Chemistry College

16. How many molecules are present in 3.0 X 102 grams of calcium
carbonate? [Calcium - 40 g/m;Carbon - 12g/m. Oxygen - 16 g/m]
A) 6.02 X 1023
B 81.1 X 1023.
C) 1.81 X 1024

Answers

Answer 1

To solve this problem, we need to use the concept of Avogadro's number and molecular weight.

The molecular weight of calcium carbonate (CaCO3) can be calculated as follows:

Calcium (Ca) atomic weight = 40 g/molCarbon (C) atomic weight = 12 g/molOxygen (O) atomic weight = 16 g/molMolecular weight of CaCO3 = (1 x 40) + (1 x 12) + (3 x 16) = 100 g/mol

Now, we can calculate the number of molecules in 3.0 x 10^2 grams of CaCO3 as follows:

Convert the mass of CaCO3 to moles using the formula:

moles = mass / molecular weight

moles = 3.0 x 10^2 g / 100 g/mol

moles = 3.0 x 10^0 mol

Use Avogadro's number to calculate the number of molecules:

number of molecules = moles x Avogadro's number

number of molecules = 3.0 x 10^0 mol x 6.02 x 10^23 molecules/mol

number of molecules = 1.806 x 10^24

Therefore, the answer is C) 1.81 x 10^24.

Related Questions

when you prepare a kettle of stew over a camp fire the stew is warmed in a variety of ways example the combination

Answers

A bonfire to heat a stew kettle. The stew is warmed using a variety of techniques, such as the combo, when I am close to a fire, you are not mainly receiving heat from hot air.

In what way does the heat get transferred by sitting next to the fire?

The method by which heat is transmitted to a person sitting near a fire is convection. Convection happens as a method of transfer when heat is transferred from one thing to another body when both bodies are made of different materials.

As we feel the heat of a campfire, convection currents are heating your palm. Different heat sources, like radiation, cause heat to manifest. However, a powerful convection current rises in your direction as you elevate your palm over a fire.

When I sit beside a campfire, how does its hot air heat me?

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When quartz undergoes metamorphism (exposure to extreme heat and pressure), what kind of metamorphic rock can it become?

Answers

it would turn into quartzite

A 1.000-g sample of iron metal reacted with sulfite powder to give 1.574 g of product. Calculate the empirical formula of iron sulfide.

Answers

The empirical formula of iron sulfide is FeS. The empirical formula represents the simplest whole number ratio of atoms in the compound, but it may not represent the actual molecular formula.

What is Empirical Formula?

The empirical formula of a chemical compound is the simplest whole number ratio of atoms of each element present in the compound. It can be determined from the mass or percentage composition of the elements in the compound.

We can use the given mass of iron and the mass of the product formed to determine the amount of sulfur that reacted with the iron.

First, we need to determine the mass of sulfur in the product:

mass of sulfur = mass of product - mass of iron

mass of sulfur = 1.574 g - 1.000 g

mass of sulfur = 0.574 g

Next, we can use the mass of iron and sulfur to calculate the number of moles of each element:

moles of iron = mass of iron / molar mass of iron

moles of iron = 1.000 g / 55.85 g/mol

moles of iron = 0.0179 mol

moles of sulfur = mass of sulfur / molar mass of sulfur

moles of sulfur = 0.574 g / 32.06 g/mol

moles of sulfur = 0.0179 mol

The mole ratio of iron to sulfur in the compound can be determined by dividing each value by the smaller of the two:

mole ratio of iron to sulfur = moles of iron / moles of sulfur

mole ratio of iron to sulfur = 0.0179 mol / 0.0179 mol

mole ratio of iron to sulfur = 1:1

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Base is added to 200. mL of a 2.0 M solution acid solution. If 400 mL of base is added to titrate the acid solution. What is the concentration of the base?

Answers

Answer:

To solve this problem, we need to use the concept of stoichiometry and the equation for neutralization reactions. The balanced equation for the neutralization of an acid and a base is: acid + base → salt + water In this case, we know that 200 mL of a 2.0 M acid solution is titrated with 400 mL of a base solution. Let's call the concentration of the base solution "x". To find the concentration of the base solution, we can use the following equation: moles of acid = moles of base The number of moles of acid can be calculated as follows: moles of acid = volume of acid × concentration of acid moles of acid = 0.2 L × 2.0 mol/L moles of acid = 0.4 mol Since the acid and base react in a 1

A sample of gas has an initial pressure of 740 mmHg and an initial volume of 32.0 L. If the volume is changed to 21.8 L, what is the new pressure? Assume temperature and amount remain constant

Answers

Answer:

1086.2 mmHg

Explanation:

P1×V1=P2×V2

740mmHg×32.0L=P2×21.8L

23680L mmHg= P2×21.8L

divide both sides by 21.8L

1086.2mmHg=P2

The term used to describe the non-living parts of an eco system

Answers

Answer:

Abiotic Factor

Explanation:

Is a non-living part of an ecosystem that shapes its enviroment.

How is an ellipse described numerically?

Answers

An ellipse is described numerically by its mathematical equation, which includes the center, major and minor axes, and values of a and b. The foci of ellipse can also be calculated from its equation.

How is an ellipse described numerically?

An ellipse is a geometric shape that is defined by two points called foci and a constant sum of distances from any point on the ellipse to the two foci. This constant sum is called the major axis or the length of the ellipse, while the distance between the center of ellipse and the foci is called the minor axis or width of the ellipse.

To describe an ellipse numerically, we use its mathematical equation, which is in the form of: ((x-h)² / a²) + ((y-k)² / b²) = 1

(h, k) is center of ellipse

a is length of major axis divided by 2; b is length of minor axis divided by 2

The values of a and b determine the shape of ellipse. If a = b, the ellipse is a circle. If a > b, ellipse is stretched horizontally and is called an oblong ellipse. If a < b, ellipse is stretched vertically and is called a flat ellipse.

Two foci of ellipse can also be calculated using: c = √(a² - b²)

c is distance from the center of the ellipse to either of the foci.

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What is the balanced equation of KOH + HCl -> KCl + H2O

Answers

I am not sure if this will help you but I tried.

Explanation,

This is already a balanced equation because there are same number of atoms for the same type of elements on both sides of the equation.

A 1.0 L of a 6.0 M solution of HCl acid is titrated with a 0.2 M basic solution. How much base is needed to reach its titration endpoint?

(I only have four more questions to ask lol)

Answers

Answer:

No worries, happy to help! To find out how much base is needed to reach the titration endpoint, we need to use the balanced chemical equation for the reaction between HCl and the basic solution, and the stoichiometry of the reaction. The balanced chemical equation is: HCl + NaOH → NaCl + H2O From the equation, we can see that 1 mole of HCl reacts with 1 mole of NaOH. We also know that the initial volume of HCl solution is 1.0 L, and the initial concentration is 6.0 M. This means we have: moles of HCl = volume x concentration = 1.0 L x 6.0 mol/L = 6.0 mol To reach the titration endpoint, we need to add enough NaOH solution to completely neutralize all

How can a good or service affect culture?

Answers

Answer:

Explanation:

establish a direct relationship between organizational culture and effectiveness

O₂(g) + 2 H₂(g) →2 H₂O
The rate law for this reaction is second order in H₂ and first order in O₂. Write the rate
law.
If the rate constant for this reaction at 1000 K is 6.0 x 104 M²s¹, what is the reaction
rate when [0₂] = 0.055 M and [H₂] = 0.015 M?

Answers

Answer:

9.94 x 10^-6 M/s

Explanation:

The rate law for the given reaction is:

Rate = k[O₂][H₂]²

where k is the rate constant, [O₂] is the concentration of O₂, and [H₂] is the concentration of H₂.

Using the given values, we can substitute them into the rate law and solve for the reaction rate:

Rate = (6.0 x 10^4 M²s^-1) x (0.055 M) x (0.015 M)²

Rate = 9.94 x 10^-6 M/s

Therefore, the reaction rate when [O₂] = 0.055 M and [H₂] = 0.015 M is 9.94 x 10^-6 M/s.

Suppose that the microwave radiation has a wavelength of 12.4 cm. How many photons are required to heat 205 mL of coffee from 25.0 ∘C to 62.0 ∘C ? Assume that the coffee has the same density, 0.997 g/mL, and specific heat capacity, 4.184 J/(g⋅K), as water over this temperature range.

Answers

Answer:

To calculate the number of photons required to heat the coffee, we can follow these steps:

Calculate the mass of the coffee using its volume and density:

mass = volume x density = 205 mL x 0.997 g/mL = 204.185 g

Calculate the amount of heat required to raise the temperature of the coffee using its mass, specific heat capacity, and temperature change:

q = m x c x ΔT = 204.185 g x 4.184 J/(g⋅K) x (62.0 - 25.0) °C = 32289.6 J

Calculate the energy of each photon using the formula E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the microwave radiation:

E = (6.626 x 10^-34 J⋅s) x (3.00 x 10^8 m/s) / (0.124 m) = 5.067 x 10^-23 J

Calculate the number of photons required to deliver the amount of energy needed to heat the coffee:

number of photons = q / E = 32289.6 J / 5.067 x 10^-23 J = 6.368 x 10^25 photons

Therefore, approximately 6.368 x 10^25 photons are required to heat 205 mL of coffee from 25.0 ∘C to 62.0 ∘C using microwave radiation with a wavelength of 12.4 cm.

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