An object is dropped from a vertical height of 1.89 m above the balcony level. What is the object’s speed when it is 2.20 m below the balcony level if 10.0% energy is lost due to the air resistance? Does it matter when to apply 10% loss before V calculations or after? [8.49m/s] [yes it does, 0.9Energy result in √0.9Velocity]

Answers

Answer 1

a.

The object's speed at 2.20 m below balcony level is 8.74 m/s

Let the balcony level be 0 m and the height above the balcony level be positive and height below the balcony level negative.

Using the principle of conservation of energy, the total energy at a vertical height of 1.89 m above the balcony level equals the total mechanical energy when the object is 2.20 m below the balcony level and

So, E = E'

U + K + f = U' + K' + f'

where U = initial potential energy at 1.89 m = mgh, K = initial kinetic energy at 1.89 m = 0 J(since it is released from rest), f = energy loss at 1.89 m = 0 J, U' = final potential energy at 2.20 m below balcony level = mgh', K = final kinetic energy at 2.20 m = 1/2mv², f' = energy loss at 1.89 m = 10%U = 0.10mgh(since 10% of the initial energy is lost).

So,

U + K + f = U' + K' + f'

mgh + 0 + 0 = mgh' + 1/2mv² + 0.10mgh

mgh = mgh' + 1/2mv² + 0.10mgh

Dividing through by m, we have

gh = gh' + 1/2v² + 0.10gh

So, gh -  0.10gh = gh' + 1/2v²

0.90gh = gh' + 1/2v²

1/2v² = 0.90gh - gh'

1/2v² = g(0.90h - h')

v² = 2g(0.90h - h')

Taking square-root of both sides, we have

v = √[2g(0.90h - h')]

where v = velocity of object at 2.20 m below balcony level, h = height above the balcony level = 1.89 m, h' = height below the balcony level = -2.20 m and  g = acceleration due to gravity = 9.8 m/s²

Substituting the values of the variables into the equation, we have

v = √[2g(0.90h - h')]

v = √[2 × 9.8 m/s²{0.90 × 1.89 m - (-2.20 m)}]

v = √[2 × 9.8 m/s²(1.701 m + 2.20 m)]

v = √[2 × 9.8 m/s²(3.901 m)]

v = √[76.4596 m²/s²]

v = 8.74 m/s

So, the object's speed at 2.20 m below balcony level is 8.74 m/s

b.

Yes it does matter when we apply 10% loss before V calculations

We need to apply the 10 % loss before V calculations because this would give us a proper value for V since the energy is lost before V is obtained.

So, yes it does matter when we apply 10% loss before V calculations

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Answer:

Explanation:

Step 1 of 4

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True

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what is the acceleration of the cart at t=8 seconds?
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Answers

ANSWER:

What is the acceleration of the cart at t=8 seconds?

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Hence the answer us letter a) 0 m/s^2.

That's all I know, Hope it help :)

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Answers

Answer:

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Answer:

Explanation:

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Explanation:

In this chapter, we will study the important concepts of kinetic energy and the

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Series hybrids feature a separate generator which is connected to the engine. In a parallel hybrid, the electric motor acts as a generator. In a series hybrid, the gasoline engine is not coupled directly to the wheels, while it is in a parallel hybrid.
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Answers

Answer:

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Answers

The units of the constant of proportionality between pressure and volume in alphabetical order are

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2. Fahrenheit (°F)

3. Kelvin (K)

The units for R, that is, the ideal gas constant are

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2. L atm K⁻¹ mol⁻¹

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The units for R, that is, the ideal gas constant are

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2. L atm K⁻¹ mol⁻¹

Hence,

The units of the constant of proportionality between pressure and volume in alphabetical order are

1. Celsius (°C)

2. Fahrenheit (°F)

3. Kelvin (K)

The units for R, that is, the ideal gas constant are

1. J K⁻¹ mol⁻¹

2. L atm K⁻¹ mol⁻¹

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Answers

Answer:

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Swim swim swim faster ‍♂️

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Answers

Answer:

This happens when the mass of one of the objects is very large and does not move.

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A vessel with an unknown volume is filled with 10 kg of water at 90oC. Inspection of the vessel at equilibrium shows that 8 kg of the wateris in the liquid state. What is the pressure in the vessel, and what is the volume of the vessel

Answers

In this case, it is possible to solve this problem by using the widely-known steam tables which show that at 90 °C, the pressure that produces a vapor-liquid mixture at equilibrium is about 70.183 kPa (Cengel, Thermodynamics 5th edition).

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Now, at this temperature and pressure, the volume of a saturated vapor is  2.3593 m³/kg whereas that of the saturated liquid is 0.001036 m³/kg and therefore, the volume of the mixture is:

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Answer:

Quiet, is the adjective in this sentence

Explanation:

She had a quiet voice. This statement uses the adjective quiet. Her voice can be characterized as quiet.

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A word used to characterize a person, place, or thing is called an adjective. Adjectives are used to modify nouns or pronouns.

There are many adjectives that describe quiet, including muted, peaceful, reticent, silent, soft, gentle, mild, placid, private, secluded, sedate, serene, timid, smooth, calm, tranquil, modest, restrained, sober, and subdued.

Hence, the significance of the adjectives is aforementioned.

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Answer: Are these free point?

Explanation:

Find the self-inductance of a 1700-turn solenoid 55 cm long and 4.0 cm in diameter. Express your answer with the appropriate units.

Answers

The self-inductance of the solenoid is 8.25 mH.

The given parameters;

number of turns, N = 1700 turnlength of the solenoid, l = 55 cm = 0.55 mdiameter of solenoid, d = 4 cmradius of the solenoid, r = 2 cm = 0.02 m

The area of the solenoid is calculated as follows;

[tex]A = \pi r^2\\\\A = \pi \times (0.02)^2\\\\A = 0.00125 \ m^2[/tex]

The self-inductance of the solenoid is calculated as follows;

[tex]L = \frac{\mu_o N^2 A }{l} \\\\L = \frac{(4\pi \times 10^{-7}) \times 1700^2 \times 0.00125}{0.55} \\\\L = 0.00825 \ H\\\\L = 8.25\ mH[/tex]

Thus, the self-inductance of the solenoid is 8.25 mH.

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Id say the second answer (high efficiency, produce more heat) as the more light, the more waste (heat) ,but I would still check just to be sure because I may be wrong.
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