3, -10)
Therefore, the coordinates of A' after the translation are (-3, -10).
These tables represent the relationships between x and y for two different sets of data.
Which statements correctly describe the relationships between x and y for each table?
Responses
Both data sets represent multiplicative relationships. In Table A, y is 3.5 times x, and in Table B, y is 9.2 times x.
Both data sets represent multiplicative relationships. In Table A, , y, is 3.5 times , x, , and in Table B, , y, is 9.2 times , x, .
Both tables represent additive relationships. In Table A, y is 2.5 more than x, and in Table B, y is 8.2 more than x.
Both tables represent additive relationships. In Table A, , y, is 2.5 more than , x, , and in Table B, , y, is 8.2 more than , x, .
Table A represents a multiplicative relationship because y is 3.5 times x, and Table B represents an additive relationship because y is 8.2 more than x.
Table A represents a multiplicative relationship because , y, is 3.5 times , x, , and Table B represents an additive relationship because , y, is 8.2 more than , x, .
Table A represents an additive relationship because y is 2.5 more than x, and Table B represents a multiplicative relationship because y is 9.2 times x.
Table A represents an additive relationship because , y, is 2.5 more than , x, , and Table B represents a multiplicative relationship because , y, is 9.2 times , x, .
Table A
x 1 2 3 4
y 3.5 7 10.5 14
Table B
x 1 2 3 4
y 9.2 10.2 11.2 12.2
Answer:
Both data sets represent multiplicative relationships. In Table A, y is 3.5 times x, and in Table B, y is 9.2 times x.
The correct statement is: Both data sets represent multiplicative relationships. In Table A, y is 3.5 times x, and in Table B, y is 9.2 times x.
What is the measure of
Answer:
∠w = 50°
∠y = 130°
Step-by-step explanation:
Angles ∠w and ∠y are supplementary angles, which means their sum is 180.
4x + 6 + 12x - 2 = 180
Add like terms16x + 4 = 180
Subtract 4 from both sides16x = 176
Divide both sides by 16x = 11
To find the angle measures replace x with 11
∠w = 4x + 6
∠w = 4*11 + 6
∠w = 50°
Now, ∠y
∠y = 12x - 2
∠y = 12*11 - 2
∠y = 130°
Alia has 36 1/4 inches shares of silver chain to make some braces if she needs 7 1/4 inches of the chain to make one bracelet how many bracelets can Alia
make
Answer:
To find the number of bracelets Alia can make, we need to divide the total length of the silver chain she has by the length of each bracelet.
Total length of silver chain = 36 1/4 inches
Length of each bracelet = 7 1/4 inches
To divide fractions, we need to invert the second fraction and multiply:
(36 1/4) ÷ (7 1/4) = (145/4) ÷ (29/4) = (145/4) x (4/29) = 5
Therefore, Alia can make 5 bracelets with the given amount of silver chain.
Answer:
5 bracelets
Step-by-step explanation:
Given Information:
Amount of chain needed for 1 bracelet: 7 1/4 inchesTotal chain length: 36 1/4 inchesClearly, the number of bracelets possible (say x) multiplied by the amount of chain required for 1 bracelet will result in the total chain length (36 1/4).
⇒ 7 1/4 × x = 36 1/4Now, we can divide 7 1/4 on both sides to find value of x (total bracelets).
⇒ (7 1/4 × x)/(7 1/4) = (36 1/4)/(7 1/4)⇒ x = (36 1/4)/(7 1/4) = 5Therefore, Alia can make 5 bracelets.
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Do you guys know the answer to this please help?
Answer:37
Step-by-step explanation:
<UYW=<UYV+<VYW=36+2x=110
2x=110-36=74
x=74/2=37
Find the foci of the hyperbola 4y2-x2=16
The foci of the hyperbola is (0,2[tex]\sqrt5[/tex]) and ([tex]0,-2\sqrt5)[/tex].
What is foci of the hyperbola?The two fixed points that are located inside each curve of a hyperbola are known as its foci, and they are important for the formal description of the curve.
Here the given equation of the hyperbola is [tex]4y^2-x^2=16[/tex] .
Now writing the given equation into standard form then,
=> [tex]4y^2-x^2=16[/tex]
=> [tex]-x^2+4y^2=16\\[/tex]
=> [tex]\frac{-x^2}{4}+\frac{4y^2}{4}=\frac{16}{4}[/tex]
=> [tex]\frac{-x^2}{4}+y^2=4[/tex]
=> [tex]\frac{-x^2}{4\times4}+\frac{y^2}{4}=1[/tex]
=> [tex]\frac{-x^2}{16}+\frac{y^2}{4}=1[/tex]
Here we know that [tex]\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1[/tex] then a=2 and b=4 , (h , k)=(0,0)
Then c=[tex]\sqrt{a^2+b^2}=\sqrt{2^2+4^2}=\sqrt{4+16}=\sqrt{20}=2\sqrt{5}[/tex].
Then foci is (0,0+c) and (0,0-c) then,
=> (0,2[tex]\sqrt5[/tex]) and ([tex]0,-2\sqrt5)[/tex]
Hence the foci of the hyperbola is (0,2[tex]\sqrt5[/tex]) and ([tex]0,-2\sqrt5)[/tex].
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the opposite of the oppsite of 28,or (-28),is equivalent to which of the following
0
-28
28
The opposite of the oppsite of 28,or (-28), is equivalent to the option (c) 28
How to determine the equivalent expressionThe opposite of a number is the number with the opposite sign.
For example, the opposite of 28 is -28, and the opposite of -28 is 28.
So, the opposite of the opposite of 28, or (-28), is the opposite of -28, which is 28.
This means that the answer is (c) 28.
To explain it further, think of the number line. 28 is a positive number, so its opposite is a negative number, which is -28.
Now, the opposite of -28 is a positive number, which is 28. So, the opposite of the opposite of 28 is 28.
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Greg covered the back of the picture with a piece of felt. The picture is 1 1/4 inches shorter than the fram and 1 inch less in width what is the area of the felt
The area of the felt is (5L - 4W - 5) / 4 (inches)².
What is an area?
To find the area of the felt, we need to know the dimensions of the picture and the frame.
Let's say the length of the frame is L and the width of the frame is W.
Then, according to the problem:
The length of the picture is 1 1/4 inches shorter than the frame, so its length is L - 1 1/4 = (4L - 5) / 4 inches.The width of the picture is 1 inch less than the frame, so its width is W - 1 inches.To find the area of the felt, we need to subtract the area of the picture from the area of the frame. The area of the frame is L x W, and the area of the picture is (4L - 5) / 4 x (W - 1). So the area of the felt is:
Felt area = Frame area - Picture area
= L x W - (4L - 5) / 4 x (W - 1)
= (4LW - 4W) / 4 - (4LW - 5L - 4W + 5) / 4
= (5L - 4W - 5) / 4
Therefore, the area of the felt is (5L - 4W - 5) / 4 (inches)². Note that we can't simplify this expression further without knowing the specific values of L and W.
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Complete question is: Greg covered the back of the picture with a piece of felt. The picture is 1 1/4 inches shorter than the fram and 1 inch less in width the area of the felt is (5L - 4W - 5) / 4 (inches)².
What is the surface area of an ice cube that has 4 cm sides?
TA
4 cm
4 cm
The surface area of an ice cube with 4 cm sides is 96 square centimeters.
What is surface area?It is a measurement of the sum of all the areas of the faces, sides, and any other surfaces of an object. For example, a cube has six square faces, each with the same area.
According to question:To find the surface area of an ice cube with 4 cm sides, we need to add up the areas of all six faces. Each face is a square with side length 4 cm, so the area of each face is:
Area of one face = (side length)² = 4 cm × 4 cm = 16 cm²
Since there are six faces on a cube, the total surface area of the ice cube is:
Total surface area = 6 × (area of one face) = 6 × 16 cm² = 96 cm²
Therefore, the surface area of an ice cube with 4 cm sides is 96 square centimeters.
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The length of the longer leg of a 30 60 90 triangle is 6. The shorter leg is 4.
State the solution in Simple Root Form:
State the solution to the nearest tenth:
Step-by-step explanation:
remember the trigonometric triangle inscribed in a circle (the norm circle with radius = 1).
for a larger system the leg lengths are sine and cosine multiplied by the radius (which is the Hypotenuse of the right-angled triangle).
the longer leg is opposite of the larger angle (60°).
the shorter leg is opposite of the smaller angle (30°).
what is the desired solution ? the length of the Hypotenuse ? or what ?
6 = sin(60)×Hypotenuse
Hypotenuse = 6/sin(60) = 6/(sqrt(3)/2) = 12/sqrt(3) =
= 6.92820323... ≈ 6.9
Which of these points are 5 units away from (-6, -3)? Select all that apply.
(-3, -7)
(-2,-7)
(-2, 0)
(-9, -1)
Answer:(-3, -7)
Step-by-step explanation: (7-3,-) look the middle is (3,-6) and instead on 7 is 6 bec in 7-
What is the product of 2.5 and 7.08?
Show your work.
Solve the following linear programming problem. Maximize: z = 7x + 2y subject to: 7x-y≤ 16 2x+y≥ 10 X≥2 y≤9 The maximum value is
Answer:
To solve the linear programming problem, we need to first graph the feasible region determined by the constraints, and then evaluate the objective function at each corner point of the feasible region to find the maximum value of z.
Plotting the lines corresponding to the inequalities, we get:
Graph of the feasible region:
The feasible region is the shaded polygon in the graph. We can see that the vertices of the feasible region are (2, 9), (2, 12), (4, 7), and (8, 2).
Next, we evaluate the objective function at each of these vertices to find the maximum value of z.
At (2, 9): z = 7x + 2y = 7(2) + 2(9) = 23
At (2, 12): z = 7x + 2y = 7(2) + 2(12) = 31
At (4, 7): z = 7x + 2y = 7(4) + 2(7) = 35
At (8, 2): z = 7x + 2y = 7(8) + 2(2) = 58
Therefore, the maximum value of z is 58, which occurs at the point (8, 2).
Hence, the answer is: the maximum value of z is 58.
Bug S Bug S and Bug F is fast. Both bugs start at 0 on a number line and move in the positive direction. The bugs leave 0 at the same time and move at constant speeds. Four seconds later, F is at 12 and S is at 8. When will F and S be 100 units apart?
Answer:
Let's call the speed of Bug F v_F and the speed of Bug S v_S. Since both bugs started at 0, we can express their positions at any time t as:
Position of Bug F = 12 + v_F * t
Position of Bug S = 8 + v_S * t
To find out when F and S will be 100 units apart, we need to find the time t at which their positions differ by 100 units. In other words, we need to solve the following equation:
|12 + v_F * t - (8 + v_S * t)| = 100
We can simplify this equation by expanding the absolute value and rearranging the terms:
|4 + (v_F - v_S) * t| = 100
Now we can split this equation into two cases:
Case 1: 4 + (v_F - v_S) * t = 100
In this case, we have:
v_F - v_S > 0 (since Bug F is faster)
t = (100 - 4) / (v_F - v_S)
Case 2: 4 + (v_F - v_S) * t = -100
In this case, we have:
v_F - v_S < 0 (since Bug S is faster)
t = (-100 - 4) / (v_F - v_S)
Since we're only interested in positive values of t, we can discard the second case. Therefore, the time at which F and S will be 100 units apart is:
t = (100 - 4) / (v_F - v_S)
t = 96 / (v_F - v_S)
We don't know the values of v_F and v_S, but we can use the fact that Bug F is at 12 and Bug S is at 8, four seconds after they started. This gives us two equations:
12 = 4v_F + 0v_S
8 = 4v_S + 0v_F
Solving these equations for v_F and v_S, we get:
v_F = 3
v_S = 2
Substituting these values into the equation for t, we get:
t = 96 / (3 - 2)
t = 96
Therefore, F and S will be 100 units apart 96 seconds after they start.
A rectangular garden measures 40m by 15m. A 1m flower bed is made round the two shorter sides and one
long side. A circular swimming pool of diameter 8m is constructed in the middle of the garden. Find
correct to the nearest square meter, the area remaining
Answer:
The area remaining, correct to the nearest square meter, is approximately 436 square meters.
Step-by-step explanation:
To find the area remaining, we need to subtract the area of the flower bed and the area of the pool from the total area of the garden.
The total area of the garden is:
40m x 15m = 600 square meters
The flower bed is 1m wide and runs along two shorter sides and one long side of the garden. So the area of the flower bed is:
(40m + 2 x 1m) x (15m + 2 x 1m) - 40m x 15m
= (42m x 17m) - (40m x 15m)
= 714 - 600
= 114 square meters
Now let's calculate the area of the pool. The diameter of the pool is 8m, so the radius is 4m. The area of the pool is:
π x (4m)^2
= 16π
≈ 50.27 square meters (rounded to two decimal places)
So the area remaining is:
600 square meters - 114 square meters - 50.27 square meters
≈ 435.73 square meters
Therefore, the area remaining, correct to the nearest square meter, is approximately 436 square meters.
If x ≠ 0 and y ≠ 0, which expression is equivalent to −4x−2 y−3 ? Responses A −4x2y3 − 4 x 2 y 3 B 14x2y3 1 4 x 2 y 3 C −4x2y3 − 4 x 2 y 3 D −4xy − 4 xy
Answer:The expression −4x−2y−3 can be written as −4/x^2y^3.
Multiplying both numerator and denominator by -1, we get 4/x^2y^3.
Hence, option A, −4x^2y^3, is equivalent to −4x−2y−3.
Step-by-step explanation:
Marissa ate 4 hot dogs every 16 hours. At that rate, how many would she eat in 12 hours?
Answer: 3
Step-by-step explanation:
Answer: 3
Step-by-step explanation:
16/4=unit rate =4
1 in 4 hour
3 for 12 hours
f(x) = x². What is g(x)?
WW
(3, 1)
g(x)
-5
y f(x) = x²
5
Click here for long description
A. g(x) = 3x²
B. g(x) = (x)²
2
C. g(x) = x²
2
D. g(x) = (x)
Finding [tex]g(x)[/tex] given that we know [tex]f(x)[/tex] and the graphs for both functions. The correct option is D:
[tex]g(x) = (x/3)^2[/tex]
How to find g(x)?Looking at the graph on the image, we notice that [tex]f(x)[/tex] and [tex]g(x)[/tex] are two quadratic functions, and [tex]g(x)[/tex] is just a dilation o f[tex]f(x)[/tex].
This means that:
[tex]g(x) = A*f(x)[/tex]
Where A is a real number.
We know that:
[tex]f(x) = x^2[/tex]
By looking at the graph in the image, we know that [tex]g(3) = 1[/tex].
Then we can write:
[tex]g(3) = A*f(3) = A*3^2 = 1[/tex]
We can now solve for A:
[tex]A*3^2 = 1[/tex]
[tex]A*9 = 1[/tex]
[tex]A = 1/9[/tex]
We will have:
[tex]g(x) = (1/9)*f(x) = (1/9)*x^2 = (x/3)^2[/tex]
Therefore, the correct option is D.
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Complete question in image attached.
HELP!!!! IM GOING TO FAIL!!!
Answer10 toooooooooooo the third poewedd
Step-by-step explanation:
Please help me to answer the question
The range of the function for one day of work is 75 ≤ y ≤ 425. So, correct option is B.
Describe Function?In mathematics, a function is a mathematical object that takes an input (or several inputs) and produces a unique output. It is a relationship between a set of inputs, called the domain, and a set of outputs, called the range.
Formally, a function f is defined by a set of ordered pairs (x, y) where x is an element of the domain, and y is an element of the range, and each element x in the domain is paired with a unique element y in the range. We write this as f(x) = y.
The linear function that models the daily cost of hiring an electrician can be written as:
y = 50x + 75
where x is the number of hours worked by the electrician and y is the cost in dollars.
Since the electrician works a maximum of 7 hours per day, the domain of the function is 0 ≤ x ≤ 7.
To find the range of the function, we can substitute the maximum and minimum values of x into the function and see what values of y we get:
When x = 0 (no hours worked), y = 50(0) + 75 = 75.
When x = 7 (maximum hours worked), y = 50(7) + 75 = 425.
Therefore, the range of the function for one day of work is:
75 ≤ y ≤ 425
So the answer is (B) 75 ≤ y ≤ 425.
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The sum of the measures of the angles of a triangle is 180. The sum of the measures of
the second and third angles is five times the measure of the first angle. The third angle
is 26 more than the second. Let x, y, and z represent the measures of the first, second,
and third angles, respectively. Find the measures of the three angles.
The measures οf the three angIes are x = 51.43 degrees, y = 92.85 degrees, and z = 118.85 degrees.
What is Iinear equatiοn?A Iinear equatiοn is a mathematicaI equatiοn that describes a straight Iine in a twο-dimensiοnaI pIane.
We can use the infοrmatiοn given in the prοbIem tο fοrm a system οf three equatiοns with three variabIes. Let x, y, and z represent the measures οf the first, secοnd, and third angIes, respectiveIy.
Frοm the first piece οf infοrmatiοn, we knοw that: x + y + z = 180
Frοm the secοnd piece οf infοrmatiοn, we knοw that: y + z = 5x
Frοm the third piece οf infοrmatiοn, we knοw that: z = y + 26
We can substitute the third equatiοn intο the secοnd equatiοn tο eIiminate z:
y + (y + 26) = 5x
2y + 26 = 5x
2y = 5x - 26
y = (5x - 26)/2
We can substitute this expressiοn fοr y intο the first equatiοn tο eIiminate y and z:
x + (5x - 26)/2 + (5x - 26)/2 + 26 = 180
2x + 5x - 26 + 26 = 360
7x = 360
x = 51.43
We can substitute this vaIue οf x back intο the expressiοn fοr y tο find y:
y = (5x - 26)/2
y = (5(51.43) - 26)/2
y = 92.85
FinaIIy, we can use the equatiοn z = y + 26 tο find z:
z = y + 26
z = 92.85 + 26
z = 118.85
Therefοre, the measures οf the three angIes are x = 51.43 degrees, y = 92.85 degrees, and z = 118.85 degrees.
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How many quarts of pure antifreeze must be added to 5 quarts of a 10 % antifreeze solution to obtain a 30 % antifreeze solution?
According to the solving this algebra approximately 1.43 quarts of pure antifreeze to the initial 5 quarts of 10% antifreeze solution to obtain a 30% antifreeze solution.
what is algebra?
Mathematical operations are applied to abstract symbols rather than concrete numbers in the field of algebra, which also includes other formal manipulations. The area of mathematics known as geometry is concerned with the qualities of the space that objects are in as well as the shape of the objects themselves.
According to the given information:
Let Q be the number of quarts of pure antifreeze to be added.
Let 0.10(5) be the amount of antifreeze in the initial 5 quarts of the 10% antifreeze solution, which is 0.5 quarts.
To obtain a 30% antifreeze solution, the amount of antifreeze in the final solution should be 0.3(5+Q) quarts.
Since we are only adding pure antifreeze, the amount of antifreeze in the final solution will be the sum of the antifreeze in the initial solution and the antifreeze we add:
0.5 + Q = 0.3(5+Q)
Now we can solve for Q:
0.5 + Q = 1.5 + 0.3Q
0.7Q = 1
Q = 1/0.7
Q ≈ 1.43
Therefore, we need to add approximately 1.43 quarts of pure antifreeze to the initial 5 quarts of 10% antifreeze solution to obtain a 30% antifreeze solution.
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The scatterplot of the data below models what type of correlation?
Answer:
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Step-by-step explanation:
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type an equation for the following pattern x12345 y-2 -4 -6 -8 -10
Answer: y = -2 - 2 * (x - 1).
Step-by-step explanation: The pattern is a linear function with a slope of -2 and an intercept of -2. The slope of a line is the change in y over the change in x. In this case, the change in y is -2 and the change in x is 1. Therefore, the slope is -2/1 = -2. The intercept is where the line crosses the y-axis, which is at y = -2 when x = 1. Therefore, the equation of the line is y = mx + b where m is the slope and b is the intercept. Substituting m = -2 and b = -2 gives us y = -2 - 2 * (x - 1).
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An air tank of 500 mL is 80% oxygen and 20% nitrogen. What is the amount of oxygen in milliliters in a 200 ml air tank that contains the same ratio?
Hence, 160 mL of oxygen is contained inside a 200 mL air tank using the same ratio as a 500 mL air tank.
How is ratio calculated?Ratios contrast two figures by ordinarily dividing them. A/B would be your formula if you were trying to compare one piece of data (A) to some other data point (B). We are multiplying information A by data B, as this suggests. In the event that A and B are both 5, for example, your ratio would've been 5/10.
80% of 500 mL of oxygen if indeed the air tank contains 80% oxygen & 20% nitrogen, which is:
0.80 x 500 mL = 400 mL
This means that the air tank contains 400 mL of oxygen and 100 mL of nitrogen.
To find the amount of oxygen in a 200 mL air tank that contains the same ratio, we need to use proportions:
If 500 mL contains 400 mL of oxygen, then 1 mL contains 400/500 = 0.8 mL of oxygen.
Therefore, if 200 mL contains the same ratio of oxygen, it will contain:
0.8 mL x 200 mL = 160 mL
So, the amount of oxygen in a 200 mL air tank with the same ratio as the 500 mL air tank is 160 mL.
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