as shown in the figure, a 10-kg block on a perfectly smooth horizontal table is connected by a horizontal string to a 63-kg block that is hanging over the edge of the table. what is the magnitude of the acceleration of the 10-kg block when the other block is gently released?

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The velocity for the entire trip is 0.4 m/s as It takes her 500 seconds to make the round trip and 60 kg • m/s2 = (45 kg • v) + (20 kg • 3 m/s).

Path 1 = 400 m В B. A Path 2 = 200 m Path 3 = 300 m. Thus, option C is correct.

A particle's settling velocity known as the rate at which is travels through a still fluid. The specific gravity of the particles, their size, and their shape all have an impact on settling velocity.

A particle in still air will gravitationally settle and reach its terminal velocity fairly quickly. A particle's terminal velocity in a still fluid is referred to as the settling velocity (also known as the "sedimentation velocity").

Understanding variations in the hydraulic regime and interactions between sediment and fluid in the surf zone depends heavily on the particle settling velocity at the foreshore region. In contrast to sedimentation, which is the end product of the settling process, settling is the movement of suspended particles through the liquid.

Therefore, Thus, option C is correct.

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Answer:

Black hole accretion disk emit in the X-rays but neutron star disks are cooler

Hope this Helps

The conservation of the momentum allows to find the velocity of the second body after the elastic collision is:

           [tex]v_f = \frac{2u_o}{1- \frac{m_2}{m_1} }[/tex]  

the momentum is defined by the product of the mass and the velocity of the body.

        p = mv

The bold letters indicate vectors, p is the moment, m the mass and v the velocity of the body.

If the system is isolated, the forces during the collision are internal and the it  is conserved. Let's find the momentum is two instants.

Initial instant. Before crash.

      p₀ = m₁ u₀ + 0

Final moment. After crash.

      [tex]p_f = m_1 u_f + m_2 v_f[/tex]  

The momentum is preserved.

      p₀ = [tex]p_f[/tex]  

      [tex]m_1 u_o = m_1 u_f + m_2 v_f[/tex]  

Since the collision is elastic, the kinetic energy is conserved.

      K₀ = [tex]K_f[/tex]

      ½ m₁ u₀² = ½ m₁ [tex]u_f^2[/tex]  + ½ m₂  [tex]v_f^2[/tex]  

Let's write our system of equations.

       [tex]m_1 u_o = m_1 u_f + m_2 v_f \\m_1 u_o^2 = m_1 u_f^2 + m_2 v_f^2[/tex]

Let's solve

       [tex]u_f = u_o - \frac{m_2}{m_2} \ v_f \\u_f^2 = u_o^2 - \frac{m_2}{m_1} \ v_f^2[/tex]

       [tex]( u_o - \frac{m_2}{m_1} v_f)^2 = u_o - \frac{m_2}{m_1} \ v_f^2 \\u_o^2 - 2 \frac{m_2}{m_1} \ u_o v_f + (\frac{m_2}{m_1} )^2 v_f^2 = u_o^2 - \frac{m_2 }{m_1} \ v_f^2[/tex]  

        [tex]2 \frac{m_2}{m_1} \ u_o = \frac{m_2}{m_1} v_f \ ( 1 - \frac{m_2}{m_1}) \\v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]

In conclusion, using the conservation of momentum, we can find the velocity of the second body after the elastic collision is:

           [tex]v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]  

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Formulas change from F to degree C : C = (F – 32) / 1.8

so we have (176-32) /1.8= 80 oC

Formulas change from F to degree K : K = 5 / 9 x (F – 32) + 273.15

so we have 5/9 x (176-32) + 273.15 = 353 oK

ok done. Thank to me :>

Answer:

speed and acceleration

Explanation:

speed is a scalar quantity

acceleration is a vector quantity

Answer:

Visible spectrum is considered to be:

4000-7000 Angstroms

400 -700 Microns

Ultraviolet is   <400 microns    causes sunburn, cellular damage

Infrared >700 microns      -heating, heat lamps, etc

Answer:

Russia

Explanation:

my answer was deleted for no reason. apparently i was violating community guidelines when i wasnt. anyways, the answer is russia...

Answer:

10

Explanation:

if you put 10 your right

This was kinda hard thinking it might be that the new force is going to 4 times bigger than the original one.

Answer:

11.1

Explanation:

2 hours 15 mins = 2 1/4 hours

2 1/4 hours = 25 miles

1 hour = 25 ÷ 2 1/4 = 25 ÷ 9/4 = 25 x 4/9 = 11.1 miles

The two conditions are:

1) Application of-force on the body.

2) Displacement of the body in the direction of force.

Hope this helps!

Answer:

C. Mechanical Energy

Explanation:

The total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy.

Hi there!

A)

The angle that will produce the same range is the compliment of 35°.

Thus, kicking the ball at 55° will result in the same range.

We can prove this by using the derived range equation:

[tex]R = \frac{v^2sin2\theta}{g}[/tex]

An angle of 35° yields:

[tex]R = \frac{v^2sin(2*35)}{g} = .939R[/tex]

An angle of 55° yields:

[tex]R = \frac{v^2sin(2*55)}{g} = .939R[/tex]

Both are the same, thus indicating that 55° produces the same range.

B)

The angle of 55° will produce the higher ball because the VERTICAL component of the ball's velocity is greater compared to kicking the ball at 35° degree.

sin(55) > sin(35)

C)

The angle of 55° will result in the ball being in the air the longest because when a ball is in the air (assuming no air resistance), the ball experiences an acceleration due to gravity of -9.8 m/s², causing the vertical velocity to decrease until it eventually reaches 0 m/s at the top of its path. A greater initial vertical velocity means that it will take longer for the ball to fall.

We can prove this using:

vf = vi + at

0 = vy - 9.8t

vy/9.8 = t

Greater vy (vertical component of velocity) ⇒ greater time taken.

D)

The angle that would result in the furthest range is 45°.

We can prove this using calculus. Recall the above range equation:

[tex]R = \frac{v^2sin2\theta}{g}[/tex]

We can take the derivative and use the first-derivative test to find its critical point:

[tex]\frac{dR}{d\theta} = \frac{v^22cos2\theta}{g} = 0[/tex]

Evaluate:

[tex]v^22cos2\theta = 0 \\\\cos2\theta = 0 \\\\2\theta = 90^o\\\\\boxed{\theta = 45^o}[/tex]

A. The angle that will produce the same range as a 35° kick is 53°.

B. The angle that produces the highest ball is 45°.

C. The angle that produces the ball that is in the air the longest is 45°.

D. There is no single angle that will produce the furthest range for all initial velocities and accelerations due to gravity.

A. The range of a projectile is the horizontal distance it travels before it hits the ground. The range of a projectile is determined by the initial velocity, the angle of projection, and the acceleration due to gravity.

For a given initial velocity, the range of a projectile is maximized when the angle of projection is 45°. However, if the ground is not level, the range of a projectile can be maximized at other angles.

In the case of a soccer ball kicked at an angle of 35°, the range will be maximized at an angle of 53°. This is because the range of a projectile is maximized when the vertical component of the initial velocity is equal to the horizontal component of the initial velocity.

The angle of 53° is the angle that produces a vertical component of the initial velocity that is equal to the horizontal component of the initial velocity when the ball is kicked at an angle of 35°.

Therefore, the angle that will produce the same range as a 35° kick is 53°.

B. The angle that produces the highest ball is 45°.

C. The angle that produces the ball that is in the air the longest is 45°.

D. The angle that produces the furthest range depends on the initial velocity and the acceleration due to gravity. There is no single angle that will produce the furthest range for all initial velocities and accelerations due to gravity.

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Answer:

[tex]\boxed {\boxed {\sf 13.3 \ m/s^2}}[/tex]

Explanation:

Acceleration is the rate of change of velocity with respect to time. It is the change in velocity over the change in time, and it is calculated using the following formula.

[tex]a= \frac{ v_f-v_i}{t}[/tex]

The car starts at a speed of 10 meters per second, then it accelerates to a speed of 50 meters per second. It achieves this acceleration in 3 seconds.

Substitute the values into the formula.

[tex]a= \frac{50 \ m/s - 10 \ m/s}{3 \ s}[/tex]

Solve the numerator.

[tex]a= \frac{40 \ m/s}{3 \ s}[/tex]

Divide.

[tex]a= 13.3333333 \ m/s/s[/tex]

[tex]a \approx 13.3 \ m/s^2[/tex]

The car's acceleration is approximately 13.3 meters per second squared.

Answer:

Kinetic Energy

Explanation:

Its on the internet

Answer: about 29.4 Earth years

Orbit and Rotation

One day on Saturn takes only 10.7 hours (the time it takes for Saturn to rotate or spin around once), and Saturn makes a complete orbit around the Sun (a year in Saturnian time) in about 29.4 Earth years (10,756 Earth days).

Answer:

the answer is A

Explanation:

Answer:

because you are not only mixing the colors u are also mix the colors in side the colors for example if u take pink red and white and mix it with green blue and yellow it will make it darling because if the inside colors

The unit for momentum is equal to Kgm/s.

Given the following data:

To determine the unit for momentum:

In Science, momentum can be defined as a multiplication of the mass of an object and its velocity.

Mathematically, momentum is giving by this formula;

[tex]Momentum = mass \times velocity[/tex]

Substituting the given parameters into the formula, we have;

[tex]Momentum = kg \times m/s\\\\[/tex]

Momentum = Kgm/s.

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Hi there!

We know that:

Momentum (p) = mass (kg) × velocity (m/s)

Or:

P = mv

We can rearrange the equation to solve for speed:

P/m = v

Plug in the given values:

(3.75 × 10⁸)/75000 = 5000 m/s

Answer:

198m

Explanation:

Distance = speed x time

. d = 330m/s x 1.2s = 396m

This is the distance travelled by the sound from the person to the object and then back to the person. To get the distance from the person to the object, we would have to divide by 2.

. distance = 396 / 2 = 198m

Answer:

C

for sure

go for it

..............

The amount of work done to stop the car is equal to 322,099.85 Joules.

Given the following data:

Conversion:

Velocity = 95 km/h = [tex]\frac{95 \times 1000}{60 \times 60} = 26.39 \;m/s^2[/tex]

To determine the amount of work done to stop the car, we would apply the work-energy theorem:

Note: The amount of work done must balance the kinetic energy possessed by the car due to its motion.

From the work-energy theorem, we have:

[tex]Work\done = \Delta K.E\\\\Work\done = \frac{1}{2} MV^2[/tex]

Substituting the given parameters into the formula, we have;

[tex]Work\;done = \frac{1}{2} \times 925 \times (26.39)^2\\\\Work\;done =462.5 \times 696.4321[/tex]

Work done = 322,099.85 Joules

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If we take West to be the negative direction, then the initial velocity is -15 m/s and the acceleration (which points East) is +7.0 m/s².

After t = 4.0 s, the helicopter's velocity is

-15 m/s + (7.0 m/s²) (4.0 s) = +13 m/s

or 13 m/s [E].

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The question is fishing for "balanced force".

But the description in the question is terrible.

Explanation:

Sound is repeated near hills due to reverberation. The sound effect is prolonged is an empty room because , in a furnished room, reverberation occurs less than in a room with no furniture.

Answer:

sound that occurs in nature, such as those of animal, trees, people, the wind, the rain, etc. are the natural sounds. it is heard near the hill because of the echo and the reverberation of the sound