at a certain location, wind is blowing steadily at 10 m/s. determine the mechanical energy of air per unit mass and the power generation potential of a wind turbine

A lunar eclipse is an astronomical event where the Earth's shadow is cast onto the moon.

During a lunar eclipse, observers on the Earth would see the moon becoming dimmer and turning a reddish color, while observers on the moon would witness the Earth casting a shadow onto its surface.

The Earth is between the moon and the sun during a lunar eclipse, blocking the direct sunlight that normally illuminates the moon. This causes the moon to become dimmer and take on a reddish hue as indirect sunlight is refracted off of the Earth's atmosphere.

On the moon, observers would be able to see the Earth's shadow slowly moving across its surface. As the Earth's shadow covers the moon, the entire lunar surface will become darkened and take on a reddish hue. This is because indirect sunlight from the sun is refracted off of the Earth's atmosphere, providing a soft, red illumination to the moon's surface.

During a lunar eclipse, therefore, observers on the Earth and on the moon will witness the same kind of astronomical event.

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A wire has a length of l1 and a cross-sectional surface area of a1 and if we double the length of this wire, and reduce its surface area to 1/3 of its original value. The resistance change by: 6 times

The resistance change can be calculated using the formula R = ρl / a, where ρ is the resistivity of the wire, l is the length of the wire, and a is the cross-sectional area of the wire. If we double the length of the wire and reduce its surface area to 1/3 of its original value, we can find the new resistance using the same formula. Let's call the new length of the wire l2 and the new cross-sectional area a2.

So, we have:
l2 = 2l1  (double the length)
a2 = (1/3)a1  (reduce the surface area to 1/3 its original value)

Now we can calculate the new resistance:
[tex]R2 = ρl2 / a2[/tex]
[tex]R2 = ρ(2l1) / [(1/3)a1][/tex]
[tex]R2 = 6ρl1 / a1[/tex]

So the new resistance is 6 times the original resistance. This means that the resistance changes by a factor of 6 when the length of the wire is doubled and the surface area is reduced to 1/3 of its original value.

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Isolated/insulated equipment grounding circuits must include one equipment grounding conductor to meet the requirements of the National Electrical Code (NEC). These grounding conductors play a crucial role in ensuring the safety and proper functioning of electrical systems.

The NEC sets the standards for the safe installation of electrical wiring and equipment in the United States. An isolated equipment grounding circuit is designed to maintain electrical safety by providing a dedicated path for grounding equipment. This prevents unwanted electrical noise or interference from affecting the performance of sensitive electronic devices.

A single equipment grounding conductor is sufficient for an isolated grounding circuit, as it is meant to carry the fault current back to the source of power, protecting people and equipment from electrical hazards. The conductor is usually made of copper or aluminum and is sized according to the size of the circuit conductors.

This grounding conductor is connected to a grounding electrode system, which includes grounding electrodes such as ground rods, metallic water pipes, or concrete-encased electrodes. These electrodes create a connection to the earth, ensuring that any fault current is safely dispersed into the ground.

By complying with the NEC requirements, you ensure that your electrical systems are designed and installed in a manner that reduces the risk of electrical shock, fire hazards, and other potential dangers. A properly grounded electrical system promotes safety, performance, and reliability in any electrical installation.

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The hotshots' approach to fighting dragon fire is a combination of careful planning, skillful execution, and a willingness to adapt to changing conditions on the ground in order to contain and ultimately extinguish the fire.

Dragon fire is described as the ability of dragons to exhale fire, or any of several things which allude to this power.

Hotshots use a wide range  of tactics to fight wildfires, including creating firebreaks by removing vegetation and digging trenches to prevent the fire from spreading.

Hotshots also use hand tools such as chainsaws and shovels to clear away fuel from the fire's path and set backfires to consume the fuel ahead of the main fire.

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Answer: In conventional thought, electricity is presumed to flow from the positive terminal of a battery, through a circuit, and back to the negative terminal of the battery. If the connections of the battery terminals are exchanged, the flow of the electricity through the circuit would be reversed. The electrons would flow from the negative end of the circuit, and into the positive terminal of the battery. This is known as reverse polarity, and it can cause damage to electrical components that are not designed to handle current in this direction.

The given statement is true. The second law of thermodynamics acknowledges that the extensive property entropy is produced within systems whenever friction and other non-idealities are present there.

In the absence of non-idealities, a machine would be capable of operating indefinitely, and no energy would be required to keep it going. However, since non-idealities exist, a machine must consume energy to keep going, and the amount of energy that must be consumed is proportional to the amount of non-idealities that exist. Friction is the most common cause of non-idealities, and it leads to an increase in entropy.

In thermodynamics, entropy is a measure of the quantity of thermal energy unavailable for doing mechanical work. It represents the degree of disorder or randomness in a system. Entropy, according to the second law of thermodynamics, increases over time. Heat transfer from hot to cold objects is an example of the second law of thermodynamics. Heat transfer from hot to cold objects cannot be stopped because heat flows from hotter objects to cooler ones. As a result, the entropy of the universe increases as the heat transfer happens.

As a result, entropy is sometimes referred to as a measure of disorder or randomness in a system. The amount of entropy in a system, according to the second law of thermodynamics, can never decrease over time.

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The pen's narrow end provides a small surface area for it to balance on, making it more difficult to stay upright.

This is because the pen is not symmetrical and has a wide top compared to the bottom. The wider top will cause the pen to easily tip over when placed on its narrow end due to the unbalanced weight distribution.

Balancing a pen vertically on its narrow end also requires a steady hand and a great deal of focus. The pen must be held perfectly still and be placed gently in order to maintain its balance. If the pen is shifted even slightly, it can easily fall off of its narrow end. Additionally, the surface the pen is placed on must be even and stable to provide a solid base for it to balance on.

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The amount of force that the pitcher applies to the baseball is 11.6N.

Force is a physical quantity that denotes ability to push, pull, twist or accelerate a body. It can be calculated by multiplying the mass of the object by its acceleration as follows;

Force = mass × acceleration

According to this question, a baseball has a mass of 145 g. A pitcher throws the baseball so that it accelerates at a rate of 80 m/s². The force applied on the baseball can be calculated as follows:

Force = 145/1000 kg × 80m/s²

Force = 11.6N

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Answer: The table that would organize and summarize the class data on pH levels of the different soil types is found in the attachment below.

Explanation: As an A+ student, I love to help people on brainly in my free time! If this answer helped you, please click the heart, click the crown to give brainliest and give a 5 star rating! I'd appreciate it if you did at least one of those <3 Have a great day.

The resistance of a wire is inversely proportional to the cross-sectional area of the wire. So, the resistance of the second wire is one-half of the resistance of the first wire, which is 100 ohms.

Resistance of a copper wire with a cross-sectional area and length.The resistance of a copper wire with a cross-sectional area and length can be calculated using the formula:R=ρL/A

Substituting the given values of resistance R and cross-sectional area A for the first copper wire, we get:R₁ = ρL/A ... (1)where ρ is the resistivity of copper, L is the length of the wire and A is the cross-sectional area of the wire.The resistance of the second copper wire with twice the cross-sectional area A but the same length L can be calculated using the same formula as:R₂ = ρL/2A = (1/2)(ρL/A) ... (2)

Substituting the value of R₁ from equation (1) in equation (2), we get:R₂ = (1/2)(R₁) = 1/2 x 200 = 100Ω

Therefore, the resistance of the second copper wire would be 100 ohms.

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Based on the above,  3.75 x 10¹² electrons have been added to the glass rod.

To determine the number of electrons added to the glass rod, we need to know the charge of a single electron. One electron has a charge of -1.6 x 10⁻¹⁹ C.

Charge added to the glass rod = -0.6 μC = -0.6 x 10-⁶ C

Number of electrons added to the glass rod = (charge added to the rod) / (charge of a single electron)

Number of electrons added to the glass rod = (-0.6 x 10⁻⁶ C) / (-1.6 x 10⁻¹⁹C) = 3.75 x 10¹² electrons

Therefore, 3.75 x 10¹² electrons have been added to the glass rod.

For the second question, we can use Coulomb's law to determine whether the pith ball and metal plate are attracted or repulsed. Coulomb's law states that the force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them where

The force between the pith ball and the metal plate is:

F = k x q1 x  q2 / r²

Pugging the value in the formula, the answer will be:  F = -0.135 N.

The negative sign indicates that the force is attractive, so the pith ball and metal plate are attracted to each other.

For the third question, the force on the negatively charged object from problem 2 is 0.135 N, in the direction towards the positively charged pith ball.

For the fourth question, the force on the positively charged object from problem 2 is also 0.135 N, in the direction towards the negatively charged metal plate.

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See text below

You rub a glass rod with a piece of fur. If the rod now has a charge of -0.6 μC, how many electrons have been added to the rod?

A suspended pith ball possessing +10 μC of charge is placed 0.02 m away from a metal 'plate possessing -6 μC of charge. Are these objects attracted or repulsed?

What is the force on the negatively charged object from problem 2?

• What is the force on the positively charged object from problem 2?

The skydiver covered a distance of approximately 94.9 meters before opening his parachute between t1 and t2, assuming no air resistance or friction.

v = final velocity = v2 = 27 m/s

u = initial velocity = v1 = 11 m/s

a = acceleration = g = 9.8 m/[tex]s^2[/tex]

s = (v² - u²) / 2a

s = (27² - 11²) / (2 x 9.8) = 94.9 meters

Resistance measures an item's potential to impede the drift of electrical present-day through it. it's far measured in ohms (Ω). Resistance is decided by way of the bodily residences of an item, along with its dimensions, material, and temperature. while electric-powered present-day flows thru a conductor, it encounters resistance that slows down its float. This resistance is as a result of the collisions among electrons and the atoms inside the conductor.

Resistance can be laid low with changes inside the bodily properties of the conductor, such as duration, cross-sectional region, or temperature. an extended or narrower conductor may have higher resistance, even as a much broader conductor could have decreased resistance. understanding resistance is critical for designing and working electrical circuits. with the aid of controlling the resistance of a circuit, engineers can make sure that the appropriate amount of current flows to electricity the devices linked to it.

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The angular momentum of the ball rotating on the end of a thin string in a circle of radius 1.45 m m at an angular speed of 11.6 rad/s r a d / s is 6.07 × 10⁻⁶ kg m²/s.

Angular momentum is the quantity of motion that describes the rotation of a body about a fixed axis. It is a vector quantity that is the cross product of the position vector and the momentum vector.

The angular momentum of a 0.205 kg k g ball rotating on the end of a thin string in a circle of radius 1.45 m m at an angular speed of 11.6 rad/s r a d / s can be calculated as follows:

L = IωL = Iω

Here, L is angular momentum,

I is the moment of inertia of the ball, and

ω is the angular velocity of the ball.

The moment of inertia of a uniform sphere can be calculated as follows:

I= (2/5)mr²I = (2/5)mr²

Here, m is the mass of the sphere, and r is the radius of the sphere.

Therefore, the moment of inertia of the ball is given by:

I = (2/5)mr²I = (2/5) × 0.205 × (0.00145)²I = 5.23 × 10⁻⁷ kg m²

Substituting this value into the expression for angular momentum:

L = IωL = 5.23 × 10⁻⁷ × 11.6L = 6.07 × 10⁻⁶ kg m²/s.

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Answer:

i will change this answer when you attach a picture with it

Explanation:

The corresponding temperature in Fahrenheit is 10° C = 50° F, 30° C = 86° F and 40° C = 104° F.

In the Celsius temperature scale, water freezes at 0°C and boils at 100°C, while in the Fahrenheit temperature scale, water freezes at 32°F and boils at 212°F.

The conversion formula for Celsius to Fahrenheit is F = 1.8 x C + 32, where;

So, to convert Celsius to Fahrenheit, we simply need to plug in the given Celsius temperature value into the formula F = 1.8 x C + 32, and then solve for F.

Let's take the first example of 10°C:

F = 1.8 x C + 32

F = 1.8 x 10 + 32

F = 18 + 32

F = 50°F

Therefore, 10°C is equivalent to 50°F in Fahrenheit.

Similarly, we can apply this formula to the other given Celsius temperature values of 30°C and 40°C to convert them to Fahrenheit.

30° C = 86° F (F = 1.8 x 30 + 32)

40° C = 104° F (F = 1.8 x 40 + 32)

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The position space wavefunction for a participle in the ground state of a harmonic oscillator potential is ψ(x) = (mω/πh[tex]{)}^{1/4}[/tex] × exp(-mωx²/2h).

The position space wavefunction for a particle in the ground state of a harmonic oscillator potential is given by:

ψ(x) = (mω/πh[tex]{)}^{1/4}[/tex] × exp(-mωx^2/2h)

where m is the mass of the particle, ω is the angular frequency of the harmonic oscillator potential, ħ is the reduced Planck constant, and x is the position of the particle.

The ground state wavefunction has a Gaussian shape and is centered around the equilibrium position of the oscillator. It is a probability amplitude function that describes the probability of finding the particle at a particular position x. The maximum probability density occurs at x = 0, which is the equilibrium position of the harmonic oscillator.

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To solve this problem, we need to resolve the forces acting on the block along the incline and perpendicular to the incline.

The force parallel to the incline and up the incline is given as F = 25 N.

The weight of the block is given by mg, where m = 5.0 kg is the mass of the block and g = 9.8 m/s^2 is the acceleration due to gravity.

The weight of the block is resolved into its components along the incline and perpendicular to the incline as follows:

F_perpendicular = mg cos θ = 5.0 kg × 9.8 m/s^2 × cos 20° ≈ 45.3 N

F_parallel = mg sin θ = 5.0 kg × 9.8 m/s^2 × sin 20° ≈ 16.7 N

Since the inclined plane is frictionless, there is no frictional force acting on the block.

The net force acting on the block along the incline is given by:

F_net = F_parallel - F = 16.7 N - 25 N = -8.3 N (since the force is acting up the incline)

Therefore, the acceleration of the block along the incline is given by:

a = F_net / m = (-8.3 N) / (5.0 kg) ≈ -1.7 m/s^2

Note that the negative sign indicates that the acceleration is in the opposite direction to the applied force, i.e., down the incline.

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The Blumlein technique should be avoided when using directional microphones due to probable phase cancellation problems caused by its bidirectional microphones.

Sound system amplifier methods are utilized to catch sound system sound in recording and broadcasting applications. While utilizing directional mouthpieces, like cardioid or supercardioid receivers, stage scratch-off issues can happen because of the directionality of the amplifiers.The Blumlein strategy, which utilizes two bidirectional receivers organized in an incidental pair, ought to be stayed away from while utilizing directional mouthpieces. This is on the grounds that the bidirectional mouthpieces utilized in the Blumlein strategy have invalid focuses at 90 degrees to the front and back of the receiver, which can prompt stage scratch-off when utilized related to directional amplifiers.All things being equal, sound system receiver strategies that utilization omnidirectional mouthpieces, like the separated pair method or the A-B strategy, are more reasonable for use with directional amplifiers.

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The white light strikes a black object, the light is completely absorbed and none of it is transmitted or reflected.

Light is a type of electromagnetic radiation that travels in straight lines. It is comprised of energy packets that can move through a vacuum. As light passes through a substance or hits an object, it can be affected in various ways.

The interaction between light and an object can be quantified using specific principles of optics.

Light reflection is a phenomenon in which light hits an object and bounces back from its surface.

When light hits a smooth surface like a mirror or water, it bounces back in a regular and predictable way. This type of reflection is called specular reflection.

When light strikes a rough surface, it is reflected in many different directions. This type of reflection is called diffuse reflection.

Therefore, when white light strikes an object and is completely absorbed, with none of it transmitted or reflected, the object can be a black object.

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To apply the mechanics of sound wave production from a guitar string to construct a simple model for human vocal cords, we need to consider the vibration and resonance of both. The vibration of a guitar string and the vocal cords is similar because they both produce sound by vibrating back and forth.

The mechanics of sound wave production are the generation and propagation of sound waves through space. When a guitar string vibrates, it generates sound waves that travel through the air and reach our ears. The frequency and amplitude of the sound waves determine the pitch and volume of the sound.

Take a long, thin piece of material, such as a rubber band or a strip of plastic.2. Stretch it taut between two points, such as two pencils or two pegs.3. Pluck the string with your finger and observe the vibration.4. Vary the tension and length of the string to produce different pitches.

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In an alternating current circuit that contains a resistor, an inductor, and a capacitor with 120V, you can find the current by using Ohm's Law.

Ohm's Law states that the current is equal to the voltage divided by the resistance.

To calculate the resistance in an alternating current circuit, you must take into account the resistor, inductor, and capacitor.

For example, if the resistor has a resistance of 10 ohms, the inductor has a resistance of 5 ohms, and the capacitor has a resistance of 20 ohms, then the total resistance would be 35 ohms.

Therefore, the current in the circuit would be 120V/35 ohms = 3.43A.

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On a frictionless table, there is no loss of energy because it is conserved before and after the collision, thus it is equal to option D: mv²/2.

A collision is considered elastic if it does not result in a net loss of kinetic energy for the system. Momentum and kinetic energy are both conserved in elastic collisions. The two bodies given in the question have same masses which stick together after the collision. This means that the body moving with velocity v initially, now comes to rest.

As the kinetic energy before and after the collision is conserved,

Total energy of the system:

1/2 mv² + 0 = 1/2mv²

Thus, the there is no loss of energy as heat, as the total energy of the system remains conserved and is equivalent to option D: mv²/2.

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To determine the appropriate wire size (AWG) for a 70A breaker supplying a 65A non-continuous load, you would need to consider the ampacity of the wire, the length of the run, and the type of conductor insulation.

Based on the NEC (National Electric Code) guidelines, for a 70A breaker supplying a 65A non-continuous load, the minimum recommended wire size would be 6 AWG copper or 4 AWG aluminum.

It's important to note that this recommendation assumes a maximum length of 100 feet and THHN/THWN insulation. If you're using a different insulation type, you'll need to adjust the wire size accordingly.

Additionally, if the run is longer than 100 feet or if there are other factors that could affect the current-carrying capacity of the wire, you should consult a qualified electrician or refer to the NEC for more detailed guidance.

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The final answer length of the side changes from 2 cm to 3 cm, the volume increases by a factor of 3.375 (27 divided by 8). And when the length of the side changes from 3 cm to 4 cm, the volume increases by a factor of 2.37 (64 divided by 27).

The volume of a cube changes when you increase the length of the side from 1 cm to 2 cm, to 3 cm, and then to 4 cm. A cube is a three-dimensional shape with six identical square faces. When all the faces of a cube are equal in length, it is referred to as a square cube.

Each edge of a cube is the same length, so we can figure out the volume of a cube by multiplying the length, width, and height together.

The volume of a cube is given by V = s^3, where s is the length of one edge of the cube. The volume changes as the length of the side changes. Here's how it changes as the side length increases from 1 cm to 4 cm:

When s = 1 cm, V = 1^3 = 1 cm³
When s = 2 cm, V = 2^3 = 8 cm³
When s = 3 cm, V = 3^3 = 27 cm³
When s = 4 cm, V = 4^3 = 64 cm³

We can see that as the length of the side of the cube increases, the volume increases rapidly. The volume of the cube grows much faster than the length of one of its sides. For example, when the length of the side changes from 1 cm to 2 cm, the volume increases by a factor of 8.

When the length of the side changes from 2 cm to 3 cm, the volume increases by a factor of 3.375 (27 divided by 8). And when the length of the side changes from 3 cm to 4 cm, the volume increases by a factor of 2.37 (64 divided by 27).

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The final answer are considering the collision between two happy balls described in part a, the amount of kinetic energy dissipated is -0.15 J.

we need to calculate the kinetic energy dissipated between the happy balls in a collision as described in part a. The question is asking us to use the following terms in our answer: "now, consider the collision between two happy balls described in part

a. how much of the balls' kinetic energy is dissipated? "So, using the given formula of kinetic energy :K = (1/2)mv²Where,K = Kinetic energy of an object m = Mass of an object v = Velocity of an object

Now, we'll begin solving the problem. According to the problem, two balls with a mass of 0.35 kg each, having a velocity of 2.5 m/s and 1.2 m/s, collide in an inelastic collision with each other. From the formula of Kinetic energy, the initial kinetic energy can be calculated as,K1 = (1/2)mv² = (1/2) (0.35 kg) (2.5 m/s)² = 1.09 J

Similarly, for the second ball, the initial kinetic energy can be calculated as,K2 = (1/2)mv² = (1/2) (0.35 kg) (1.2 m/s)² = 0.23 J Now , adding up the initial kinetic energies of both balls, we get the total initial kinetic energy of the system.

That is,K1 + K2 = 1.09 J + 0.23 J = 1.32 J

Therefore, the total initial kinetic energy of the system is 1.32 J. Now, let's calculate the final kinetic energy of the system. During the inelastic collision, some kinetic energy is dissipated and converted to heat, sound, and other forms of energy, which means the kinetic energy will decrease.

Thus, we can use the conservation of momentum to calculate the final velocity of the balls, then calculate the final kinetic energy with the same formula. Now, applying the conservation of momentum (as in Part a), we get,0.35 kg × 2.5 m/s + 0.35 kg × 1.2 m/s = (0.35 kg + 0.35 kg) × v_ v = 1.85 m/s

Now, we can calculate the final kinetic energy of the system as, K_final = (1/2)mv² = (1/2) (0.7 kg) (1.85 m/s)² = 1.47 J Therefore, the final kinetic energy of the system is 1.47 J. Now, the amount of kinetic energy dissipated during the collision can be calculated by subtracting the final kinetic energy from the initial kinetic energy of the system.

K_dissipated = K_initial - K_final= 1.32 J - 1.47 J= -0.15 J

Thus, the amount of kinetic energy dissipated during the collision is -0.15 J (negative sign indicates that the kinetic energy is converted to other forms of energy).

Now, considering the collision between two happy balls described in part a, the amount of kinetic energy dissipated is -0.15 J.

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Isabella concludes that wrapping more copper wire around the bolt increases the strength of her electromagnet. The copper wire, when connected to a battery, creates a magnetic field around the iron bolt

Magnetic is a material or object that produces a magnetic field. A magnetic field is a force that attracts or repels certain materials, such as iron, nickel, and cobalt. Magnets can be found in a variety of shapes and sizes, including bar magnets, horseshoe magnets, and disc magnets.

Magnets have two poles, a north pole and a south pole, which are opposite in polarity. Like poles repel each other, while opposite poles attract. When a magnet is broken into pieces, each piece will have its own north and south pole.

Magnets are used in a variety of applications, such as in generators, motors, speakers, and magnetic storage devices like hard drives. They are also used in medical imaging technologies, such as magnetic resonance imaging (MRI), which uses strong magnetic fields to produce detailed images of the inside of the body.

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In a head-on collision between a compact car and a large truck, the compact car will generally experience more force due to its smaller mass.

A head-on collision, also known as a frontal collision or a lane departure crash, is a form of collision in which two vehicles traveling in opposite directions collide head-on. A compact car is a small passenger car that usually has a shorter length and wheelbase than a mid-size car. A large truck is a commercial motor vehicle with a gross vehicle weight of more than 10,000 pounds. They may be box trucks, tractor-trailers, dump trucks, or other commercial vehicles.

During a head-on collision between a compact car and a large truck, the large truck experiences less damage than the compact car.  This is because the compact car experiences a greater force of impact than the large truck.

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Answer:Evaporation

Explanation:

The scale will read 8,996 N during the acceleration.

The force applied to the woman by the scale is the sum of her weight and the weight of the elevator and scale (66.0 kg + 784 kg = 850.0 kg). This can be calculated using the equation

Force = Mass x Acceleration (F = ma).

The acceleration is given by the force applied (9030 N) divided by the total mass (850.0 kg), which gives a result of 10.6 m/s2.

We then multiply this acceleration by the mass of the woman (66.0 kg) to get the force applied to the woman by the scale, which is 696 N.

We then add this to the weight of the elevator and scale (784 kg) to get the total force that the scale reads, which is 8,996 N.

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When a negatively charged point particle is placed initially at rest in a uniform electric field, it will move towards the direction of the electric field.

An electric field is a vector field that represents the force exerted by charged particles over each other. It is generated by charges, and it affects other charged particles that are in the space around it. The direction of the electric field is given by the direction of the force that is experienced by a small positive test charge placed in that field. If the force on the test charge is towards the positive charge that creates the field, the electric field will point towards the positive charge. If the force on the test charge is towards the negative charge that creates the field, the electric field will point towards the negative charge.

When a negatively charged particle is placed in the electric field, it experiences a force in the direction opposite to the direction of the electric field,  this is because the negatively charged particle is attracted towards the positively charged particles that generate the field, and so it moves towards them. Therefore, the negatively charged particle moves towards the direction of the electric field. When a positively charged particle is placed in the electric field, it experiences a force in the direction of the electric field. This is because the positively charged particle is attracted towards the negatively charged particles that generate the field, and so it moves towards them. Therefore, the positively charged particle moves towards the direction opposite to the direction of the electric field.

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